在讨论了一些最重要的答案之后，我编写了另一个实现，它也可以处理一些边缘情况

function serialize(params, prefix) {                
    return Object.entries(params).reduce((acc, [key, value]) => {
        // remove whitespace from both sides of the key before encoding
        key = encodeURIComponent(key.trim());

        if (params.constructor === Array ) {
          key = `${prefix}[]`;
        } else if (params.constructor === Object) {
          key = (prefix ? `${prefix}[${key}]` : key);
        }

        /**
         *  - undefined and NaN values will be skipped automatically
         *  - value will be empty string for functions and null
         *  - nested arrays will be flattened
         */
        if (value === null || typeof value === 'function') {
            acc.push(`${key}=`);
        } else if (typeof value === 'object') {
            acc = acc.concat(serialize(value, key));
        } else if(['number', 'boolean', 'string'].includes(typeof value) && value === value) { // self-check to avoid NaN
            acc.push(`${key}=${encodeURIComponent(value)}`);
        }

        return acc;
    }, []);
}

function objectToQueryString(queryParameters) {
    return queryParameters ? serialize(queryParameters).join('&'): '';
}

let x = objectToQueryString({
    foo: 'hello world',
    bar: {
      blah: 123,
      list: [1, 2, 3],
        'nested array': [[4,5],[6,7]] // will be flattened
    },
    page: 1,
    limit: undefined, // field will be ignored
    check: false,
    max: NaN, // field will be ignored
    prop: null,
    ' key value': 'with spaces' // space in key will be trimmed out
});
  
console.log(x); // foo=hello%20world&bar[blah]=123&bar[list][]=1&bar[list][]=2&bar[list][]=3&bar[nested%20array][][]=4&bar[nested%20array][][]=5&bar[nested%20array][][]=6&bar[nested%20array][][]=7&page=1&check=false&prop=&key%20value=with%20spaces

这是一个开箱即用的。net后端解决方案。我已经采取了这个线程的主要答案，并更新它以适应我们的。net需求。

function objectToQuerystring(params) {
var result = '';

    function convertJsonToQueryString(data, progress, name) {
        name = name || '';
        progress = progress || '';
        if (typeof data === 'object') {
            Object.keys(data).forEach(function (key) {
                var value = data[key];
                if (name == '') {
                    convertJsonToQueryString(value, progress, key);
                } else {
                    if (isNaN(parseInt(key))) {
                        convertJsonToQueryString(value, progress, name + '.' + key);
                    } else {
                        convertJsonToQueryString(value, progress, name + '[' + key+ ']');
                    }
                }
            })
        } else {
            result = result ? result.concat('&') : result.concat('?');
            result = result.concat(`${name}=${data}`);
        }
    }

    convertJsonToQueryString(params);
    return result;
}

如果您想递归地转换嵌套对象，并且对象可能包含也可能不包含数组(数组可能包含对象或数组等)，那么解决方案就会变得稍微复杂一些。这就是我的尝试。

我还添加了一些选项，用于选择是否要为每个对象成员记录它位于主对象中的深度，以及选择是否要向来自已转换数组的成员添加标签。

理想情况下，您应该测试thing参数是否真的接收到对象或数组。

function thingToString(thing,maxDepth,recordLevel,markArrays){
    //thing: object or array to be recursively serialized
    //maxDepth (int or false):
    // (int) how deep to go with converting objects/arrays within objs/arrays
    // (false) no limit to recursive objects/arrays within objects/arrays
    //recordLevel (boolean):
    //  true - insert "(level 1)" before transcript of members at level one (etc)
    //  false - just 
    //markArrays (boolean):
    //  insert text to indicate any members that came from arrays
    var result = "";
    if (maxDepth !== false && typeof maxDepth != 'number') {maxDepth = 3;}
    var runningDepth = 0;//Keeps track how deep we're into recursion

    //First prepare the function, so that it can call itself recursively
    function serializeAnything(thing){
        //Set path-finder values
        runningDepth += 1;
        if(recordLevel){result += "(level " + runningDepth + ")";}

        //First convert any arrays to object so they can be processed
        if (thing instanceof Array){
            var realObj = {};var key;
            if (markArrays) {realObj['type'] = "converted array";}
            for (var i = 0;i < thing.length;i++){
                if (markArrays) {key = "a" + i;} else {key = i;}
                realObj[key] = thing[i];
            }
            thing = realObj;
            console.log('converted one array to ' + typeof realObj);
            console.log(thing);
        }

        //Then deal with it
        for (var member in thing){
            if (typeof thing[member] == 'object' && runningDepth < maxDepth){
                serializeAnything(thing[member]);
                //When a sub-object/array is serialized, it will add one to
                //running depth. But when we continue to this object/array's
                //next sibling, the level must go back up by one
                runningDepth -= 1;
            } else if (maxDepth !== false && runningDepth >= maxDepth) {
                console.log('Reached bottom');
            } else 
            if (
                typeof thing[member] == "string" || 
                typeof thing[member] == 'boolean' ||
                typeof thing[member] == 'number'
            ){
                result += "(" + member + ": " + thing[member] + ") ";
            }  else {
                result += "(" + member + ": [" + typeof thing[member] + " not supported]) ";
            }
        }
    }
    //Actually kick off the serialization
    serializeAnything(thing);

    return result;

}

对用户187291接受的解决方案的一个小修改:

serialize = function(obj) {
   var str = [];
   for(var p in obj){
       if (obj.hasOwnProperty(p)) {
           str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
       }
   }
   return str.join("&");
}

检查对象上的hasOwnProperty使JSLint和JSHint高兴，它防止意外序列化对象的方法或其他东西，如果对象不是一个简单的字典。有关JavaScript编程语言的代码约定的语句，请参阅上一段。

好吧，似乎每个人都把他的俏皮话写在这里，所以我的是:

const encoded = Object.entries(obj).map(([k, v]) => `${k}=${encodeURIComponent(v)}`).join("&");

在ES7中，你可以用一行写:

const serialize = (obj) => (Object.entries(obj).map(i => [i[0], encodeURIComponent(i[1])].join('=')).join('&'))