我正在尝试从一个“活动”发送客户类的对象,并在另一个“”中显示它。

客户类别的代码:

public class Customer {

    private String firstName, lastName, address;
    int age;

    public Customer(String fname, String lname, int age, String address) {

        firstName = fname;
        lastName = lname;
        age = age;
        address = address;
    }

    public String printValues() {

        String data = null;

        data = "First Name :" + firstName + " Last Name :" + lastName
        + " Age : " + age + " Address : " + address;

        return data;
    }
}

我想将其对象从一个“活动”发送到另一个“,然后在另一个活动”上显示数据。

我怎样才能做到这一点?


当前回答

不可能序列化任何类型的对象。例如,不能序列化携带代码而不是数据的委托方法或接口。因此,我编写了一个“Box”类,您可以使用它来传递任何类型的数据,而无需序列化。

1-将数据用于预期用途:

Intent I = new Intent(this, YourActivity.class);
CustomClass Date = new CustomClass();
Box.Add(I, "Name", Data);

2-用于从意向检索数据:

CustomClass Data = Box.Get(getIntent(), "Name");

3-要在使用后删除数据,请将此方法添加到活动中:

@Override
protected void onDestroy() {
    Box.Remove(getIntent());
    super.onDestroy();
}

4-并将此代码添加到项目中:

package ir.namirasoft.Utility;

import android.content.Intent;

import java.util.HashMap;
import java.util.Vector;

public class Box {
    // Number
    private static int Number = 1;

    public static int NextNumber() {
        return Number++;
    }

    //
    private static String _Intent_Identifier = "_Intent_Identifier";
    private static HashMap<Integer, Vector<Integer>> DeleteList = new HashMap<Integer, Vector<Integer>>();
    private static HashMap<Integer, HashMap<String, Object>> ObjectList = new HashMap<Integer, HashMap<String, Object>>();

    public static int GetIntent_Identifier(Intent I) {
        int Intent_Identifier = I.getIntExtra(_Intent_Identifier, 0);
        if (Intent_Identifier == 0)
            I.putExtra(_Intent_Identifier, Intent_Identifier = NextNumber());
        return Intent_Identifier;
    }

    public static void Add(Intent I, String Name, Object O) {
        int Intent_Identifier = GetIntent_Identifier(I);
        synchronized (ObjectList) {
            if (!ObjectList.containsKey(Intent_Identifier))
                ObjectList.put(Intent_Identifier, new HashMap<String, Object>());
            ObjectList.get(Intent_Identifier).put(Name, O);
        }
    }

    public static <T> T Get(Intent I, String Name) {
        int Intent_Identifier = GetIntent_Identifier(I);
        synchronized (DeleteList) {
            DeleteList.remove(Intent_Identifier);
        }
        return (T) ObjectList.get(Intent_Identifier).get(Name);
    }

    public static void Remove(final Intent I) {
        final int Intent_Identifier = GetIntent_Identifier(I);
        final int ThreadID = NextNumber();
        synchronized (DeleteList) {
            if (!DeleteList.containsKey(Intent_Identifier))
                DeleteList.put(Intent_Identifier, new Vector<Integer>());
            DeleteList.get(Intent_Identifier).add(ThreadID);
        }
        new Thread(new Runnable() {
            @Override
            public void run() {
                try {
                    Thread.sleep(60 * 1000);
                } catch (InterruptedException e) {
                }
                synchronized (DeleteList) {
                    if (DeleteList.containsKey(Intent_Identifier))
                        if (DeleteList.get(Intent_Identifier).contains(ThreadID))
                            synchronized (ObjectList) {
                                ObjectList.remove(Intent_Identifier);
                            }
                }
            }
        }).start();
    }
}

**Box类是线程安全的。

其他回答

使用gson将对象转换为JSON并通过intent传递。在新的Activity中,将JSON转换为对象。

在build.gradle中,将其添加到依赖项中

implementation 'com.google.code.gson:gson:2.8.4'

在“活动”中,将对象转换为json字符串:

Gson gson = new Gson();
String myJson = gson.toJson(vp);
intent.putExtra("myjson", myjson);

在接收活动中,将json字符串转换回原始对象:

Gson gson = new Gson();
YourObject ob = gson.fromJson(getIntent().getStringExtra("myjson"), YourObject.class);

对于Kotlin来说,这是完全一样的

传递数据

val gson = Gson()
val intent = Intent(this, YourActivity::class.java)
intent.putExtra("identifier", gson.toJson(your_object))
startActivity(intent)

接收数据

val gson = Gson()
val yourObject = gson.fromJson<YourObject>(intent.getStringExtra("identifier"), YourObject::class.java)

像这样创建自定义类:

public class Test implements Parcelable {
    String message;

    protected Test(Parcel in) {
        message = in.readString();
    }

    public static final Creator<Test> CREATOR = new Creator<Test>() {
        @Override
        public Test createFromParcel(Parcel in) {
            return new Test(in);
        }

        @Override
        public Test[] newArray(int size) {
            return new Test[size];
        }
    };

    public String getMessage() {
        return message;
    }

    @Override
    public int describeContents() {
        return 0;
    }

    @Override
    public void writeToParcel(Parcel dest, int flags) {
        dest.writeString(message);
    }

使用Intent发送数据,如下所示:开始活动之前,必须设置一些数据

Intent intent = new Intent(context, PostDetailsActivity.class);
                intent.putExtra("data", (Parcelable) test);
                ((context)).startActivity(intent);

从以下意图中获取数据:

Test test = (Test) getIntent().getParcelableExtra("data");

调用活动时

Intent intent = new Intent(fromClass.this,toClass.class).putExtra("myCustomerObj",customerObj);

在toClass.java中,通过

Customer customerObjInToClass = getIntent().getExtras().getParcelable("myCustomerObj");

请确保客户类实现parcelable

public class Customer implements Parcelable {

    private String firstName, lastName, address;
    int age;

    /* all your getter and setter methods */

    public Customer(Parcel in ) {
        readFromParcel( in );
    }

    public static final Parcelable.Creator CREATOR = new Parcelable.Creator() {
        public LeadData createFromParcel(Parcel in ) {
            return new Customer( in );
        }

        public Customer[] newArray(int size) {
            return new Customer[size];
        }
    };


    @Override
    public void writeToParcel(Parcel dest, int flags) {

        dest.writeString(firstName);
        dest.writeString(lastName);
        dest.writeString(address);
        dest.writeInt(age);
    }

    private void readFromParcel(Parcel in ) {

        firstName = in .readString();
        lastName  = in .readString();
        address   = in .readString();
        age       = in .readInt();
    }

是的,使用静态对象是迄今为止使用自定义非串行对象实现这一点的最简单方法。

最好的方法是在应用程序中有一个类(称为Control),该类将保存类型为“Customer”的静态变量(在您的情况下)。初始化活动A中的变量。

例如:

Control.Customer = CustomerClass;

然后转到Activity B并从Control类获取它。使用变量后不要忘记赋值null,否则会浪费内存。