下面是一个简单的实现，获取一个对象并将其转换为查询参数字符串:

export function objectToQueryParams(queryParams: object): string {
  return queryParams ?
    Object.entries(queryParams).reduce((acc, [key, val], index) => {
      const sign = index === 0 ? '?' : '&';
      acc += `${sign}${encodeURIComponent(key)}=${encodeURIComponent(val)}`;
      return acc;
    }, '')
    : '';
}

下面是ES6中的一行代码:

Object.keys(obj).map(k => `${encodeURIComponent(k)}=${encodeURIComponent(obj[k])}`).join('&');

 let data = {
    id:1,
    name:'Newuser'
    };
const getqueryParam = data => {
  let datasize = Object.keys(data).length;
  let initial = '?';

  Object.keys(data).map(function (key, index) {
    initial = initial.concat(`${key}=${data[key]}`);
    index != datasize - 1 && (initial = initial.concat('&'));
  });
  console.log(initial, 'MyqueryString');
  return initial;
};

console.log(getqueryParam(data))//You can get the query string here

If you have baseUrl means to get full query use 

baseUrl concat (getqueryParam(数据)。

这个函数跳过null/undefined值

export function urlEncodeQueryParams(data) {
    const params = Object.keys(data).map(key => data[key] ? `${encodeURIComponent(key)}=${encodeURIComponent(data[key])}` : '');
    return params.filter(value => !!value).join('&');
}

const serialize = obj => Object.keys(obj).reduce((a, b) =>
    a.push(encodeURIComponent(b) + "=" + encodeURIComponent(obj[b])) && a,
    []).join("&");

电话:

console.log(serialize({a:1,b:2}));
// output: 'a=1&b=2

'

还有一个很受欢迎的图书馆，qs。您可以通过以下方式添加:

yarn add qs

然后像这样使用它:

import qs from 'qs'

const array = { a: { b: 'c' } }
const stringified = qs.stringify(array, { encode: false })

console.log(stringified) //-- outputs a[b]=c