当使用React钩子时，没有访问this.props.location的权限。 要获取url参数，请使用窗口对象。

const search = window.location.search;
const params = new URLSearchParams(search);
const foo = params.get('bar');

如果你没有得到这个。道具…根据其他答案，您可能需要使用withthrouter (docs v4):

import React from 'react'
import PropTypes from 'prop-types'
import { withRouter } from 'react-router'

// A simple component that shows the pathname of the current location
class ShowTheLocation extends React.Component {
  static propTypes = {
    match: PropTypes.object.isRequired,
    location: PropTypes.object.isRequired,
    history: PropTypes.object.isRequired
  }

  render() {
    const { match, location, history } = this.props

    return (
      <div>You are now at {location.pathname}</div>
    )
  }
}

// Create a new component that is "connected" (to borrow redux terminology) to the router.  
const TwitterSsoButton = withRouter(ShowTheLocation)  

// This gets around shouldComponentUpdate
withRouter(connect(...)(MyComponent))

// This does not
connect(...)(withRouter(MyComponent))

如果你的路由器是这样的

<Route exact path="/category/:id" component={ProductList}/>

你会得到这样的id

this.props.match.params.id

React路由器v6

来源:在React路由器中获取查询字符串(搜索参数)

使用新的useSearchParams钩子和.get()方法:

const Users = () => {
  const [searchParams] = useSearchParams();
  console.log(searchParams.get('sort')); // 'name'

  return <div>Users</div>;
};

使用这种方法，您可以读取一个或几个参数。

将参数作为一个对象:

如果你需要一次性获得所有的查询字符串参数，那么我们可以像这样使用Object.fromEntries:

const Users = () => {
  const [searchParams] = useSearchParams();
  console.log(Object.fromEntries([...searchParams])); // ▶ { sort: 'name', order: 'asecnding' }
  return <div>Users</div>;
};

阅读更多和现场演示:在React路由器中获取查询字符串(搜索参数)

有了这一行代码，你可以在React Hook和React Class Component的任何地方使用它。

https://www.hunterisgod.com/?city=Leipzig

let city = (new URLSearchParams(window.location.search)).get("city")

在typescript中，参见下面的示例片段:

const getQueryParams = (s?: string): Map<string, string> => {
  if (!s || typeof s !== 'string' || s.length < 2) {
    return new Map();
  }

  const a: [string, string][] = s
    .substr(1) // remove `?`
    .split('&') // split by `&`
    .map(x => {
      const a = x.split('=');
      return [a[0], a[1]];
    }); // split by `=`

  return new Map(a);
};

在react中使用react-router-dom，你可以做

const {useLocation} from 'react-router-dom';
const s = useLocation().search;
const m = getQueryParams(s);

参见下面的例子

//下面是上面转换和缩小的ts函数 如果(const getQueryParams = t = > {! t | |“字符串”!=typeof t||t.length<2)return new Map;const r=t.substr(1).split("&")。地图(t = > {const r = t.split(" = ");返回[r[0],[1]]});返回新地图(r)}; //一个示例查询字符串 Const s = '?__arg1 = value1&arg2 = value2 ' getQueryParams(s) console.log (m.get (__arg1)) console.log (m.get(最长)) Console.log (m.t get('arg3')) //不存在，返回undefined