2024-04-14 06:00:02

c#中的数组片

你是怎么做到的?给定一个字节数组:

byte[] foo = new byte[4096];

我如何得到数组的前x字节作为一个单独的数组?(具体来说,我需要它作为一个IEnumerable<byte>)

这是用于使用Sockets的。我认为最简单的方法是数组切片,类似于perl语法:

@bar = @foo[0..40];

将前41个元素返回到@bar数组中。c#中是否有我遗漏的东西,或者有其他我应该做的事情?

LINQ对我来说是一个选择。NET 3.5),如果有帮助的话。


当前回答

如果你想要IEnumerable<byte>,那么只是

IEnumerable<byte> data = foo.Take(x);

其他回答

您可以使用Take扩展方法

var array = new byte[] {1, 2, 3, 4};
var firstTwoItems = array.Take(2);
static byte[] SliceMe(byte[] source, int length)
{
    byte[] destfoo = new byte[length];
    Array.Copy(source, 0, destfoo, 0, length);
    return destfoo;
}

//

var myslice = SliceMe(sourcearray,41);

如果你想要IEnumerable<byte>,那么只是

IEnumerable<byte> data = foo.Take(x);

您可以对原始数组(即IList)使用包装器,就像下面(未经测试的)代码一样。

public class SubList<T> : IList<T>
{
    #region Fields

    private readonly int startIndex;
    private readonly int endIndex;
    private readonly int count;
    private readonly IList<T> source;

    #endregion

    public SubList(IList<T> source, int startIndex, int count)
    {
        this.source = source;
        this.startIndex = startIndex;
        this.count = count;
        this.endIndex = this.startIndex + this.count - 1;
    }

    #region IList<T> Members

    public int IndexOf(T item)
    {
        if (item != null)
        {
            for (int i = this.startIndex; i <= this.endIndex; i++)
            {
                if (item.Equals(this.source[i]))
                    return i;
            }
        }
        else
        {
            for (int i = this.startIndex; i <= this.endIndex; i++)
            {
                if (this.source[i] == null)
                    return i;
            }
        }
        return -1;
    }

    public void Insert(int index, T item)
    {
        throw new NotSupportedException();
    }

    public void RemoveAt(int index)
    {
        throw new NotSupportedException();
    }

    public T this[int index]
    {
        get
        {
            if (index >= 0 && index < this.count)
                return this.source[index + this.startIndex];
            else
                throw new IndexOutOfRangeException("index");
        }
        set
        {
            if (index >= 0 && index < this.count)
                this.source[index + this.startIndex] = value;
            else
                throw new IndexOutOfRangeException("index");
        }
    }

    #endregion

    #region ICollection<T> Members

    public void Add(T item)
    {
        throw new NotSupportedException();
    }

    public void Clear()
    {
        throw new NotSupportedException();
    }

    public bool Contains(T item)
    {
        return this.IndexOf(item) >= 0;
    }

    public void CopyTo(T[] array, int arrayIndex)
    {
        for (int i=0; i<this.count; i++)
        {
            array[arrayIndex + i] = this.source[i + this.startIndex];
        }
    }

    public int Count
    {
        get { return this.count; }
    }

    public bool IsReadOnly
    {
        get { return true; }
    }

    public bool Remove(T item)
    {
        throw new NotSupportedException();
    }

    #endregion

    #region IEnumerable<T> Members

    public IEnumerator<T> GetEnumerator()
    {
        for (int i = this.startIndex; i < this.endIndex; i++)
        {
            yield return this.source[i];
        }
    }

    #endregion

    #region IEnumerable Members

    IEnumerator IEnumerable.GetEnumerator()
    {
        return GetEnumerator();
    }

    #endregion
}

下面是一个简单的扩展方法,它返回一个slice作为一个新数组:

public static T[] Slice<T>(this T[] arr, uint indexFrom, uint indexTo) {
    if (indexFrom > indexTo) {
        throw new ArgumentOutOfRangeException("indexFrom is bigger than indexTo!");
    }

    uint length = indexTo - indexFrom;
    T[] result = new T[length];
    Array.Copy(arr, indexFrom, result, 0, length);

    return result;
}

然后你可以这样使用它:

byte[] slice = foo.Slice(0, 40);