如何在我的路由中定义路由。jsx文件捕获__firebase_request_key参数值从一个URL生成的Twitter的单点登录过程后,从他们的服务器重定向?

http://localhost:8000/#/signin?_k=v9ifuf&__firebase_request_key=blablabla

我尝试了以下路由配置,但:redirectParam没有捕获提到的参数:

<Router>
  <Route path="/" component={Main}>
    <Route path="signin" component={SignIn}>
      <Route path=":redirectParam" component={TwitterSsoButton} />
    </Route>
  </Route>
</Router>

当前回答

你也可以使用react-location-query包,例如:

  const [name, setName] = useLocationField("name", {
    type: "string",
    initial: "Rostyslav"
  });

  return (
    <div className="App">
      <h1>Hello {name}</h1>
      <div>
        <label>Change name: </label>
        <input value={name} onChange={e => setName(e.target.value)} />
      </div>
    </div>
  );

名称-获取价值 setName =设置值

这个包有很多选项,在Github上的文档中阅读更多

其他回答

也许有人可以帮助解释为什么,但如果你试图从App.js页面上的新安装的Create React App中点击props来查找位置,你会得到:

无法读取未定义的属性“搜索”

即使我有App.js作为主路径:

<Route exact path='/' render={props => (

只在App.js上,使用window。地点对我来说很合适:

import queryString from 'query-string';
...
const queryStringParams = queryString.parse(window.location.search);

你可以使用这个用Typescript写的简单钩子:

const useQueryParams = (query: string = null) => {      
    const result: Record<string, string> = {};
    new URLSearchParams(query||window.location.search).forEach((value, key) => {
      result[key] = value;
    });
    return result;
}

用法:

// http://localhost:3000/?userId=1889&num=112
const { userId, num } = useQueryParams();
// OR
const params = useQueryParams('userId=1889&num=112');

你也可以使用react-location-query包,例如:

  const [name, setName] = useLocationField("name", {
    type: "string",
    initial: "Rostyslav"
  });

  return (
    <div className="App">
      <h1>Hello {name}</h1>
      <div>
        <label>Change name: </label>
        <input value={name} onChange={e => setName(e.target.value)} />
      </div>
    </div>
  );

名称-获取价值 setName =设置值

这个包有很多选项,在Github上的文档中阅读更多

当使用React钩子时,没有访问this.props.location的权限。 要获取url参数,请使用窗口对象。

const search = window.location.search;
const params = new URLSearchParams(search);
const foo = params.get('bar');

React路由器Dom V6 https://reactrouter.com/docs/en/v6/hooks/use-search-params

import * as React from "react";
import { useSearchParams } from "react-router-dom";

function App() {
  let [searchParams, setSearchParams] = useSearchParams();

  function handleSubmit(event) {
    event.preventDefault();
    // The serialize function here would be responsible for
    // creating an object of { key: value } pairs from the
    // fields in the form that make up the query.
    let params = serializeFormQuery(event.target);
    setSearchParams(params);
  }

  return (
    <div>
      <form onSubmit={handleSubmit}>{/* ... */}</form>
    </div>
  );
}

直到React路由器Dom V5

function useQueryParams() {
    const params = new URLSearchParams(
      window ? window.location.search : {}
    );

    return new Proxy(params, {
        get(target, prop) {
            return target.get(prop)
        },
    });
}

React钩子很棒

如果你的url看起来像/users?页面= 2数= 10字段=姓名、电子邮件、电话

// app.domain.com/users?page=2&count=10&fields=name,email,phone

const { page, fields, count, ...unknown } = useQueryParams();

console.log({ page, fields, count })
console.log({ unknown })

如果您的查询参数包含hyphone("-")或空格(" ") 然后你不能像{page, fields, count,…未知的}

你需要做传统的作业,比如

// app.domain.com/users?utm-source=stackOverFlow

const params = useQueryParams();

console.log(params['utm-source']);