import datetime

monthinteger = 4

month = datetime.date(1900, monthinteger, 1).strftime('%B')

print month

4月

对于任意范围的月份数字

month_integer=range(0,100)
map(lambda x: calendar.month_name[x%12+start],month_integer)

将产生正确的列表。从月份-整数列表中一月份开始的位置调整start-parameter。

日历火

从那里你可以看到那个日历。month_name[3]将返回March，数组索引为0是空字符串，因此也不需要担心零索引。

一次打印所有月份:

 import datetime

 monthint = list(range(1,13))

 for X in monthint:
     month = datetime.date(1900, X , 1).strftime('%B')
     print(month)

这就是我要做的:

from datetime import *

months = ["Unknown",
          "January",
          "Febuary",
          "March",
          "April",
          "May",
          "June",
          "July",
          "August",
          "September",
          "October",
          "November",
          "December"]

now = (datetime.now())
year = (now.year)
month = (months[now.month])
print(month)

输出:

>>> September

(这是我写这篇文章的真实日期)

我创建了自己的函数，将数字转换为对应的月份。

def month_name (number):
    if number == 1:
        return "January"
    elif number == 2:
        return "February"
    elif number == 3:
        return "March"
    elif number == 4:
        return "April"
    elif number == 5:
        return "May"
    elif number == 6:
        return "June"
    elif number == 7:
        return "July"
    elif number == 8:
        return "August"
    elif number == 9:
        return "September"
    elif number == 10:
        return "October"
    elif number == 11:
        return "November"
    elif number == 12:
        return "December"

然后我可以调用函数。例如:

print (month_name (12))

输出:

>>> December