您需要使用useEffect钩子来实现这一点。

const [counter, setCounter] = useState(0);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
   console.log('Do something after counter has changed', counter);
}, [counter]);

如果你想在第一次初始渲染时忽略useEffect回调，那么相应地修改代码:

import React, { useEffect, useRef } from 'react';

const [counter, setCounter] = useState(0);
const didMount = useRef(false);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
  // Return early, if this is the first render:
  if ( !didMount.current ) {
    return didMount.current = true;
  }
  // Paste code to be executed on subsequent renders:
  console.log('Do something after counter has changed', counter);
}, [counter]);

您需要使用useEffect钩子来实现这一点。

const [counter, setCounter] = useState(0);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
   console.log('Do something after counter has changed', counter);
}, [counter]);

如果你想在第一次初始渲染时忽略useEffect回调，那么相应地修改代码:

import React, { useEffect, useRef } from 'react';

const [counter, setCounter] = useState(0);
const didMount = useRef(false);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
  // Return early, if this is the first render:
  if ( !didMount.current ) {
    return didMount.current = true;
  }
  // Paste code to be executed on subsequent renders:
  console.log('Do something after counter has changed', counter);
}, [counter]);

简单的解决方案，只需安装

我使用-state-with-callback

import React from 'react';
import { useStateWithCallbackLazy } from "use-state-with-callback";

const initialFilters = {
  smart_filter: "",
};

const MyCallBackComp = () => {
  const [filters, setFilters] = useStateWithCallbackLazy(initialFilters);

  const filterSearchHandle = (e) => {
    setFilters(
      {
        ...filters,
        smart_filter: e,
      },
      (value) => console.log("smartFilters:>", value)
    );
  };

  return (
    <Input
      type="text"
      onChange={(e) => filterSearchHandle(e.target.value)}
      name="filter"
      placeholder="Search any thing..."
    />
  );
};

认为: 反应usestate回调

如果你想要更新之前的状态，那么你可以在hooks中这样做:

const [count, setCount] = useState(0);


setCount(previousCount => previousCount + 1);

我认为你需要的是useState和useCallback:

useState react doc; useCallback react doc;

示例代码

import React, { useCallback, useState } from 'react';

const Test = () => {
  const [name, setName] = useState("");
  const testCallback = useCallback(() => console.log(name), [name]);

  return (
    <button onClick={() => {
      setName("Michael")
      testCallback();
    }}>Name</button>
  )
};

export default Test;

我不认为用useRef区分挂载与否是一个好方法，不是一个更好的方法来确定useState()在useEffect()中生成的值是否为初始值?

const [val, setVal] = useState(null)

useEffect(() => {
  if (val === null) return
  console.log('not mounted, val updated', val)
}, [val])