我需要将秒转换为“小时:分钟:秒”。

例如:“685”转换为“00:11:25”

我怎样才能做到这一点呢?


当前回答

仅当秒数小于86400(1天)时使用函数gmdate():

$seconds = 8525;
echo gmdate('H:i:s', $seconds);
# 02:22:05

参见: gmdate()

运行Demo


将秒转换为“脚”格式无限制*:

$seconds = 8525;
$H = floor($seconds / 3600);
$i = ($seconds / 60) % 60;
$s = $seconds % 60;
echo sprintf("%02d:%02d:%02d", $H, $i, $s);
# 02:22:05

参见:floor(), sprintf(),算术运算符

运行Demo


DateTime扩展的示例使用:

$seconds = 8525;
$zero    = new DateTime("@0");
$offset  = new DateTime("@$seconds");
$diff    = $zero->diff($offset);
echo sprintf("%02d:%02d:%02d", $diff->days * 24 + $diff->h, $diff->i, $diff->s);
# 02:22:05

参见:DateTime::__construct(), DateTime::modify(), clone, sprintf ()

运行Demo


MySQL示例的结果范围被限制为TIME数据类型,从-838:59:59到838:59:59:

SELECT SEC_TO_TIME(8525);
# 02:22:05

看:SEC_TO_TIME

运行Demo


PostgreSQL的例子:

SELECT TO_CHAR('8525 second'::interval, 'HH24:MI:SS');
# 02:22:05

运行Demo

其他回答

仅当秒数小于86400(1天)时使用函数gmdate():

$seconds = 8525;
echo gmdate('H:i:s', $seconds);
# 02:22:05

参见: gmdate()

运行Demo


将秒转换为“脚”格式无限制*:

$seconds = 8525;
$H = floor($seconds / 3600);
$i = ($seconds / 60) % 60;
$s = $seconds % 60;
echo sprintf("%02d:%02d:%02d", $H, $i, $s);
# 02:22:05

参见:floor(), sprintf(),算术运算符

运行Demo


DateTime扩展的示例使用:

$seconds = 8525;
$zero    = new DateTime("@0");
$offset  = new DateTime("@$seconds");
$diff    = $zero->diff($offset);
echo sprintf("%02d:%02d:%02d", $diff->days * 24 + $diff->h, $diff->i, $diff->s);
# 02:22:05

参见:DateTime::__construct(), DateTime::modify(), clone, sprintf ()

运行Demo


MySQL示例的结果范围被限制为TIME数据类型,从-838:59:59到838:59:59:

SELECT SEC_TO_TIME(8525);
# 02:22:05

看:SEC_TO_TIME

运行Demo


PostgreSQL的例子:

SELECT TO_CHAR('8525 second'::interval, 'HH24:MI:SS');
# 02:22:05

运行Demo

写这样的函数返回一个数组

function secondsToTime($seconds) {

  // extract hours
  $hours = floor($seconds / (60 * 60));

  // extract minutes
  $divisor_for_minutes = $seconds % (60 * 60);
  $minutes = floor($divisor_for_minutes / 60);

  // extract the remaining seconds
  $divisor_for_seconds = $divisor_for_minutes % 60;
  $seconds = ceil($divisor_for_seconds);

  // return the final array
  $obj = array(
      "h" => (int) $hours,
      "m" => (int) $minutes,
      "s" => (int) $seconds,
   );

  return $obj;
}

然后像这样简单地调用函数:

secondsToTime(100);

输出是

Array ( [h] => 0 [m] => 1 [s] => 40 )

不知道为什么还没有提出这个建议,但是这里有一个使用DateInterval的变体,它的优点是秒> 86400不是问题(只是不要期望小时< 24)

noteable:该函数返回DateInterval对象,因此输出格式由调用者决定

function seconds2interval($seconds) {
    $s = intval($seconds);
    $hrs = floor($s / 3600);
    $min = floor(($s - ($hrs * 3600)) / 60);
    $sec = $s % 60;
    
    $duration = sprintf('PT%dH%dM%dS', $hrs, $min, $sec);
    $d = new DateInterval($duration);
    
    return $d;
}

$d = seconds2interval(93837.3113);  
echo $d->format('%H:%I:%s'); // 26:03:57

这个函数是有用的,你可以扩展它:

function formatSeconds($seconds) {

if(!is_integer($seconds)) {
    return FALSE;
}

$fmt = "";

$days = floor($seconds / 86400);
if($days) {
    $fmt .= $days."D ";
    $seconds %= 86400;
}

$hours = floor($seconds / 3600);
if($hours) {
    $fmt .= str_pad($hours, 2, '0', STR_PAD_LEFT).":";
    $seconds %= 3600;
}

$mins = floor($seconds / 60 );
if($mins) {
    $fmt .= str_pad($mins, 2, '0', STR_PAD_LEFT).":";
    $seconds %= 60;
}

$fmt .= str_pad($seconds, 2, '0', STR_PAD_LEFT);

return $fmt;}

如果你想创建一个音频/视频持续时间字符串,如YouTube等,你可以这样做:

($seconds >= 60) ?ltrim(函数(“我:年代”,美元秒),“0”):函数(“0:年代”,美元秒)

将返回如下字符串:

55.55 => '0:55'
100   => '1:40'

在>= 24小时内可能不会很好地工作。