假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
当前回答
非顶部:
对于搜索如何使用子字符串(而不是字符)拆分字符串的人来说,下面是一个有效的解决方案:
// TESTING
let str1 = "Hello user! What user's details? Here user rounded with space."
let a = str1.split(withSubstring: "user") // <-------------- HERE IS A SPLIT
print(a) // ["Hello ", "! What ", "\'s details? Here ", " rounded with space."]
// testing the result
var result = ""
for item in a {
if !result.isEmpty {
result += "user"
}
result += item
}
print(str1) // "Hello user! What user's details? Here user rounded with space."
print(result) // "Hello user! What user's details? Here user rounded with space."
print(result == str1) // true
/// Extension providing `split` and `substring` methods.
extension String {
/// Split given string with substring into array
/// - Parameters:
/// - string: the string
/// - substring: the substring to search
/// - Returns: array of components
func split(withSubstring substring: String) -> [String] {
var a = [String]()
var str = self
while let range = str.range(of: substring) {
let i = str.distance(from: str.startIndex, to: range.lowerBound)
let j = str.distance(from: str.startIndex, to: range.upperBound)
let left = str.substring(index: 0, length: i)
let right = str.substring(index: j, length: str.length - j)
a.append(left)
str = right
}
if !str.isEmpty {
a.append(str)
}
return a
}
/// the length of the string
public var length: Int {
return self.count
}
/// Get substring, e.g. "ABCDE".substring(index: 2, length: 3) -> "CDE"
///
/// - parameter index: the start index
/// - parameter length: the length of the substring
///
/// - returns: the substring
public func substring(index: Int, length: Int) -> String {
if self.length <= index {
return ""
}
let leftIndex = self.index(self.startIndex, offsetBy: index)
if self.length <= index + length {
return String(self[leftIndex..<self.endIndex])
}
let rightIndex = self.index(self.endIndex, offsetBy: -(self.length - index - length))
return String(self[leftIndex..<rightIndex])
}
}
其他回答
最简单的解决方案是
let fullName = "First Last"
let components = fullName.components(separatedBy: .whitespacesAndNewlines).compactMap { $0.isEmpty ? nil : $0 }
这将处理不同类型的一行中的多个空格(空格、制表符、换行符等),并且只返回一个两元素数组,您可以更改CharacterSet以包含更多您喜欢的字符,如果您想获得切割符,可以使用正则表达式解码器,这允许您编写正则表达式,该表达式可用于将字符串直接解码到实现解码协议的自己的类/结构中。对于像这样的东西来说,这是过度的,但如果您将其用作更复杂字符串的示例,则可能更有意义。
作为WMios答案的替代方案,您还可以使用componentsSeparatedByCharactersSet,这在分隔符(空格、逗号等)较多的情况下非常方便。
使用您的特定输入:
let separators = NSCharacterSet(charactersInString: " ")
var fullName: String = "First Last";
var words = fullName.componentsSeparatedByCharactersInSet(separators)
// words contains ["First", "Last"]
使用多个分隔符:
let separators = NSCharacterSet(charactersInString: " ,")
var fullName: String = "Last, First Middle";
var words = fullName.componentsSeparatedByCharactersInSet(separators)
// words contains ["Last", "First", "Middle"]
或者没有闭包,你可以在Swift 2中这样做:
let fullName = "First Last"
let fullNameArr = fullName.characters.split(" ")
let firstName = String(fullNameArr[0])
只需在fullName上调用componentsSeparatedByString方法
import Foundation
var fullName: String = "First Last"
let fullNameArr = fullName.componentsSeparatedByString(" ")
var firstName: String = fullNameArr[0]
var lastName: String = fullNameArr[1]
Swift 3更新+
import Foundation
let fullName = "First Last"
let fullNameArr = fullName.components(separatedBy: " ")
let name = fullNameArr[0]
let surname = fullNameArr[1]
Swift的方法是使用全局拆分函数,如下所示:
var fullName = "First Last"
var fullNameArr = split(fullName) {$0 == " "}
var firstName: String = fullNameArr[0]
var lastName: String? = fullNameArr.count > 1 ? fullNameArr[1] : nil
使用Swift 2
在Swift 2中,由于引入了内部CharacterView类型,拆分的使用变得有点复杂。这意味着String不再采用SequenceType或CollectionType协议,您必须改为使用.characts属性来访问String实例的CharacterView类型表示。(注意:CharacterView确实采用SequenceType和CollectionType协议)。
let fullName = "First Last"
let fullNameArr = fullName.characters.split{$0 == " "}.map(String.init)
// or simply:
// let fullNameArr = fullName.characters.split{" "}.map(String.init)
fullNameArr[0] // First
fullNameArr[1] // Last