在我们有内置的setState回调支持之前，我们可以用简单的javascript方式…调用该函数并直接将新变量传递给它。

  const [counter, setCounter] = useState(0);

  const doSomething = () => {
    const newCounter = 123
    setCounter(newCounter);
    doSomethingWCounter(newCounter);
  };

  function doSomethingWCounter(newCounter) {
    console.log(newCounter); // 123
  }

你可以使用以下方法，我知道获得更新后的最新状态:

useEffect https://reactjs.org/docs/hooks-reference.html#useeffect

    const [state, setState] = useState({name: "Michael"});
    
    const handleChangeName = () => {
      setState({name: "Jack"});
    }
    
    useEffect(() => {
      console.log(state.name); //"Jack"

      //do something here
    }, [state]);

功能更新 https://reactjs.org/docs/hooks-reference.html#functional-updates 如果新的状态是用之前的状态计算出来的，你可以传递一个函数给setState。该函数将接收之前的值，并返回更新后的值。”

    const [state, setState] = useState({name: "Michael"});

    const handleChangeName = () => {
      setState({name: "Jack"})
      setState(prevState => {
        console.log(prevState.name);//"Jack"

        //do something here

        // return updated state
        return prevState;
      });
    }

useRef https://reactjs.org/docs/hooks-reference.html#useref 返回的ref对象将在组件的整个生命周期内持续存在。

    const [state, setState] = useState({name: "Michael"});

    const stateRef = useRef(state);
    stateRef.current  = state;
    const handleClick = () => {
      setState({name: "Jack"});

      setTimeout(() => {
        //it refers to old state object
        console.log(state.name);// "Michael";

        //out of syntheticEvent and after batch update
        console.log(stateRef.current.name);//"Jack"

        //do something here
      }, 0);
    }

在react synticevent处理程序中，setState是一个批量更新过程，因此每次状态更改都会等待并返回一个新状态。 setState()并不总是立即更新组件。它可以批处理或延迟更新。"， https://reactjs.org/docs/react-component.html#setstate

这里有一个有用的链接 React是否保持状态更新的顺序?

我不认为用useRef区分挂载与否是一个好方法，不是一个更好的方法来确定useState()在useEffect()中生成的值是否为初始值?

const [val, setVal] = useState(null)

useEffect(() => {
  if (val === null) return
  console.log('not mounted, val updated', val)
}, [val])

您需要使用useEffect钩子来实现这一点。

const [counter, setCounter] = useState(0);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
   console.log('Do something after counter has changed', counter);
}, [counter]);

如果你想在第一次初始渲染时忽略useEffect回调，那么相应地修改代码:

import React, { useEffect, useRef } from 'react';

const [counter, setCounter] = useState(0);
const didMount = useRef(false);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
  // Return early, if this is the first render:
  if ( !didMount.current ) {
    return didMount.current = true;
  }
  // Paste code to be executed on subsequent renders:
  console.log('Do something after counter has changed', counter);
}, [counter]);

我们可以写一个叫做useScheduleNextRenderCallback的钩子，它返回一个“schedule”函数。在我们调用setState之后，我们可以调用“schedule”函数，传递一个我们希望在下次呈现时运行的回调。

import { useCallback, useEffect, useRef } from "react";

type ScheduledCallback = () => void;
export const useScheduleNextRenderCallback = () => {
  const ref = useRef<ScheduledCallback>();

  useEffect(() => {
    if (ref.current !== undefined) {
      ref.current();
      ref.current = undefined;
    }
  });

  const schedule = useCallback((fn: ScheduledCallback) => {
    ref.current = fn;
  }, []);

  return schedule;
};

使用示例:

const App = () => {
  const scheduleNextRenderCallback = useScheduleNextRenderCallback();

  const [state, setState] = useState(0);

  const onClick = useCallback(() => {
    setState(state => state + 1);
    scheduleNextRenderCallback(() => {
      console.log("next render");
    });
  }, []);

  return <button onClick={onClick}>click me to update state</button>;
};

简化的测试用例:https://stackblitz.com/edit/react-ts-rjd9jk

我认为你需要的是useState和useCallback:

useState react doc; useCallback react doc;

示例代码

import React, { useCallback, useState } from 'react';

const Test = () => {
  const [name, setName] = useState("");
  const testCallback = useCallback(() => console.log(name), [name]);

  return (
    <button onClick={() => {
      setName("Michael")
      testCallback();
    }}>Name</button>
  )
};

export default Test;