在typescript中，参见下面的示例片段:

const getQueryParams = (s?: string): Map<string, string> => {
  if (!s || typeof s !== 'string' || s.length < 2) {
    return new Map();
  }

  const a: [string, string][] = s
    .substr(1) // remove `?`
    .split('&') // split by `&`
    .map(x => {
      const a = x.split('=');
      return [a[0], a[1]];
    }); // split by `=`

  return new Map(a);
};

在react中使用react-router-dom，你可以做

const {useLocation} from 'react-router-dom';
const s = useLocation().search;
const m = getQueryParams(s);

参见下面的例子

//下面是上面转换和缩小的ts函数 如果(const getQueryParams = t = > {! t | |“字符串”!=typeof t||t.length<2)return new Map;const r=t.substr(1).split("&")。地图(t = > {const r = t.split(" = ");返回[r[0],[1]]});返回新地图(r)}; //一个示例查询字符串 Const s = '?__arg1 = value1&arg2 = value2 ' getQueryParams(s) console.log (m.get (__arg1)) console.log (m.get(最长)) Console.log (m.t get('arg3')) //不存在，返回undefined

React路由器v3

使用React Router v3，你可以从this.props.location.search (?qs1=naisarg&qs2=parmar)获取查询字符串。例如，使用let params = queryString.parse(this.props.location.search)，将给出{qs1: 'naisarg'， qs2: 'parmar'}

React路由器v4

在React Router v4中，this.props.location.query不再存在。您需要使用this.props.location.search，并自己或使用现有的包(如query-string)解析查询参数。

例子

下面是一个使用React Router v4和query-string库的最小示例。

import { withRouter } from 'react-router-dom';
import queryString from 'query-string';
    
class ActivateAccount extends Component{
    someFunction(){
        let params = queryString.parse(this.props.location.search)
        ...
    }
    ...
}
export default withRouter(ActivateAccount);

理性的

React Router团队移除query属性的理由是:

There are a number of popular packages that do query string parsing/stringifying slightly differently, and each of these differences might be the "correct" way for some users and "incorrect" for others. If React Router picked the "right" one, it would only be right for some people. Then, it would need to add a way for other users to substitute in their preferred query parsing package. There is no internal use of the search string by React Router that requires it to parse the key-value pairs, so it doesn't have a need to pick which one of these should be "right". [...] The approach being taken for 4.0 is to strip out all the "batteries included" kind of features and get back to just basic routing. If you need query string parsing or async loading or Redux integration or something else very specific, then you can add that in with a library specifically for your use case. Less cruft is packed in that you don't need and you can customize things to your specific preferences and needs.

你可以在GitHub上找到完整的讨论。

如果你的路由器是这样的

<Route exact path="/category/:id" component={ProductList}/>

你会得到这样的id

this.props.match.params.id

我花了很长时间才解决这个问题。如果以上都不行，你可以试试这个。我正在使用创建-反应应用程序

需求

react-router-dom ^ 4.3.1“:

解决方案

在指定路由器的位置

<Route path="some/path" ..../>

像这样添加您想要传入的参数名

<Route path="some/path/:id" .../>

在你渲染一些/路径的页面上，你可以指定这个来查看参数名调用id，就像这样

componentDidMount(){
  console.log(this.props);
  console.log(this.props.match.params.id);
}

在导出默认值的最后

export default withRouter(Component);

记住要包含import

import { withRouter } from 'react-router-dom'

当console.log(this.props)时，你就可以知道传递了什么。玩得开心!

我使用了一个名为query-string的外部包来解析url参数，如下所示。

import React, {Component} from 'react'
import { parse } from 'query-string';

resetPass() {
    const {password} = this.state;
    this.setState({fetching: true, error: undefined});
    const query = parse(location.search);
    return fetch(settings.urls.update_password, {
        method: 'POST',
        headers: {'Content-Type': 'application/json', 'Authorization': query.token},
        mode: 'cors',
        body: JSON.stringify({password})
    })
        .then(response=>response.json())
        .then(json=>{
            if (json.error)
                throw Error(json.error.message || 'Unknown fetch error');
            this.setState({fetching: false, error: undefined, changePassword: true});
        })
        .catch(error=>this.setState({fetching: false, error: error.message}));
}

React路由器5.1+

5.1引入了各种钩子，如useLocation和useParams，可以在这里使用。

例子:

<Route path="/test/:slug" component={Dashboard} />

如果我们去参观

http://localhost:3000/test/signin?_k=v9ifuf&__firebase_request_key=blablabla

你可以把它找回来

import { useLocation } from 'react-router';
import queryString from 'query-string';

const Dashboard: React.FC = React.memo((props) => {
    const location = useLocation();

    console.log(queryString.parse(location.search));

    // {__firebase_request_key: "blablabla", _k: "v9ifuf"}

    ...

    return <p>Example</p>;
}