我有2个不同的嵌套对象,我需要知道它们是否在其中一个嵌套属性中有不同。
var a = {};
var b = {};
a.prop1 = 2;
a.prop2 = { prop3: 2 };
b.prop1 = 2;
b.prop2 = { prop3: 3 };
对象可以更复杂,有更多嵌套的属性。但这是一个很好的例子。我可以选择使用递归函数或lodash的东西…
我有2个不同的嵌套对象,我需要知道它们是否在其中一个嵌套属性中有不同。
var a = {};
var b = {};
a.prop1 = 2;
a.prop2 = { prop3: 2 };
b.prop1 = 2;
b.prop2 = { prop3: 3 };
对象可以更复杂,有更多嵌套的属性。但这是一个很好的例子。我可以选择使用递归函数或lodash的东西…
当前回答
下面是一个使用Lodash的简单解决方案:
_.differenceWith(a, b, _.isEqual);
注意,两个输入都需要是数组(可能是一个对象的数组)。
其他回答
简单使用_。isEqual方法,它将适用于所有比较…
注意:此方法支持比较数组、数组缓冲区、 布尔值、 *日期对象,错误对象,地图,数字,对象对象,正则表达式, *集合、字符串、符号和类型化数组。对象对象进行比较 *通过自身的,不可继承的,可枚举的属性。函数和DOM *节点不支持。
所以如果你有以下情况:
const firstName = {name: "Alireza"};
const otherName = {name: "Alireza"};
如果是:_。isEqual (firstName, otherName);
它会返回true
如果const fullName = {firstName: "Alireza", familyName: "Dezfoolian"};
如果是:_。isEqual (firstName, fullName);
将返回false
我们需要在两个json更新之间获取delta,以跟踪数据库更新。也许其他人会觉得这很有用。
https://gist.github.com/jp6rt/7fcb6907e159d7851c8d59840b669e3d
const {
isObject,
isEqual,
transform,
has,
merge,
} = require('lodash');
const assert = require('assert');
/**
* Perform a symmetric comparison on JSON object.
* @param {*} baseObj - The base object to be used for comparison against the withObj.
* @param {*} withObj - The withObject parameter is used as the comparison on the base object.
* @param {*} invert - Because this is a symmetric comparison. Some values in the with object
* that doesn't exist on the base will be lost in translation.
* You can execute again the function again with the parameters interchanged.
* However you will lose the reference if the value is from the base or with
* object if you intended to do an assymetric comparison.
* Setting this to true will do make sure the reference is not lost.
* @returns - The returned object will label the result of the comparison with the
* value from base and with object.
*/
const diffSym = (baseObj, withObj, invert = false) => transform(baseObj, (result, value, key) => {
if (isEqual(value, withObj[key])
&& has(withObj, key)) {
return;
}
if (isObject(value)
&& isObject(withObj[key])
&& !Array.isArray(value)) {
result[key] = diffSym(value, withObj[key], invert);
return;
}
if (!invert) {
result[key] = {
base: value,
with: withObj[key],
};
return;
}
if (invert) {
result[key] = {
base: withObj[key],
with: value,
};
}
});
/**
* Perform a assymmetric comparison on JSON object.
* @param {*} baseObj - The base object to be used for comparison against the withObj.
* @param {*} withObj - The withObject parameter is used as the comparison on the base object.
* @returns - The returned object will label the values with
* reference to the base and with object.
*/
const diffJSON = (baseObj, withObj) => {
// Deep clone the objects so we don't update the reference objects.
const baseObjClone = JSON.parse(JSON.stringify(baseObj));
const withObjClone = JSON.parse(JSON.stringify(withObj));
const beforeDelta = diffSym(baseObjClone, withObjClone);
const afterDelta = diffSym(withObjClone, baseObjClone, true);
return merge(afterDelta, beforeDelta);
};
// By Example:
const beforeDataObj = {
a: 1,
c: { d: 2, f: 3 },
g: 4,
h: 5,
};
const afterDataObj = {
a: 2,
b: 3,
c: { d: 1, e: 1 },
h: 5,
};
const delta = diffJSON(beforeDataObj, afterDataObj);
// Assert expected result.
