假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
当前回答
这直接提供了一个分割部分的数组
var fullNameArr = fullName.components(separatedBy:" ")
那么你可以这样使用,
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
其他回答
这里是我刚刚构建的一个算法,它将通过数组中的任何字符分割字符串,如果有任何希望保留具有分割字符的子字符串,可以将swall参数设置为true。
Xcode 7.3-Swift 2.2:
extension String {
func splitBy(characters: [Character], swallow: Bool = false) -> [String] {
var substring = ""
var array = [String]()
var index = 0
for character in self.characters {
if let lastCharacter = substring.characters.last {
// swallow same characters
if lastCharacter == character {
substring.append(character)
} else {
var shouldSplit = false
// check if we need to split already
for splitCharacter in characters {
// slit if the last character is from split characters or the current one
if character == splitCharacter || lastCharacter == splitCharacter {
shouldSplit = true
break
}
}
if shouldSplit {
array.append(substring)
substring = String(character)
} else /* swallow characters that do not equal any of the split characters */ {
substring.append(character)
}
}
} else /* should be the first iteration */ {
substring.append(character)
}
index += 1
// add last substring to the array
if index == self.characters.count {
array.append(substring)
}
}
return array.filter {
if swallow {
return true
} else {
for splitCharacter in characters {
if $0.characters.contains(splitCharacter) {
return false
}
}
return true
}
}
}
}
例子:
"test text".splitBy([" "]) // ["test", "text"]
"test++text--".splitBy(["+", "-"], swallow: true) // ["test", "++" "text", "--"]
根据Swift 2.2
您只需编写2行代码,就会得到拆分字符串。
let fullName = "FirstName LastName"
var splitedFullName = fullName.componentsSeparatedByString(" ")
print(splitedFullName[0])
print(splitedFullName[1])
享受。:)
您可以使用此公共函数并添加任何要分隔的字符串
func separateByString(String wholeString: String, byChar char:String) -> [String] {
let resultArray = wholeString.components(separatedBy: char)
return resultArray
}
var fullName: String = "First Last"
let array = separateByString(String: fullName, byChar: " ")
var firstName: String = array[0]
var lastName: String = array[1]
print(firstName)
print(lastName)
雨燕3
let line = "AAA BBB\t CCC"
let fields = line.components(separatedBy: .whitespaces).filter {!$0.isEmpty}
返回三个字符串AAA、BBB和CCC筛选出空字段处理多个空格和制表字符如果要处理新行,请将.whittespaces替换为.whittespace和新行
Swift 5.2的更新和最简单的方式
let paragraph = "Bob hit a ball, the hit BALL flew far after it was hit. Hello! Hie, How r u?"
let words = paragraph.components(separatedBy: [",", " ", "!",".","?"])
这张照片,
[“Bob”,“hit”,“a”,“ball”,“the”,“击球”,“ball”,“fly”,“far”,“after”,“it”,“was”,“hit”,“Hello”,“Hie”,“How”,“u”,“”]
但是,如果要过滤空字符串,
let words = paragraph.components(separatedBy: [",", " ", "!",".","?"]).filter({!$0.isEmpty})
输出
[“Bob”,“hit”,“a”,“ball”,“the”,“命中”,“ball”,“fly”,“far”,“after”,“it”,“was”,“hit”,“Hello”,”Hie“,”How“,”r“,”u“]
但请确保,Foundation已导入。