在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?

我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。

代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。


当前回答

这段代码应该转到main方法。关于WPF中main方法的更多信息,请参阅这里。

[DllImport("user32.dll")]
private static extern Boolean ShowWindow(IntPtr hWnd, Int32 nCmdShow);

private const int SW_SHOWMAXIMIZED = 3;

static void Main() 
{
    Process currentProcess = Process.GetCurrentProcess();
    var runningProcess = (from process in Process.GetProcesses()
                          where
                            process.Id != currentProcess.Id &&
                            process.ProcessName.Equals(
                              currentProcess.ProcessName,
                              StringComparison.Ordinal)
                          select process).FirstOrDefault();
    if (runningProcess != null)
    {
        ShowWindow(runningProcess.MainWindowHandle, SW_SHOWMAXIMIZED);
       return; 
    }
}

方法2

static void Main()
{
    string procName = Process.GetCurrentProcess().ProcessName;
    // get the list of all processes by that name

    Process[] processes=Process.GetProcessesByName(procName);

    if (processes.Length > 1)
    {
        MessageBox.Show(procName + " already running");  
        return;
    } 
    else
    {
        // Application.Run(...);
    }
}

注意:上述方法假设您的进程/应用程序有唯一的名称。因为它使用进程名来查找是否有现有的处理器。所以,如果你的应用程序有一个非常普通的名字(如:记事本),上述方法是行不通的。

其他回答

我喜欢一个解决方案,以允许多个实例,如果exe是从其他路径调用。我修改了CharithJ溶液方法一:

   static class Program {
    [DllImport("user32.dll")]
    private static extern bool ShowWindow(IntPtr hWnd, Int32 nCmdShow);
    [DllImport("User32.dll")]
    public static extern Int32 SetForegroundWindow(IntPtr hWnd);
    [STAThread]
    static void Main() {
        Process currentProcess = Process.GetCurrentProcess();
        foreach (var process in Process.GetProcesses()) {
            try {
                if ((process.Id != currentProcess.Id) && 
                    (process.ProcessName == currentProcess.ProcessName) &&
                    (process.MainModule.FileName == currentProcess.MainModule.FileName)) {
                    ShowWindow(process.MainWindowHandle, 5); // const int SW_SHOW = 5; //Activates the window and displays it in its current size and position. 
                    SetForegroundWindow(process.MainWindowHandle);
                    return;
                }
            } catch (Exception ex) {
                //ignore Exception "Access denied "
            }
        }

        Application.EnableVisualStyles();
        Application.SetCompatibleTextRenderingDefault(false);
        Application.Run(new Form1());
    }
}

从这里。

跨进程互斥锁的一个常见用途是确保一个程序一次只能运行一个实例。以下是如何做到的:

class OneAtATimePlease {

  // Use a name unique to the application (eg include your company URL)
  static Mutex mutex = new Mutex (false, "oreilly.com OneAtATimeDemo");

  static void Main()
  {
    // Wait 5 seconds if contended – in case another instance
    // of the program is in the process of shutting down.
    if (!mutex.WaitOne(TimeSpan.FromSeconds (5), false))
    {
        Console.WriteLine("Another instance of the app is running. Bye!");
        return;
    }

    try
    {    
        Console.WriteLine("Running - press Enter to exit");
        Console.ReadLine();
    }
    finally
    {
        mutex.ReleaseMutex();
    }    
  }    
}

互斥锁的一个很好的特性是,如果应用程序在没有首先调用ReleaseMutex的情况下终止,CLR将自动释放互斥锁。

您还可以使用CodeFluent Runtime,这是一组免费的工具。它提供了一个SingleInstance类来实现单个实例应用程序。

基于Matt Davis的答案,为方便起见包装成一个类。

public static class SingleAppInstanceChecker
{
    /// <summary>
    /// Arbitrary unique string
    /// </summary>
    private static Mutex _mutex = new Mutex(true, "0d12ad74-026f-40c3-bdae-e178ddee8602");

    public static bool IsNotRunning()
    {
        return _mutex.WaitOne(TimeSpan.Zero, true);
    }
}

使用示例:

private void Application_Startup(object sender, StartupEventArgs e)
{
    if (!SingleAppInstanceChecker.IsNotRunning())
    {
        MessageBox.Show("Application is already running.");

        // Exit application using:
        // Environment.Exit(1);
        // Application.Current.Shutdown();
        // Etc...

        return;
    }
    
    // Allow startup and continue with normal processing
    // ...
}

基于命名互斥的方法不是跨平台的,因为命名互斥在Mono中不是全局的。基于进程枚举的方法没有任何同步,可能会导致不正确的行为(例如,同时启动的多个进程可能都根据时间自行终止)。在控制台应用程序中不需要基于windows系统的方法。这个解决方案建立在Divin的答案之上,解决了所有这些问题:

using System;
using System.IO;

namespace TestCs
{
    public class Program
    {
        // The app id must be unique. Generate a new guid for your application. 
        public static string AppId = "01234567-89ab-cdef-0123-456789abcdef";

        // The stream is stored globally to ensure that it won't be disposed before the application terminates.
        public static FileStream UniqueInstanceStream;

        public static int Main(string[] args)
        {
            EnsureUniqueInstance();

            // Your code here.

            return 0;
        }

        private static void EnsureUniqueInstance()
        {
            // Note: If you want the check to be per-user, use Environment.SpecialFolder.ApplicationData instead.
            string lockDir = Path.Combine(
                Environment.GetFolderPath(Environment.SpecialFolder.CommonApplicationData),
                "UniqueInstanceApps");
            string lockPath = Path.Combine(lockDir, $"{AppId}.unique");

            Directory.CreateDirectory(lockDir);

            try
            {
                // Create the file with exclusive write access. If this fails, then another process is executing.
                UniqueInstanceStream = File.Open(lockPath, FileMode.Create, FileAccess.Write, FileShare.None);

                // Although only the line above should be sufficient, when debugging with a vshost on Visual Studio
                // (that acts as a proxy), the IO exception isn't passed to the application before a Write is executed.
                UniqueInstanceStream.Write(new byte[] { 0 }, 0, 1);
                UniqueInstanceStream.Flush();
            }
            catch
            {
                throw new Exception("Another instance of the application is already running.");
            }
        }
    }
}