在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
当前回答
这段代码应该转到main方法。关于WPF中main方法的更多信息,请参阅这里。
[DllImport("user32.dll")]
private static extern Boolean ShowWindow(IntPtr hWnd, Int32 nCmdShow);
private const int SW_SHOWMAXIMIZED = 3;
static void Main()
{
Process currentProcess = Process.GetCurrentProcess();
var runningProcess = (from process in Process.GetProcesses()
where
process.Id != currentProcess.Id &&
process.ProcessName.Equals(
currentProcess.ProcessName,
StringComparison.Ordinal)
select process).FirstOrDefault();
if (runningProcess != null)
{
ShowWindow(runningProcess.MainWindowHandle, SW_SHOWMAXIMIZED);
return;
}
}
方法2
static void Main()
{
string procName = Process.GetCurrentProcess().ProcessName;
// get the list of all processes by that name
Process[] processes=Process.GetProcessesByName(procName);
if (processes.Length > 1)
{
MessageBox.Show(procName + " already running");
return;
}
else
{
// Application.Run(...);
}
}
注意:上述方法假设您的进程/应用程序有唯一的名称。因为它使用进程名来查找是否有现有的处理器。所以,如果你的应用程序有一个非常普通的名字(如:记事本),上述方法是行不通的。
其他回答
这里有一个解决方案:
Protected Overrides Sub OnStartup(e As StartupEventArgs)
Const appName As String = "TestApp"
Dim createdNew As Boolean
_mutex = New Mutex(True, appName, createdNew)
If Not createdNew Then
'app is already running! Exiting the application
MessageBox.Show("Application is already running.")
Application.Current.Shutdown()
End If
MyBase.OnStartup(e)
End Sub
这是一篇关于互斥锁解决方案的很好的文章。本文描述的方法有两个优点。
首先,它不需要依赖于Microsoft。VisualBasic组装。如果我的项目已经依赖于该程序集,我可能会建议使用另一个答案中显示的方法。但事实上,我不使用微软。VisualBasic程序集,我宁愿不向项目添加不必要的依赖项。
其次,本文将展示当用户试图启动另一个实例时,如何将应用程序的现有实例显示到前台。这是这里描述的其他互斥锁解决方案没有解决的问题。
更新
截至2014年8月1日,我上面链接的文章仍然活跃,但博客已经有一段时间没有更新了。这让我担心,它最终可能会消失,随之而来的是所倡导的解决方案。我在这里复制这篇文章的内容以供后人参考。这些文字仅属于Sanity Free Coding的博客所有者。
Today I wanted to refactor some code that prohibited my application from running multiple instances of itself. Previously I had use System.Diagnostics.Process to search for an instance of my myapp.exe in the process list. While this works, it brings on a lot of overhead, and I wanted something cleaner. Knowing that I could use a mutex for this (but never having done it before) I set out to cut down my code and simplify my life. In the class of my application main I created a static named Mutex:
static class Program
{
static Mutex mutex = new Mutex(true, "{8F6F0AC4-B9A1-45fd-A8CF-72F04E6BDE8F}");
[STAThread]
...
