创建单实例WPF应用程序的正确方法是什么?

在。net下使用c#和WPF(而不是Windows窗体或控制台)，创建一个只能作为单个实例运行的应用程序的正确方法是什么?

我知道它与某种叫做互斥的神秘事物有关，我很少能找到有人费心停下来解释其中一个是什么。

代码还需要通知已经运行的实例，用户试图启动第二个实例，如果存在命令行参数，还可能传递任何命令行参数。

当前回答

更新2017-01-25。在尝试了一些东西之后，我决定使用VisualBasic.dll，它更容易，工作效果更好(至少对我来说)。我让我之前的答案只是作为参考…

只是作为参考，这是我如何不传递参数(我找不到任何理由这样做…我指的是带有参数的单个应用程序，这些参数可以从一个实例传递到另一个实例)。如果需要文件关联，那么应用程序应该(根据用户的标准期望)为每个文档实例化。如果你必须传递args到现有的应用程序，我想我会使用vb dll。

不传递参数(只是单实例应用程序)，我更喜欢不注册一个新的窗口消息，不覆盖Matt Davis解决方案中定义的消息循环。虽然添加一个VisualBasic dll不是一个大问题，但我不喜欢添加一个新的引用只是做单个实例应用程序。此外，我更喜欢用Main实例化一个新类，而不是调用Shutdown from app. startup重写以确保尽快退出。

希望大家都喜欢……或者会启发一点:-)

项目启动类应该设置为“SingleInstanceApp”。

public class SingleInstanceApp
{
    [STAThread]
    public static void Main(string[] args)
    {
        Mutex _mutexSingleInstance = new Mutex(true, "MonitorMeSingleInstance");

        if (_mutexSingleInstance.WaitOne(TimeSpan.Zero, true))
        {
            try
            {
                var app = new App();
                app.InitializeComponent();
                app.Run();

            }
            finally
            {
                _mutexSingleInstance.ReleaseMutex();
                _mutexSingleInstance.Close();
            }
        }
        else
        {
            MessageBox.Show("One instance is already running.");

            var processes = Process.GetProcessesByName(Assembly.GetEntryAssembly().GetName().Name);
            {
                if (processes.Length > 1)
                {
                    foreach (var process in processes)
                    {
                        if (process.Id != Process.GetCurrentProcess().Id)
                        {
                            WindowHelper.SetForegroundWindow(process.MainWindowHandle);
                        }
                    }
                }
            }
        }
    }
}

WindowHelper:

using System;
using System.Runtime.InteropServices;
using System.Windows;
using System.Windows.Interop;
using System.Windows.Threading;

namespace HQ.Util.Unmanaged
{
    public class WindowHelper
    {
        [DllImport("user32.dll")]
        [return: MarshalAs(UnmanagedType.Bool)]
        public static extern bool SetForegroundWindow(IntPtr hWnd);

2013-12-05 23:00:54

其他回答

这段代码应该转到main方法。关于WPF中main方法的更多信息，请参阅这里。

[DllImport("user32.dll")]
private static extern Boolean ShowWindow(IntPtr hWnd, Int32 nCmdShow);

private const int SW_SHOWMAXIMIZED = 3;

static void Main() 
{
    Process currentProcess = Process.GetCurrentProcess();
    var runningProcess = (from process in Process.GetProcesses()
                          where
                            process.Id != currentProcess.Id &&
                            process.ProcessName.Equals(
                              currentProcess.ProcessName,
                              StringComparison.Ordinal)
                          select process).FirstOrDefault();
    if (runningProcess != null)
    {
        ShowWindow(runningProcess.MainWindowHandle, SW_SHOWMAXIMIZED);
       return; 
    }
}

方法2

static void Main()
{
    string procName = Process.GetCurrentProcess().ProcessName;
    // get the list of all processes by that name

    Process[] processes=Process.GetProcessesByName(procName);

    if (processes.Length > 1)
    {
        MessageBox.Show(procName + " already running");  
        return;
    } 
    else
    {
        // Application.Run(...);
    }
}

注意:上述方法假设您的进程/应用程序有唯一的名称。因为它使用进程名来查找是否有现有的处理器。所以，如果你的应用程序有一个非常普通的名字(如:记事本)，上述方法是行不通的。

2011-08-24 22:48:30

[我在下面提供了控制台和wpf应用程序的示例代码。]

在创建命名的Mutex实例后，只需检查createdNew变量的值(示例如下!)。

布尔值createdNew将返回false:

如果命名为“YourApplicationNameHere”的互斥锁实例已经存在在系统某处创建

布尔值createdNew将返回true:

如果这是第一个名为“YourApplicationNameHere”的互斥锁系统。

控制台应用程序-示例:

static Mutex m = null;

static void Main(string[] args)
{
    const string mutexName = "YourApplicationNameHere";
    bool createdNew = false;

    try
    {
        // Initializes a new instance of the Mutex class with a Boolean value that indicates 
        // whether the calling thread should have initial ownership of the mutex, a string that is the name of the mutex, 
        // and a Boolean value that, when the method returns, indicates whether the calling thread was granted initial ownership of the mutex.

        using (m = new Mutex(true, mutexName, out createdNew))
        {
            if (!createdNew)
            {
                Console.WriteLine("instance is alreday running... shutting down !!!");
                Console.Read();
                return; // Exit the application
            }

            // Run your windows forms app here
            Console.WriteLine("Single instance app is running!");
            Console.ReadLine();
        }


