我有几个方法返回不同的泛型列表。
在。net中存在任何类静态方法或将任何列表转换为数据表?我唯一能想到的是使用反射来做到这一点。
如果我有这个:
List<Whatever> whatever = new List<Whatever>();
(这下代码当然不工作,但我想有这样的可能性:
DataTable dt = (DataTable) whatever;
我有几个方法返回不同的泛型列表。
在。net中存在任何类静态方法或将任何列表转换为数据表?我唯一能想到的是使用反射来做到这一点。
如果我有这个:
List<Whatever> whatever = new List<Whatever>();
(这下代码当然不工作,但我想有这样的可能性:
DataTable dt = (DataTable) whatever;
当前回答
我认为它更方便和容易使用。
List<Whatever> _lobj= new List<Whatever>();
var json = JsonConvert.SerializeObject(_lobj);
DataTable dt = (DataTable)JsonConvert.DeserializeObject(json, (typeof(DataTable)));
其他回答
如果你使用VB。NET,那么这个类就会完成这项工作。
Imports System.Reflection
''' <summary>
''' Convert any List(Of T) to a DataTable with correct column types and converts Nullable Type values to DBNull
''' </summary>
Public Class ConvertListToDataset
Public Function ListToDataset(Of T)(ByVal list As IList(Of T)) As DataTable
Dim dt As New DataTable()
'/* Create the DataTable columns */
For Each pi As PropertyInfo In GetType(T).GetProperties()
If pi.PropertyType.IsValueType Then
Debug.Print(pi.Name)
End If
If IsNothing(Nullable.GetUnderlyingType(pi.PropertyType)) Then
dt.Columns.Add(pi.Name, pi.PropertyType)
Else
dt.Columns.Add(pi.Name, Nullable.GetUnderlyingType(pi.PropertyType))
End If
Next
'/* Populate the DataTable with the values in the Items in List */
For Each item As T In list
Dim dr As DataRow = dt.NewRow()
For Each pi As PropertyInfo In GetType(T).GetProperties()
dr(pi.Name) = IIf(IsNothing(pi.GetValue(item)), DBNull.Value, pi.GetValue(item))
Next
dt.Rows.Add(dr)
Next
Return dt
End Function
End Class
如果你想使用反射并设置列的顺序/只包括一些列/排除一些列,试试这个:
private static DataTable ConvertToDataTable<T>(IList<T> data, string[] fieldsToInclude = null,
string[] fieldsToExclude = null)
{
PropertyDescriptorCollection properties = TypeDescriptor.GetProperties(typeof(T));
DataTable table = new DataTable();
foreach (PropertyDescriptor prop in properties)
{
if ((fieldsToInclude != null && !fieldsToInclude.Contains(prop.Name)) ||
(fieldsToExclude != null && fieldsToExclude.Contains(prop.Name)))
continue;
table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);
}
foreach (T item in data)
{
var atLeastOnePropertyExists = false;
DataRow row = table.NewRow();
foreach (PropertyDescriptor prop in properties)
{
if ((fieldsToInclude != null && !fieldsToInclude.Contains(prop.Name)) ||
(fieldsToExclude != null && fieldsToExclude.Contains(prop.Name)))
continue;
row[prop.Name] = prop.GetValue(item) ?? DBNull.Value;
atLeastOnePropertyExists = true;
}
if(atLeastOnePropertyExists) table.Rows.Add(row);
}
if (fieldsToInclude != null)
SetColumnsOrder(table, fieldsToInclude);
return table;
}
private static void SetColumnsOrder(DataTable table, params String[] columnNames)
{
int columnIndex = 0;
foreach (var columnName in columnNames)
{
table.Columns[columnName].SetOrdinal(columnIndex);
columnIndex++;
}
}
如果你的类中有属性,这行代码是OK的!!
PropertyDescriptorCollection props =
TypeDescriptor.GetProperties(typeof(T));
但如果你有所有的公共字段,那么使用这个:
public static DataTable ToDataTable<T>( IList<T> data)
{
FieldInfo[] myFieldInfo;
Type myType = typeof(T);
// Get the type and fields of FieldInfoClass.
myFieldInfo = myType.GetFields(BindingFlags.NonPublic | BindingFlags.Instance
| BindingFlags.Public);
DataTable dt = new DataTable();
for (int i = 0; i < myFieldInfo.Length; i++)
{
FieldInfo property = myFieldInfo[i];
dt.Columns.Add(property.Name, property.FieldType);
}
object[] values = new object[myFieldInfo.Length];
foreach (T item in data)
{
for (int i = 0; i < values.Length; i++)
{
values[i] = myFieldInfo[i].GetValue(item);
}
dt.Rows.Add(values);
}
return dt;
}
原来的答案是从上面,我只是编辑使用字段而不是属性
然后这样使用它
DataTable dt = new DataTable();
dt = ToDataTable(myBriefs);
gridData.DataSource = dt;
gridData.DataBind();
将通用列表转换为数据表
使用Newtonsoft.Json;
public DataTable GenericToDataTable(IList<T> list)
{
var json = JsonConvert.SerializeObject(list);
DataTable dt = (DataTable)JsonConvert.DeserializeObject(json, (typeof(DataTable)));
return dt;
}
我认为它更方便和容易使用。
List<Whatever> _lobj= new List<Whatever>();
var json = JsonConvert.SerializeObject(_lobj);
DataTable dt = (DataTable)JsonConvert.DeserializeObject(json, (typeof(DataTable)));