如何从我的C或c++代码中确定目录中的文件列表?

我不允许在程序中执行ls命令并解析结果。


当前回答

塞萨尔·亚历杭德罗·蒙特罗·奥罗斯科回答。

简单中有美,通过添加/s键,我们还可以遍历子目录。

system("dir /n /b /s * > file_names.txt");

其他回答

这个实现实现了您的目的,用指定目录的内容动态填充字符串数组。

int exploreDirectory(const char *dirpath, char ***list, int *numItems) {
    struct dirent **direntList;
    int i;
    errno = 0;

    if ((*numItems = scandir(dirpath, &direntList, NULL, alphasort)) == -1)
        return errno;

    if (!((*list) = malloc(sizeof(char *) * (*numItems)))) {
        fprintf(stderr, "Error in list allocation for file list: dirpath=%s.\n", dirpath);
        exit(EXIT_FAILURE);
    }

    for (i = 0; i < *numItems; i++) {
        (*list)[i] = stringDuplication(direntList[i]->d_name);
    }

    for (i = 0; i < *numItems; i++) {
        free(direntList[i]);
    }

    free(direntList);

    return 0;
}

为什么不使用glob()?

#include <glob.h>

glob_t glob_result;
glob("/your_directory/*",GLOB_TILDE,NULL,&glob_result);
for(unsigned int i=0; i<glob_result.gl_pathc; ++i){
  cout << glob_result.gl_pathv[i] << endl;
}

基于上面的答案

#include <vector>
#include <string>
#include <algorithm>

#ifdef _WIN32
#include <windows.h>
std::vector<std::string> files_in_directory(std::string path)
{
    std::vector<std::string> files;

    // check directory exists
    char fullpath[MAX_PATH];
    GetFullPathName(path.c_str(), MAX_PATH, fullpath, 0);
    std::string fp(fullpath);
    if (GetFileAttributes(fp.c_str()) != FILE_ATTRIBUTE_DIRECTORY)
        return files;

    // get file names
    WIN32_FIND_DATA findfiledata;
    HANDLE hFind = FindFirstFile((LPCSTR)(fp + "\\*").c_str(), &findfiledata);
    if (hFind != INVALID_HANDLE_VALUE)
    {
        do 
        {
            files.push_back(findfiledata.cFileName);
        } 
        while (FindNextFile(hFind, &findfiledata));
        FindClose(hFind);
    }

    // delete current and parent directories
    files.erase(std::find(files.begin(), files.end(), "."));
    files.erase(std::find(files.begin(), files.end(), ".."));

    // sort in alphabetical order
    std::sort(files.begin(), files.end());

    return files;
}
#else
#include <dirent.h>
std::vector<std::string> files_in_directory(std::string directory)
{
    std::vector<std::string> files;

    // open directory
    DIR *dir;
    dir = opendir(directory.c_str());
    if (dir == NULL)
        return files;

    // get file names
    struct dirent *ent;
    while ((ent = readdir(dir)) != NULL)
        files.push_back(ent->d_name);
    closedir(dir);

    // delete current and parent directories
    files.erase(std::find(files.begin(), files.end(), "."));
    files.erase(std::find(files.begin(), files.end(), ".."));

    // sort in alphabetical order
    std::sort(files.begin(), files.end());

    return files;
}
#endif  // _WIN32
#include<iostream>
#include <dirent.h>
using namespace std;
char ROOT[]={'.'};

void listfiles(char* path){
    DIR * dirp = opendir(path);
    dirent * dp;
    while ( (dp = readdir(dirp)) !=NULL ) {
         cout << dp->d_name << " size " << dp->d_reclen<<std::endl;
    }
    (void)closedir(dirp);
}

int main(int argc, char **argv)
{
    char* path;
    if (argc>1) path=argv[1]; else path=ROOT;

    cout<<"list files in ["<<path<<"]"<<std::endl;
    listfiles(path);

    return 0;
}

下面是c++ 11中使用boost::filesystem库获取目录中的文件名(不包括文件夹名)的一个非常简单的代码:

#include <string>
#include <iostream>
#include <boost/filesystem.hpp>
using namespace std;
using namespace boost::filesystem;

int main()
{
    path p("D:/AnyFolder");
    for (auto i = directory_iterator(p); i != directory_iterator(); i++)
    {
        if (!is_directory(i->path())) //we eliminate directories
        {
            cout << i->path().filename().string() << endl;
        }
        else
            continue;
    }
}

输出如下:

file1.txt
file2.dat