一次打印所有月份:

 import datetime

 monthint = list(range(1,13))

 for X in monthint:
     month = datetime.date(1900, X , 1).strftime('%B')
     print(month)

一些好的答案已经使用了日历，但是设置语言环境的效果还没有被提及。

Calendar根据当前地区设置月份名称，例如在法语中:

import locale
import calendar

locale.setlocale(locale.LC_ALL, 'fr_FR')

assert calendar.month_name[1] == 'janvier'
assert calendar.month_abbr[1] == 'jan'

如果您计划在代码中使用setlocale，请确保阅读文档中的提示和警告以及扩展编写器部分。这里显示的示例不能代表它应该如何使用。特别是这两个部分:

在某些库例程中调用setlocale()通常不是一个好主意，因为它会影响整个程序[…] 扩展模块永远不应该调用setlocale()[…]

如果(像我一样)你在数据框架中有一列月份数字，我会提供这个:

df['monthName'] = df['monthNumer'].apply(lambda x: calendar.month_name[x])

import datetime

monthinteger = 4

month = datetime.date(1900, monthinteger, 1).strftime('%B')

print month

4月

import datetime
mydate = datetime.datetime.now()
mydate.strftime("%B") # 'December'
mydate.strftime("%b") # 'dec'

datetime -基本日期和时间类型- Python文档

所有strftime格式代码的列表。月份的名称，以及格式化左零填充之类的好东西。阅读整页的内容，比如“天真”参数的规则。以下是清单的简要内容:

%a  Sun, Mon, …, Sat 
%A  Sunday, Monday, …, Saturday 
%w  Weekday as number, where 0 is Sunday 
%d  Day of the month 01, 02, …, 31
%b  Jan, Feb, …, Dec
%B  January, February, …, December
%m  Month number as a zero-padded 01, 02, …, 12
%y  2 digit year zero-padded 00, 01, …, 99
%Y  4 digit Year 1970, 1988, 2001, 2013
%H  Hour (24-hour clock) zero-padded 00, 01, …, 23
%I  Hour (12-hour clock) zero-padded 01, 02, …, 12
%p  AM or PM.
%M  Minute zero-padded 00, 01, …, 59
%S  Second zero-padded 00, 01, …, 59
%f  Microsecond zero-padded 000000, 000001, …, 999999
%z  UTC offset in the form +HHMM or -HHMM   +0000, -0400, +1030
%Z  Time zone name  UTC, EST, CST
%j  Day of the year zero-padded 001, 002, …, 366
%U  Week number of the year zero padded, Days before the first Sunday are week 0
%W  Week number of the year (Monday as first day)
%c  Locale’s date and time representation. Tue Aug 16 21:30:00 1988
%x  Locale’s date representation. 08/16/1988 (en_US)
%X  Locale’s time representation. 21:30:00 
%%  literal '%' character.