灵感来自@kitsu的回答。但使用RandomNumberGenerator而不是Random或RNGCryptoServiceProvider(在。net 6中已弃用)，并添加了一些特殊字符。

可选参数，用于排除在使用System.Text.Json.JsonSerializer.Serialize时将转义的字符—例如&，它转义为\u0026—以便您可以保证序列化字符串的长度与密码的长度匹配。

适用于。net Core 3.0及以上版本。

public static class PasswordGenerator
{
    const string lower = "abcdefghijklmnopqrstuvwxyz";
    const string upper = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    const string number = "1234567890";
    const string special = "!@#$%^&*()[]{},.:`~_-=+"; // excludes problematic characters like ;'"/\
    const string specialJsonSafe = "!@#$%^*()[]{},.:~_-="; // excludes problematic characters like ;'"/\ and &`+

    const int lowerLength = 26; // lower.Length
    const int upperLength = 26; // upper.Length;
    const int numberLength = 10; // number.Length;
    const int specialLength = 23; // special.Length;
    const int specialJsonSafeLength = 20; // specialJsonSafe.Length;

    public static string Generate(int length = 96, bool jsonSafeSpecialCharactersOnly = false)
    {
        Span<char> result = length < 1024 ? stackalloc char[length] : new char[length].AsSpan();

        for (int i = 0; i < length; ++i)
        {
            switch (RandomNumberGenerator.GetInt32(4))
            {
                case 0:
                    result[i] = lower[RandomNumberGenerator.GetInt32(0, lowerLength)];
                    break;
                case 1:
                    result[i] = upper[RandomNumberGenerator.GetInt32(0, upperLength)];
                    break;
                case 2:
                    result[i] = number[RandomNumberGenerator.GetInt32(0, numberLength)];
                    break;
                case 3:
                    if (jsonSafeSpecialCharactersOnly)
                    {
                        result[i] = specialJsonSafe[RandomNumberGenerator.GetInt32(0, specialJsonSafeLength)];
                    }
                    else
                    {
                        result[i] = special[RandomNumberGenerator.GetInt32(0, specialLength)];
                    }
                    break;
            }
        }

        return result.ToString();
    }
}

插入一个定时器:timer1, 2个按钮:button1, button2, 1个textBox: textBox1，和一个comboBox: comboBox1。请务必申报:

int count = 0;

源代码:

 private void button1_Click(object sender, EventArgs e)
    {
    // This clears the textBox, resets the count, and starts the timer
        count = 0;
        textBox1.Clear();
        timer1.Start();
    }

    private void timer1_Tick(object sender, EventArgs e)
    {
    // This generates the password, and types it in the textBox
        count += 1;
            string possible = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
            string psw = "";
            Random rnd = new Random { };
            psw += possible[rnd.Next(possible.Length)];
            textBox1.Text += psw;
            if (count == (comboBox1.SelectedIndex + 1))
            {
                timer1.Stop();
            }
    }
    private void Form1_Load(object sender, EventArgs e)
    {
        // This adds password lengths to the comboBox to choose from.
        comboBox1.Items.Add("1");
        comboBox1.Items.Add("2");
        comboBox1.Items.Add("3");
        comboBox1.Items.Add("4");
        comboBox1.Items.Add("5");
        comboBox1.Items.Add("6");
        comboBox1.Items.Add("7");
        comboBox1.Items.Add("8");
        comboBox1.Items.Add("9");
        comboBox1.Items.Add("10");
        comboBox1.Items.Add("11");
        comboBox1.Items.Add("12");
    }
    private void button2_click(object sender, EventArgs e)
    {
        // This encrypts the password
        tochar = textBox1.Text;
        textBox1.Clear();
        char[] carray = tochar.ToCharArray();
        for (int i = 0; i < carray.Length; i++)
        {
            int num = Convert.ToInt32(carray[i]) + 10;
            string cvrt = Convert.ToChar(num).ToString();
            textBox1.Text += cvrt;
        }
    }

在我的网站上，我使用这个方法:

    //Symb array
    private const string _SymbolsAll = "~`!@#$%^&*()_+=-\\|[{]}'\";:/?.>,<";

    //Random symb
    public string GetSymbol(int Length)
    {
        Random Rand = new Random(DateTime.Now.Millisecond);
        StringBuilder result = new StringBuilder();
        for (int i = 0; i < Length; i++)
            result.Append(_SymbolsAll[Rand.Next(0, _SymbolsAll.Length)]);
        return result.ToString();
    }

编辑字符串_SymbolsAll为你的数组列表。

public static string GeneratePassword(int passLength) {
        var chars = "abcdefghijklmnopqrstuvwxyz@#$&ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
        var random = new Random();
        var result = new string(
            Enumerable.Repeat(chars, passLength)
                      .Select(s => s[random.Next(s.Length)])
                      .ToArray());
        return result;
    }

我喜欢生成密码，就像生成软件密钥一样。您应该从遵循良好实践的字符数组中进行选择。采用@Radu094回答的内容并修改它以遵循良好的实践。不要把每个字母都放在字符数组中。有些信在电话里更难读懂。

您还应该考虑对生成的密码使用校验和，以确保它是由您生成的。实现这一点的一个好方法是使用LUHN算法。

validChars可以是任何结构，但我决定基于ascii码范围选择删除控制字符。本例中为12个字符的字符串。

string validChars = String.Join("", Enumerable.Range(33, (126 - 33)).Where(i => !(new int[] { 34, 38, 39, 44, 60, 62, 96 }).Contains(i)).Select(i => { return (char)i; }));
string.Join("", Enumerable.Range(1, 12).Select(i => { return validChars[(new Random(Guid.NewGuid().GetHashCode())).Next(0, validChars.Length - 1)]; }))