assert(isEqual(delta, {
a: { base: 1, with: 2 },
b: { base: undefined, with: 3 },
c: {
d: { base: 2, with: 1 },
e: { base: undefined, with: 1 },
f: { base: 3, with: undefined },
},
g: { base: 4, with: undefined },
}));
这段代码返回一个具有不同值的所有属性的对象,以及两个对象的值。对记录差异很有用。
var allkeys = _.union(_.keys(obj1), _.keys(obj2));
var difference = _.reduce(allkeys, function (result, key) {
if ( !_.isEqual(obj1[key], obj2[key]) ) {
result[key] = {obj1: obj1[key], obj2: obj2[key]}
}
return result;
}, {});
以Sridhar Gudimela的回答为基础,下面以一种使用TypeScript的方式进行了更新:
/// U T I L S
interface LooseObjectInterface {
[key: string]: any;
};
type inputOptions = LooseObjectInterface | any[];
/// E X P O R T
export const objectCompare = (objectA: inputOptions, objectB: inputOptions): LooseObjectInterface => {
let diffObj: LooseObjectInterface = {};
switch(true) {
case (Array.isArray(objectA)):
objectA.forEach((elem: any, index: number) => {
if (!Array.isArray(diffObj))
diffObj = [];
diffObj[index] = objectCompare(elem, (objectB || [])[index]);
});
break;
case (objectA !== null && typeof objectA === "object"):
Object.keys(objectA).forEach((key: any) => {
if (Array.isArray(objectA[key])) {
let arr = objectCompare(objectA[key], objectB[key]);
if (!Array.isArray(arr))
arr = [];
arr.forEach((elem: any, index: number) => {
if (!Array.isArray(diffObj[key]))
diffObj[key] = [];
diffObj[key][index] = elem;
});
} else if (typeof objectA[key] === "object")
diffObj[key] = objectCompare(objectA[key], objectB[key]);
else if (objectA[key] !== (objectB || {})[key])
diffObj[key] = objectA[key];
else if (objectA[key] === (objectB || {})[key])
delete objectA[key];
});
break;
default:
break;
}
Object.keys(diffObj).forEach((key: any) => {
if (typeof diffObj[key] === "object" && JSON.stringify(diffObj[key]) === "{}")
delete diffObj[key];
});
return diffObj;
};
编辑:我最初的回答使用了Flow,因此被否决了(我猜,或者可能是因为我的回答没有使用Lodash……)然而,有一个类似问题的答案也无妨)。
这是我对这个问题的解决办法
const _ = require('lodash');
var objects = [{ 'x': 1, 'y': 2, 'z':3, a:{b:1, c:2, d:{n:0}}, p:[1, 2, 3] }, { 'x': 2, 'y': 1, z:3, a:{b:2, c:2,d:{n:1}}, p:[1,3], m:3 }];
const diffFn=(a,b, path='')=>_.reduce(a, function(result, value, key) {
if(_.isObjectLike(value)){
if(_.isEqual(value, b[key])){
return result;
}else{
return result.concat(diffFn(value, b[key], path?(`${path}.${key}`):key))
}
}else{
return _.isEqual(value, b[key]) ?
result : result.concat(path?(`${path}.${key}`):key);
}
}, []);
const diffKeys1=diffFn(objects[0], objects[1])
const diffKeys2=diffFn(objects[1], objects[0])
const diffKeys=_.union(diffKeys1, diffKeys2)
const res={};
_.forEach(diffKeys, (key)=>_.assign(res, {[key]:{ old: _.get(objects[0], key), new:_.get(objects[1], key)} }))
res
/*
Returns
{
x: { old: 1, new: 2 },
y: { old: 2, new: 1 },
'a.b': { old: 1, new: 2 },
'a.d.n': { old: 0, new: 1 },
'p.1': { old: 2, new: 3 },
'p.2': { old: 3, new: undefined },
m: { old: undefined, new: 3 }
}
*/