假设我这里有一个字符串：
var fullName: String = "First Last"
我想在空白处拆分字符串，并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外，有时用户可能没有姓氏。
当前回答
斯威夫特4
let string = "loremipsum.dolorsant.amet:"
let result = string.components(separatedBy: ".")
print(result[0])
print(result[1])
print(result[2])
print("total: \(result.count)")
输出
loremipsum
dolorsant
amet:
total: 3
其他回答
Swift 4使拆分字符变得更加容易，只需为字符串使用新的拆分函数即可。
例子：让s=“嗨，你好”让a=s.split（分隔符：“，”）打印（a）
现在您得到了一个带有“hi”和“hello”的数组。
或者没有闭包，你可以在Swift 2中这样做：
let fullName = "First Last"
let fullNameArr = fullName.characters.split(" ")
let firstName = String(fullNameArr[0])
这里是我刚刚构建的一个算法，它将通过数组中的任何字符分割字符串，如果有任何希望保留具有分割字符的子字符串，可以将swall参数设置为true。
Xcode 7.3-Swift 2.2：
extension String {
func splitBy(characters: [Character], swallow: Bool = false) -> [String] {
var substring = ""
var array = [String]()
var index = 0
for character in self.characters {
if let lastCharacter = substring.characters.last {
// swallow same characters
if lastCharacter == character {
substring.append(character)
} else {
var shouldSplit = false
// check if we need to split already
for splitCharacter in characters {
// slit if the last character is from split characters or the current one
if character == splitCharacter || lastCharacter == splitCharacter {
shouldSplit = true
break
}
}
if shouldSplit {
array.append(substring)
substring = String(character)
} else /* swallow characters that do not equal any of the split characters */ {
substring.append(character)
}
}
} else /* should be the first iteration */ {
substring.append(character)
}
index += 1
// add last substring to the array
if index == self.characters.count {
array.append(substring)
}
}
return array.filter {
if swallow {
return true
} else {
for splitCharacter in characters {
if $0.characters.contains(splitCharacter) {
return false
}
}
return true
}
}
}
}
例子：
"test text".splitBy([" "]) // ["test", "text"]
"test++text--".splitBy(["+", "-"], swallow: true) // ["test", "++" "text", "--"]
作为WMios答案的替代方案，您还可以使用componentsSeparatedByCharactersSet，这在分隔符（空格、逗号等）较多的情况下非常方便。
使用您的特定输入：
let separators = NSCharacterSet(charactersInString: " ")
var fullName: String = "First Last";
var words = fullName.componentsSeparatedByCharactersInSet(separators)
// words contains ["First", "Last"]
使用多个分隔符：
let separators = NSCharacterSet(charactersInString: " ,")
var fullName: String = "Last, First Middle";
var words = fullName.componentsSeparatedByCharactersInSet(separators)
// words contains ["Last", "First", "Middle"]
在Swift 4中将字符串拆分为数组的步骤。
赋值字符串基于@spling。
注意：variableName.components（separatedBy:“split关键字”）
let fullName: String = "First Last @ triggerd event of the session by session storage @ it can be divided by the event of the trigger."
let fullNameArr = fullName.components(separatedBy: "@")
print("split", fullNameArr)