    }
    catch (Exception ex)
    {

        Console.WriteLine(ex.Message);
        Console.ReadLine();
    }
}

WPF-Example:

public partial class App : Application
{
static Mutex m = null;

protected override void OnStartup(StartupEventArgs e)
{

    const string mutexName = "YourApplicationNameHere";
    bool createdNew = false;

    try
    {
        // Initializes a new instance of the Mutex class with a Boolean value that indicates 
        // whether the calling thread should have initial ownership of the mutex, a string that is the name of the mutex, 
        // and a Boolean value that, when the method returns, indicates whether the calling thread was granted initial ownership of the mutex.

        m = new Mutex(true, mutexName, out createdNew);

        if (!createdNew)
        {
            Current.Shutdown(); // Exit the application
        }

    }
    catch (Exception)
    {
        throw;
    }

    base.OnStartup(e);
}


protected override void OnExit(ExitEventArgs e)
{
    if (m != null)
    {
        m.Dispose();
    }
    base.OnExit(e);
}
}

2017-12-16 19:01:25

更新2017-01-25。在尝试了一些东西之后，我决定使用VisualBasic.dll，它更容易，工作效果更好(至少对我来说)。我让我之前的答案只是作为参考…

希望大家都喜欢……或者会启发一点:-)

项目启动类应该设置为“SingleInstanceApp”。

public class SingleInstanceApp
{
    [STAThread]
    public static void Main(string[] args)
    {
        Mutex _mutexSingleInstance = new Mutex(true, "MonitorMeSingleInstance");

        if (_mutexSingleInstance.WaitOne(TimeSpan.Zero, true))
        {
            try
            {
                var app = new App();
                app.InitializeComponent();
                app.Run();

            }
            finally
            {
                _mutexSingleInstance.ReleaseMutex();
                _mutexSingleInstance.Close();
            }
        }
        else
        {
            MessageBox.Show("One instance is already running.");

            var processes = Process.GetProcessesByName(Assembly.GetEntryAssembly().GetName().Name);
            {
                if (processes.Length > 1)
                {
                    foreach (var process in processes)
                    {
                        if (process.Id != Process.GetCurrentProcess().Id)
                        {
                            WindowHelper.SetForegroundWindow(process.MainWindowHandle);
                        }
                    }
                }
            }
        }
    }
}

WindowHelper:

using System;
using System.Runtime.InteropServices;
using System.Windows;
using System.Windows.Interop;
using System.Windows.Threading;

namespace HQ.Util.Unmanaged
{
    public class WindowHelper
    {
        [DllImport("user32.dll")]
        [return: MarshalAs(UnmanagedType.Bool)]
        public static extern bool SetForegroundWindow(IntPtr hWnd);

2013-12-05 23:00:54

基于命名互斥的方法不是跨平台的，因为命名互斥在Mono中不是全局的。基于进程枚举的方法没有任何同步，可能会导致不正确的行为(例如，同时启动的多个进程可能都根据时间自行终止)。在控制台应用程序中不需要基于windows系统的方法。这个解决方案建立在Divin的答案之上，解决了所有这些问题:

using System;
using System.IO;

namespace TestCs
{
    public class Program
    {
        // The app id must be unique. Generate a new guid for your application. 
        public static string AppId = "01234567-89ab-cdef-0123-456789abcdef";

        // The stream is stored globally to ensure that it won't be disposed before the application terminates.
        public static FileStream UniqueInstanceStream;

        public static int Main(string[] args)
        {
            EnsureUniqueInstance();

            // Your code here.

            return 0;
        }

        private static void EnsureUniqueInstance()
        {
            // Note: If you want the check to be per-user, use Environment.SpecialFolder.ApplicationData instead.
            string lockDir = Path.Combine(
                Environment.GetFolderPath(Environment.SpecialFolder.CommonApplicationData),
                "UniqueInstanceApps");
            string lockPath = Path.Combine(lockDir, $"{AppId}.unique");

            Directory.CreateDirectory(lockDir);

            try
            {
                // Create the file with exclusive write access. If this fails, then another process is executing.
                UniqueInstanceStream = File.Open(lockPath, FileMode.Create, FileAccess.Write, FileShare.None);

                // Although only the line above should be sufficient, when debugging with a vshost on Visual Studio
                // (that acts as a proxy), the IO exception isn't passed to the application before a Write is executed.
                UniqueInstanceStream.Write(new byte[] { 0 }, 0, 1);
                UniqueInstanceStream.Flush();
            }
            catch
            {
                throw new Exception("Another instance of the application is already running.");
            }
        }
    }
}

2017-08-20 05:28:30

这么简单的问题有这么多答案。稍微改变一下这里是我对这个问题的解决方案。

Creating a Mutex can be troublesome because the JIT-er only sees you using it for a small portion of your code and wants to mark it as ready for garbage collection. It pretty much wants to out-smart you thinking you are not going to be using that Mutex for that long. In reality you want to hang onto this Mutex for as long as your application is running. The best way to tell the garbage collector to leave you Mutex alone is to tell it to keep it alive though out the different generations of garage collection. Example:

var m = new Mutex(...);
...
GC.KeepAlive(m);

我从这个网页上获得了灵感:http://www.ai.uga.edu/~mc/SingleInstance.html

2010-05-05 00:54:24

创建单实例WPF应用程序的正确方法是什么?

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