基于ID匹配从一个表到另一个表的SQL更新

我有一个有帐号和卡号的数据库。我将这些匹配到一个文件，以将任何卡号更新为帐号，这样我只使用帐号。

我创建了一个将表链接到帐户/卡数据库的视图，以返回table ID和相关的帐号，现在我需要更新那些ID与account number匹配的记录。

这是Sales_Import表，其中的帐号字段需要更新:

LeadID	AccountNumber
147	5807811235
150	5807811326
185	7006100100007267039

这是RetrieveAccountNumber表，我需要从这里更新:

LeadID	AccountNumber
147	7006100100007266957
150	7006100100007267039

我尝试了下面的方法，但到目前为止运气都不佳:

UPDATE [Sales_Lead].[dbo].[Sales_Import] 
SET    [AccountNumber] = (SELECT RetrieveAccountNumber.AccountNumber 
                          FROM   RetrieveAccountNumber 
                          WHERE  [Sales_Lead].[dbo].[Sales_Import]. LeadID = 
                                                RetrieveAccountNumber.LeadID)

它将卡号更新为帐号，但是帐号被NULL替换

当前回答

甲骨文

use

UPDATE suppliers
SET supplier_name = (SELECT customers.customer_name
                     FROM customers
                     WHERE customers.customer_id = suppliers.supplier_id)
WHERE EXISTS (SELECT customers.customer_name
              FROM customers
              WHERE customers.customer_id = suppliers.supplier_id);

2022-01-28 15:14:07

其他回答

在同一个表内更新:

  DECLARE @TB1 TABLE
    (
        No Int
        ,Name NVarchar(50)
        ,linkNo int
    )

    DECLARE @TB2 TABLE
    (
        No Int
        ,Name NVarchar(50)
        ,linkNo int
    )

    INSERT INTO @TB1 VALUES(1,'changed person data',  0);
    INSERT INTO @TB1 VALUES(2,'old linked data of person', 1);

INSERT INTO @TB2 SELECT * FROM @TB1 WHERE linkNo = 0


SELECT * FROM @TB1
SELECT * FROM @TB2


    UPDATE @TB1 
        SET Name = T2.Name
    FROM        @TB1 T1
    INNER JOIN  @TB2 T2 ON T2.No = T1.linkNo

    SELECT * FROM @TB1

2012-12-06 12:24:29

根据匹配的id从一个表更新到另一个表

UPDATE 
     TABLE1 t1, 
     TABLE2 t2
SET 
     t1.column_name = t2.column_name 
WHERE
     t1.id = t2.id;

2020-12-21 13:25:30

如果以上答案不适合你，试试这个

Update Sales_Import A left join RetrieveAccountNumber B on A.LeadID = B.LeadID
Set A.AccountNumber = B.AccountNumber
where A.LeadID = B.LeadID

2018-01-10 04:10:35

MYSQL(这是我最喜欢的恢复所有特定列reasonId值的方法，基于主键id等价)

UPDATE `site` AS destination  
INNER JOIN `site_copy` AS backupOnTuesday 
      ON backupOnTuesday.`id` = destination.`id`
SET destdestination.`reasonId` = backupOnTuesday.`reasonId`

2021-01-06 09:46:14

MS Sql

UPDATE  c4 SET Price=cp.Price*p.FactorRate FROM TableNamea_A c4
inner join TableNamea_B p on c4.Calcid=p.calcid 
inner join TableNamea_A cp on c4.Calcid=cp.calcid 
WHERE c4..Name='MyName';

Oracle 11 g

        MERGE INTO  TableNamea_A u 
        using
        (
                SELECT c4.TableName_A_ID,(cp.Price*p.FactorRate) as CalcTot 
                FROM TableNamea_A c4
                inner join TableNamea_B p on c4.Calcid=p.calcid 
                inner join TableNamea_A cp on c4.Calcid=cp.calcid 
                WHERE p.Name='MyName' 
        )  rt
        on (u.TableNamea_A_ID=rt.TableNamea_B_ID)
        WHEN MATCHED THEN
        Update set Price=CalcTot  ;

2019-04-23 06:30:11

基于ID匹配从一个表到另一个表的SQL更新

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