有些函数，比如INDEX'ing，可能会花费很长时间——而且在运行时它会锁定整个数据库。在这种情况下，它甚至可能不使用日志文件!

因此，最好/唯一的方法来检查您的数据库是否被锁定，因为一个进程正在积极地写入它(因此你应该让它独自呆着，直到它完成它的操作)是md5(或md5sum在某些系统)文件两次。 如果你得到一个不同的校验和，数据库正在被写入，你真的真的真的不想杀死这个进程，因为如果你这样做，你很容易得到一个损坏的表/数据库。

我要重申一下，因为这很重要——解决方案不是找到锁程序并杀死它——而是找出数据库是否有一个很好的写锁，然后从那里开始。有时候正确的解决方法就是喝杯咖啡休息一下。

The only way to create this locked-but-not-being-written-to situation is if your program runs BEGIN EXCLUSIVE, because it wanted to do some table alterations or something, then for whatever reason never sends an END afterwards, and the process never terminates. All three conditions being met is highly unlikely in any properly-written code, and as such 99 times out of 100 when someone wants to kill -9 their locking process, the locking process is actually locking your database for a good reason. Programmers don't typically add the BEGIN EXCLUSIVE condition unless they really need to, because it prevents concurrency and increases user complaints. SQLite itself only adds it when it really needs to (like when indexing).

Finally, the 'locked' status does not exist INSIDE the file as several answers have stated - it resides in the Operating System's kernel. The process which ran BEGIN EXCLUSIVE has requested from the OS a lock be placed on the file. Even if your exclusive process has crashed, your OS will be able to figure out if it should maintain the file lock or not!! It is not possible to end up with a database which is locked but no process is actively locking it!! When it comes to seeing which process is locking the file, it's typically better to use lsof rather than fuser (this is a good demonstration of why: https://unix.stackexchange.com/questions/94316/fuser-vs-lsof-to-check-files-in-use). Alternatively if you have DTrace (OSX) you can use iosnoop on the file.

如果一个进程在SQLite DB上有一个锁，并且崩溃了，那么这个DB将永远处于锁定状态。这就是问题所在。并不是其他进程有锁。

在选择重新启动选项之前，有必要看看能否找到sqlite数据库的用户。

在Linux上，可以使用fuser:

$ fuser database.db

$ fuser database.db-journal

在我的案例中，我得到了如下的回应:

philip    3556  4700  0 10:24 pts/3    00:00:01 /usr/bin/python manage.py shell

这表明我有另一个使用数据库的pid 3556 (manage.py)的Python程序。

应该是数据库的内部问题… 对我来说，这是在尝试用“SQLite管理器”浏览数据库后表现出来的… 所以，如果你找不到另一个连接到数据库的进程，你也无法修复它， 试试这个激进的解决方案:

提供导出您的表(您可以在Firefox上使用“SQLite管理器”) 如果迁移改变了数据库方案，请删除上次失败的迁移 重命名“数据库”。sqlite”文件 执行“rake db:migrate”创建一个新的工作数据库 提供给正确的权限数据库表的导入 导入备份的表 编写新的迁移 执行"rake db:migrate"

SQLite wiki DatabaseIsLocked页面提供了此错误消息的解释。在某种程度上，它指出争用的来源是内部的(对发出错误的进程而言)。本页没有解释的是SQLite如何决定进程中的某些东西持有锁，以及哪些条件会导致误报。

当您试图从同一个数据库连接同时对数据库执行两项不兼容的操作时，就会出现此错误代码。

在v3中引入的有关文件锁定的变化可能对未来的读者有用，可以在这里找到:SQLite版本3中的文件锁定和并发性

我也有同样的问题。显然，回滚函数似乎用与db文件相同但没有最近更改的日志覆盖了db文件。我已经在下面的代码中实现了这一点，从那时起它一直工作得很好，而之前我的代码会因为数据库保持锁定而陷入循环。

希望这能有所帮助

我的python代码

##############
#### Defs ####
##############
def conn_exec( connection , cursor , cmd_str ):
    done        = False
    try_count   = 0.0
    while not done:
        try:
            cursor.execute( cmd_str )
            done = True
        except sqlite.IntegrityError:
            # Ignore this error because it means the item already exists in the database
            done = True
        except Exception, error:
            if try_count%60.0 == 0.0:       # print error every minute
                print "\t" , "Error executing command" , cmd_str
                print "Message:" , error

            if try_count%120.0 == 0.0:      # if waited for 2 miutes, roll back
                print "Forcing Unlock"
                connection.rollback()

            time.sleep(0.05)    
            try_count += 0.05


def conn_comit( connection ):
    done        = False
    try_count   = 0.0
    while not done:
        try:
            connection.commit()
            done = True
        except sqlite.IntegrityError:
            # Ignore this error because it means the item already exists in the database
            done = True
        except Exception, error:
            if try_count%60.0 == 0.0:       # print error every minute
                print "\t" , "Error executing command" , cmd_str
                print "Message:" , error

            if try_count%120.0 == 0.0:      # if waited for 2 miutes, roll back
                print "Forcing Unlock"
                connection.rollback()

            time.sleep(0.05)    
            try_count += 0.05       




##################
#### Run Code ####
##################
connection = sqlite.connect( db_path )
cursor = connection.cursor()
# Create tables if database does not exist
conn_exec( connection , cursor , '''CREATE TABLE IF NOT EXISTS fix (path TEXT PRIMARY KEY);''')
conn_exec( connection , cursor , '''CREATE TABLE IF NOT EXISTS tx (path TEXT PRIMARY KEY);''')
conn_exec( connection , cursor , '''CREATE TABLE IF NOT EXISTS completed (fix DATE, tx DATE);''')
conn_comit( connection )