您需要使用useEffect钩子来实现这一点。

const [counter, setCounter] = useState(0);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
   console.log('Do something after counter has changed', counter);
}, [counter]);

如果你想在第一次初始渲染时忽略useEffect回调，那么相应地修改代码:

import React, { useEffect, useRef } from 'react';

const [counter, setCounter] = useState(0);
const didMount = useRef(false);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
  // Return early, if this is the first render:
  if ( !didMount.current ) {
    return didMount.current = true;
  }
  // Paste code to be executed on subsequent renders:
  console.log('Do something after counter has changed', counter);
}, [counter]);

您需要使用useEffect钩子来实现这一点。

const [counter, setCounter] = useState(0);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
   console.log('Do something after counter has changed', counter);
}, [counter]);

如果你想在第一次初始渲染时忽略useEffect回调，那么相应地修改代码:

import React, { useEffect, useRef } from 'react';

const [counter, setCounter] = useState(0);
const didMount = useRef(false);

const doSomething = () => {
  setCounter(123);
}

useEffect(() => {
  // Return early, if this is the first render:
  if ( !didMount.current ) {
    return didMount.current = true;
  }
  // Paste code to be executed on subsequent renders:
  console.log('Do something after counter has changed', counter);
}, [counter]);

如果你想要更新之前的状态，那么你可以在hooks中这样做:

const [count, setCount] = useState(0);


setCount(previousCount => previousCount + 1);

你可以使用以下方法，我知道获得更新后的最新状态:

useEffect https://reactjs.org/docs/hooks-reference.html#useeffect

    const [state, setState] = useState({name: "Michael"});
    
    const handleChangeName = () => {
      setState({name: "Jack"});
    }
    
    useEffect(() => {
      console.log(state.name); //"Jack"

      //do something here
    }, [state]);

功能更新 https://reactjs.org/docs/hooks-reference.html#functional-updates 如果新的状态是用之前的状态计算出来的，你可以传递一个函数给setState。该函数将接收之前的值，并返回更新后的值。”

    const [state, setState] = useState({name: "Michael"});

    const handleChangeName = () => {
      setState({name: "Jack"})
      setState(prevState => {
        console.log(prevState.name);//"Jack"

        //do something here

        // return updated state
        return prevState;
      });
    }

useRef https://reactjs.org/docs/hooks-reference.html#useref 返回的ref对象将在组件的整个生命周期内持续存在。

    const [state, setState] = useState({name: "Michael"});

    const stateRef = useRef(state);
    stateRef.current  = state;
    const handleClick = () => {
      setState({name: "Jack"});

      setTimeout(() => {
        //it refers to old state object
        console.log(state.name);// "Michael";

        //out of syntheticEvent and after batch update
        console.log(stateRef.current.name);//"Jack"

        //do something here
      }, 0);
    }

在react synticevent处理程序中，setState是一个批量更新过程，因此每次状态更改都会等待并返回一个新状态。 setState()并不总是立即更新组件。它可以批处理或延迟更新。"， https://reactjs.org/docs/react-component.html#setstate

这里有一个有用的链接 React是否保持状态更新的顺序?

简单的解决方案，只需安装

我使用-state-with-callback

import React from 'react';
import { useStateWithCallbackLazy } from "use-state-with-callback";

const initialFilters = {
  smart_filter: "",
};

const MyCallBackComp = () => {
  const [filters, setFilters] = useStateWithCallbackLazy(initialFilters);

  const filterSearchHandle = (e) => {
    setFilters(
      {
        ...filters,
        smart_filter: e,
      },
      (value) => console.log("smartFilters:>", value)
    );
  };

  return (
    <Input
      type="text"
      onChange={(e) => filterSearchHandle(e.target.value)}
      name="filter"
      placeholder="Search any thing..."
    />
  );
};

认为: 反应usestate回调

传递一个函数怎么样?

const [name, setName] = useState(initialName); 
...
setName(() => {
    const nextName = "Michael";
    console.log(nextName);
    return nextName;
  });