我想测量执行一个函数所花费的时间。我没时间工作:

import timeit
start = timeit.timeit()
print("hello")
end = timeit.timeit()
print(end - start)

当前回答

如何测量两次操作之间的时间。比较两次操作的时间。

import time

b = (123*321)*123
t1 = time.time()

c = ((9999^123)*321)^123
t2 = time.time()

print(t2-t1)

7.987022399902344e-05

其他回答

基于https://stackoverflow.com/a/30024601/5095636,以下为无lambda版本,如flake8根据E731对lambda使用的警告:

from contextlib import contextmanager
from timeit import default_timer

@contextmanager
def elapsed_timer():
    start_time = default_timer()

    class _Timer():
      start = start_time
      end = default_timer()
      duration = end - start

    yield _Timer

    end_time = default_timer()
    _Timer.end = end_time
    _Timer.duration = end_time - start_time

测试:

from time import sleep

with elapsed_timer() as t:
    print("start:", t.start)
    sleep(1)
    print("end:", t.end)

t.start
t.end
t.duration

您可以使用Benchmark Timer(免责声明:我是作者):

基准计时器使用BenchmarkTimer类来测量执行某段代码所需的时间。这比内置的timeit函数具有更大的灵活性,并且与其他代码在相同的范围内运行。安装pip安装git+https://github.com/michaelitvin/benchmark-timer.git@main#egg=基准计时器用法单次迭代示例从benchmark_timer导入BenchmarkTimer导入时间使用BenchmarkTimer(name=“MySimpleCode”)作为tm,tm.single_ieration():睡眠时间(.3)输出:正在对标MySimpleCode。。。MySimpleCode基准:n_iters=1 avg=0.300881s std=0.000000s range=[0.3000881s ~ 0.300881s]多次迭代示例从benchmark_timer导入BenchmarkTimer导入时间使用BenchmarkTimer(name=“MyTimedCode”,print_iters=True)作为tm:对于tm迭代中的timing_iteration(n=5,预热=2):定时重复:睡眠时间(.1)打印(“\n===============\n”)print(“定时列表:”,列表(tm.timenings.values()))输出:正在对标MyTimedCode。。。[MyTimedCode]iter=0耗时0.099755s(预热)[MyTimedCode]iter=1耗时0.100476秒(预热)[MyTimedCode]iter=2耗时0.100189秒[MyTimedCode]iter=3耗时0.099900s[MyTimedCode]iter=4耗时0.100888秒MyTimedCode基准:n_iters=3 avg=0.100326s std=0.000414s range=[0.099900s ~ 0.100888s]===================时间列表:[0.1001885000000001,0.09990049999999995,0.10088760000000008]

import time

def getElapsedTime(startTime, units):
    elapsedInSeconds = time.time() - startTime
    if units == 'sec':
        return elapsedInSeconds
    if units == 'min':
        return elapsedInSeconds/60
    if units == 'hour':
        return elapsedInSeconds/(60*60)

对于Python 3

如果使用时间模块,则可以获取当前时间戳,然后执行代码,然后再次获取时间戳。现在,所用时间将是第一个时间戳减去第二个时间戳:

import time

first_stamp = int(round(time.time() * 1000))

# YOUR CODE GOES HERE
time.sleep(5)

second_stamp = int(round(time.time() * 1000))

# Calculate the time taken in milliseconds
time_taken = second_stamp - first_stamp

# To get time in seconds:
time_taken_seconds = round(time_taken / 1000)
print(f'{time_taken_seconds} seconds or {time_taken} milliseconds')

我参加聚会已经很晚了,但这种方法以前没有涉及过。当我们想要手动对某段代码进行基准测试时,我们可能需要首先找出哪些类方法占用了执行时间,这有时并不明显。我构建了以下元类来解决这个问题:

from __future__ import annotations

from functools import wraps
from time import time
from typing import Any, Callable, TypeVar, cast

F = TypeVar('F', bound=Callable[..., Any])


def timed_method(func: F, prefix: str | None = None) -> F:
    prefix = (prefix + ' ') if prefix else ''

    @wraps(func)
    def inner(*args, **kwargs):  # type: ignore
        start = time()
        try:
            ret = func(*args, **kwargs)
        except BaseException:
            print(f'[ERROR] {prefix}{func.__qualname__}: {time() - start}')
            raise
        
        print(f'{prefix}{func.__qualname__}: {time() - start}')
        return ret

    return cast(F, inner)


class TimedClass(type):
    def __new__(
        cls: type[TimedClass],
        name: str,
        bases: tuple[type[type], ...],
        attrs: dict[str, Any],
        **kwargs: Any,
    ) -> TimedClass:
        for name, attr in attrs.items():
            if isinstance(attr, (classmethod, staticmethod)):
                attrs[name] = type(attr)(timed_method(attr.__func__))
            elif isinstance(attr, property):
                attrs[name] = property(
                    timed_method(attr.fget, 'get') if attr.fget is not None else None,
                    timed_method(attr.fset, 'set') if attr.fset is not None else None,
                    timed_method(attr.fdel, 'del') if attr.fdel is not None else None,
                )
            elif callable(attr):
                attrs[name] = timed_method(attr)

        return super().__new__(cls, name, bases, attrs)

它允许如下使用:

class MyClass(metaclass=TimedClass):
    def foo(self): 
        print('foo')
    
    @classmethod
    def bar(cls): 
        print('bar')
    
    @staticmethod
    def baz(): 
        print('baz')
    
    @property
    def prop(self): 
        print('prop')
    
    @prop.setter
    def prop(self, v): 
        print('fset')
    
    @prop.deleter
    def prop(self): 
        print('fdel')


c = MyClass()

c.foo()
c.bar()
c.baz()
c.prop
c.prop = 2
del c.prop

MyClass.bar()
MyClass.baz()

它打印:

foo
MyClass.foo: 1.621246337890625e-05
bar
MyClass.bar: 4.5299530029296875e-06
baz
MyClass.baz: 4.291534423828125e-06
prop
get MyClass.prop: 3.814697265625e-06
fset
set MyClass.prop: 3.5762786865234375e-06
fdel
del MyClass.prop: 3.5762786865234375e-06
bar
MyClass.bar: 3.814697265625e-06
baz
MyClass.baz: 4.0531158447265625e-06

它可以与其他答案相结合,以更精确的方式代替time.time。