我想从一个MySQL数据库的所有表的所有字段搜索一个给定的字符串,可能使用语法为:
SELECT * FROM * WHERE * LIKE '%stuff%'
有可能做这样的事情吗?
我想从一个MySQL数据库的所有表的所有字段搜索一个给定的字符串,可能使用语法为:
SELECT * FROM * WHERE * LIKE '%stuff%'
有可能做这样的事情吗?
当前回答
虽然这个问题已经很老了,但如果你使用的是mysql workbench 6.3,你可以这样做。(很可能它也适用于其他版本)
右键点击你的模式和“搜索表数据”,输入你的值,然后点击“开始搜索”。这是它。
其他回答
这是我知道的最简单的方法。 在PHPMyAdmin中选择你的DB,然后转到“搜索”选项卡,写下你想要找到的内容以及你要搜索的位置。如果要从所有表中搜索单词,则选择所有表。然后“开始”,看看结果。
PHP函数:
function searchAllDB($search){
global $mysqli;
$out = Array();
$sql = "show tables";
$rs = $mysqli->query($sql);
if($rs->num_rows > 0){
while($r = $rs->fetch_array()){
$table = $r[0];
$sql_search = "select * from `".$table."` where ";
$sql_search_fields = Array();
$sql2 = "SHOW COLUMNS FROM `".$table."`";
$rs2 = $mysqli->query($sql2);
if($rs2->num_rows > 0){
while($r2 = $rs2->fetch_array()){
$column = $r2[0];
$sql_search_fields[] = "`".$column."` like('%".$mysqli->real_escape_string($search)."%')";
}
$rs2->close();
}
$sql_search .= implode(" OR ", $sql_search_fields);
$rs3 = $mysqli->query($sql_search);
$out[$table] = $rs3->num_rows."\n";
if($rs3->num_rows > 0){
$rs3->close();
}
}
$rs->close();
}
return $out;
}
print_r(searchAllDB("search string"));
使用MySQL Workbench可以很容易地选择几个表,并在所有这些数据库表中搜索文本;-)
这个解决方案 a)只有MySQL,不需要其他语言,并且 b)返回SQL结果,准备处理!
#Search multiple database tables and/or columns
#Version 0.1 - JK 2014-01
#USAGE: 1. set the search term @search, 2. set the scope by adapting the WHERE clause of the `information_schema`.`columns` query
#NOTE: This is a usage example and might be advanced by setting the scope through a variable, putting it all in a function, and so on...
#define the search term here (using rules for the LIKE command, e.g % as a wildcard)
SET @search = '%needle%';
#settings
SET SESSION group_concat_max_len := @@max_allowed_packet;
#ini variable
SET @sql = NULL;
#query for prepared statement
SELECT
GROUP_CONCAT("SELECT '",`TABLE_NAME`,"' AS `table`, '",`COLUMN_NAME`,"' AS `column`, `",`COLUMN_NAME`,"` AS `value` FROM `",TABLE_NAME,"` WHERE `",COLUMN_NAME,"` LIKE '",@search,"'" SEPARATOR "\nUNION\n") AS col
INTO @sql
FROM `information_schema`.`columns`
WHERE TABLE_NAME IN
(
SELECT TABLE_NAME FROM `information_schema`.`columns`
WHERE
TABLE_SCHEMA IN ("my_database")
&& TABLE_NAME IN ("my_table1", "my_table2") || TABLE_NAME LIKE "my_prefix_%"
);
#prepare and execute the statement
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
我要用这个。你只需要改变变量
$query ="SELECT `column_name` FROM `information_schema`.`columns` WHERE `table_schema`='" . $_SESSION['db'] . "' AND `table_name`='" . $table . "' ";
$stmt = $dbh->prepare($query);
$stmt->execute();
$columns = $stmt->fetchAll(PDO::FETCH_ASSOC);
$query="SELECT name FROM `" . $database . "`.`" . $table . "` WHERE ( ";
foreach ( $columns as $column ) {
$query .=" CONVERT( `" . $column['column_name'] . "` USING utf8 ) LIKE '%" . $search . "%' OR ";
}
$query = substr($query, 0, -3);
$query .= ")";
echo $query . "<br>";
$stmt=$dbh->prepare($query);
$stmt->execute();
$results = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo "<pre>";
print_r ($results );
echo "</pre>";