我有一本嵌套的字典。是否只有一种方法可以安全地传递价值观?
try:
example_dict['key1']['key2']
except KeyError:
pass
或者python有一个类似get()的方法用于嵌套字典?
我有一本嵌套的字典。是否只有一种方法可以安全地传递价值观?
try:
example_dict['key1']['key2']
except KeyError:
pass
或者python有一个类似get()的方法用于嵌套字典?
当前回答
你可以使用pydash:
import pydash as _ #NOTE require `pip install pydash`
_.get(example_dict, 'key1.key2', default='Default')
https://pydash.readthedocs.io/en/latest/api.html
其他回答
对于二级键检索,你可以这样做:
key2_value = (example_dict.get('key1') or {}).get('key2')
通过把所有这些答案和我做的小改变结合起来,我认为这个函数会很有用。安全、快捷、易于维护。
def deep_get(dictionary, keys, default=None):
return reduce(lambda d, key: d.get(key, default) if isinstance(d, dict) else default, keys.split("."), dictionary)
例子:
from functools import reduce
def deep_get(dictionary, keys, default=None):
return reduce(lambda d, key: d.get(key, default) if isinstance(d, dict) else default, keys.split("."), dictionary)
person = {'person':{'name':{'first':'John'}}}
print(deep_get(person, "person.name.first")) # John
print(deep_get(person, "person.name.lastname")) # None
print(deep_get(person, "person.name.lastname", default="No lastname")) # No lastname
我改编了GenesRus和unutbu的答案,非常简单:
class new_dict(dict):
def deep_get(self, *args, default=None):
_empty_dict = {}
out = self
for key in args:
out = out.get(key, _empty_dict)
return out if out else default
它适用于:
d = new_dict(some_data)
d.deep_get("key1", "key2", "key3", ..., default=some_value)
虽然reduce方法简洁而简短,但我认为简单的循环更容易理解。我还包含了一个默认参数。
def deep_get(_dict, keys, default=None):
for key in keys:
if isinstance(_dict, dict):
_dict = _dict.get(key, default)
else:
return default
return _dict
作为理解reduce一行程序如何工作的练习,我执行了以下操作。但最终循环方法对我来说似乎更直观。
def deep_get(_dict, keys, default=None):
def _reducer(d, key):
if isinstance(d, dict):
return d.get(key, default)
return default
return reduce(_reducer, keys, _dict)
使用
nested = {'a': {'b': {'c': 42}}}
print deep_get(nested, ['a', 'b'])
print deep_get(nested, ['a', 'b', 'z', 'z'], default='missing')
减少方法的改进很少,使其与列表一起工作。也使用数据路径作为字符串除以点,而不是数组。
def deep_get(dictionary, path):
keys = path.split('.')
return reduce(lambda d, key: d[int(key)] if isinstance(d, list) else d.get(key) if d else None, keys, dictionary)