}
Having a named mutex allows us to stack synchronization across multiple threads and processes which is just the magic I'm looking for. Mutex.WaitOne has an overload that specifies an amount of time for us to wait. Since we're not actually wanting to synchronizing our code (more just check if it is currently in use) we use the overload with two parameters: Mutex.WaitOne(Timespan timeout, bool exitContext). Wait one returns true if it is able to enter, and false if it wasn't. In this case, we don't want to wait at all; If our mutex is being used, skip it, and move on, so we pass in TimeSpan.Zero (wait 0 milliseconds), and set the exitContext to true so we can exit the synchronization context before we try to aquire a lock on it. Using this, we wrap our Application.Run code inside something like this:
static class Program
{
static Mutex mutex = new Mutex(true, "{8F6F0AC4-B9A1-45fd-A8CF-72F04E6BDE8F}");
[STAThread]
static void Main() {
if(mutex.WaitOne(TimeSpan.Zero, true)) {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
mutex.ReleaseMutex();
} else {
MessageBox.Show("only one instance at a time");
}
}
}
So, if our app is running, WaitOne will return false, and we'll get a message box. Instead of showing a message box, I opted to utilize a little Win32 to notify my running instance that someone forgot that it was already running (by bringing itself to the top of all the other windows). To achieve this I used PostMessage to broadcast a custom message to every window (the custom message was registered with RegisterWindowMessage by my running application, which means only my application knows what it is) then my second instance exits. The running application instance would receive that notification and process it. In order to do that, I overrode WndProc in my main form and listened for my custom notification. When I received that notification I set the form's TopMost property to true to bring it up on top. Here is what I ended up with: Program.cs
static class Program
{
static Mutex mutex = new Mutex(true, "{8F6F0AC4-B9A1-45fd-A8CF-72F04E6BDE8F}");
[STAThread]
static void Main() {
if(mutex.WaitOne(TimeSpan.Zero, true)) {
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Form1());
mutex.ReleaseMutex();
} else {
// send our Win32 message to make the currently running instance
// jump on top of all the other windows
NativeMethods.PostMessage(
(IntPtr)NativeMethods.HWND_BROADCAST,
NativeMethods.WM_SHOWME,
IntPtr.Zero,
IntPtr.Zero);
}
}
}
NativeMethods.cs
// this class just wraps some Win32 stuff that we're going to use
internal class NativeMethods
{
public const int HWND_BROADCAST = 0xffff;
public static readonly int WM_SHOWME = RegisterWindowMessage("WM_SHOWME");
[DllImport("user32")]
public static extern bool PostMessage(IntPtr hwnd, int msg, IntPtr wparam, IntPtr lparam);
[DllImport("user32")]
public static extern int RegisterWindowMessage(string message);
}
Form1.cs(正面部分)
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
protected override void WndProc(ref Message m)
{
if(m.Msg == NativeMethods.WM_SHOWME) {
ShowMe();
}
base.WndProc(ref m);
}
private void ShowMe()
{
if(WindowState == FormWindowState.Minimized) {
WindowState = FormWindowState.Normal;
}
// get our current "TopMost" value (ours will always be false though)
bool top = TopMost;
// make our form jump to the top of everything
TopMost = true;
// set it back to whatever it was
TopMost = top;
}
}
基于Matt Davis的答案,为方便起见包装成一个类。
public static class SingleAppInstanceChecker
{
/// <summary>
/// Arbitrary unique string
/// </summary>
private static Mutex _mutex = new Mutex(true, "0d12ad74-026f-40c3-bdae-e178ddee8602");
public static bool IsNotRunning()
{
return _mutex.WaitOne(TimeSpan.Zero, true);
}
}
使用示例:
private void Application_Startup(object sender, StartupEventArgs e)
{
if (!SingleAppInstanceChecker.IsNotRunning())
{
MessageBox.Show("Application is already running.");
// Exit application using:
// Environment.Exit(1);
// Application.Current.Shutdown();
// Etc...
return;
}
// Allow startup and continue with normal processing
// ...
}
我在解决方案中使用互斥来防止多个实例。
static Mutex mutex = null;
//A string that is the name of the mutex
string mutexName = @"Global\test";
//Prevent Multiple Instances of Application
bool onlyInstance = false;
mutex = new Mutex(true, mutexName, out onlyInstance);
if (!onlyInstance)
{
MessageBox.Show("You are already running this application in your system.", "Already Running..", MessageBoxButton.OK);
Application.Current.Shutdown();
}
这是我的整个App.xaml.cs,这段代码也将启动的程序实例带到前台:
public partial class App : Application
{
private static Mutex _mutex = null;
[DllImport("user32.dll")]
static extern bool SetForegroundWindow(IntPtr hWnd);
[DllImport("user32.dll")]
static extern bool ShowWindow(IntPtr hWnd, int nCmdShow);
protected override void OnStartup(StartupEventArgs e)
{
_mutex = new Mutex(true, "YourMutexName", out var createdNew);
if (!createdNew)
{
using (var currentProcess = Process.GetCurrentProcess())
{
foreach (var process in Process.GetProcessesByName(currentProcess.ProcessName))
{
if (process.Id != currentProcess.Id)
{
ShowWindow(process.MainWindowHandle, 9);
SetForegroundWindow(process.MainWindowHandle);
}
process.Dispose();
}
}
// app is already running! Exiting the application
Shutdown();
}
base.OnStartup(e);
}
protected override void OnExit(ExitEventArgs e)
{
_mutex.Dispose();
base.OnExit(e);
}
}