这是我的两分钱

 static class Program
    {
        [STAThread]
        static void Main()
        {
            bool createdNew;
            using (new Mutex(true, "MyApp", out createdNew))
            {
                if (createdNew) {
                    Application.EnableVisualStyles();
                    Application.SetCompatibleTextRenderingDefault(false);
                    var mainClass = new SynGesturesLogic();
                    Application.ApplicationExit += mainClass.tray_exit;
                    Application.Run();
                }
                else
                {
                    var current = Process.GetCurrentProcess();
                    foreach (var process in Process.GetProcessesByName(current.ProcessName).Where(process => process.Id != current.Id))
                    {
                        NativeMethods.SetForegroundWindow(process.MainWindowHandle);
                        break;
                    }
                }
            }
        }
    }

你可以使用Mutex类，但是你很快就会发现你需要自己实现传递参数的代码。当我读Chris Sell的书时，我学到了一个用WinForms编程的技巧。这个技巧使用了框架中已经可用的逻辑。我不知道你怎么想，但当我了解到可以在框架中重用的东西时，这通常是我采取的路线，而不是重新发明轮子。当然，除非它不能做到我想要的一切。

当我进入WPF时，我想到了一种使用相同代码的方法，但在WPF应用程序中。基于您的问题，这个解决方案应该能够满足您的需求。

首先，我们需要创建应用程序类。在这个类中，我们将重写OnStartup事件并创建一个名为Activate的方法，该方法将在稍后使用。

public class SingleInstanceApplication : System.Windows.Application
{
    protected override void OnStartup(System.Windows.StartupEventArgs e)
    {
        // Call the OnStartup event on our base class
        base.OnStartup(e);

        // Create our MainWindow and show it
        MainWindow window = new MainWindow();
        window.Show();
    }

    public void Activate()
    {
        // Reactivate the main window
        MainWindow.Activate();
    }
}

Second, we will need to create a class that can manage our instances. Before we go through that, we are actually going to reuse some code that is in the Microsoft.VisualBasic assembly. Since, I am using C# in this example, I had to make a reference to the assembly. If you are using VB.NET, you don't have to do anything. The class we are going to use is WindowsFormsApplicationBase and inherit our instance manager off of it and then leverage properties and events to handle the single instancing.

public class SingleInstanceManager : Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase
{
    private SingleInstanceApplication _application;
    private System.Collections.ObjectModel.ReadOnlyCollection<string> _commandLine;

    public SingleInstanceManager()
    {
        IsSingleInstance = true;
    }

    protected override bool OnStartup(Microsoft.VisualBasic.ApplicationServices.StartupEventArgs eventArgs)
    {
        // First time _application is launched
        _commandLine = eventArgs.CommandLine;
        _application = new SingleInstanceApplication();
        _application.Run();
        return false;
    }

    protected override void OnStartupNextInstance(StartupNextInstanceEventArgs eventArgs)
    {
        // Subsequent launches
        base.OnStartupNextInstance(eventArgs);
        _commandLine = eventArgs.CommandLine;
        _application.Activate();
    }
}

基本上，我们使用VB位来检测单个实例并进行相应的处理。OnStartup将在第一个实例加载时被触发。当应用程序再次运行时，OnStartupNextInstance被触发。如您所见，我可以通过事件参数获得在命令行上传递的内容。我将值设置为一个实例字段。您可以在这里解析命令行，也可以通过构造函数和对Activate方法的调用将它传递给应用程序。

第三，是时候创建我们的入口点了。我们将利用SingleInstanceManager，而不是像通常那样更新应用程序。

public class EntryPoint
{
    [STAThread]
    public static void Main(string[] args)
    {
        SingleInstanceManager manager = new SingleInstanceManager();
        manager.Run(args);
    }
}

好吧，我希望您能够理解所有内容，能够使用这个实现并使其成为您自己的实现。

[我在下面提供了控制台和wpf应用程序的示例代码。]

在创建命名的Mutex实例后，只需检查createdNew变量的值(示例如下!)。

布尔值createdNew将返回false:

如果命名为“YourApplicationNameHere”的互斥锁实例已经存在 在系统某处创建

布尔值createdNew将返回true:

如果这是第一个名为“YourApplicationNameHere”的互斥锁 系统。

控制台应用程序-示例:

static Mutex m = null;

static void Main(string[] args)
{
    const string mutexName = "YourApplicationNameHere";
    bool createdNew = false;

    try
    {
        // Initializes a new instance of the Mutex class with a Boolean value that indicates 
        // whether the calling thread should have initial ownership of the mutex, a string that is the name of the mutex, 
        // and a Boolean value that, when the method returns, indicates whether the calling thread was granted initial ownership of the mutex.

        using (m = new Mutex(true, mutexName, out createdNew))
        {
            if (!createdNew)
            {
                Console.WriteLine("instance is alreday running... shutting down !!!");
                Console.Read();
                return; // Exit the application
            }

            // Run your windows forms app here
            Console.WriteLine("Single instance app is running!");
            Console.ReadLine();
        }


    }
    catch (Exception ex)
    {

        Console.WriteLine(ex.Message);
        Console.ReadLine();
    }
}

WPF-Example:

public partial class App : Application
{
static Mutex m = null;

protected override void OnStartup(StartupEventArgs e)
{

    const string mutexName = "YourApplicationNameHere";
    bool createdNew = false;

    try
    {
        // Initializes a new instance of the Mutex class with a Boolean value that indicates 
        // whether the calling thread should have initial ownership of the mutex, a string that is the name of the mutex, 
        // and a Boolean value that, when the method returns, indicates whether the calling thread was granted initial ownership of the mutex.

        m = new Mutex(true, mutexName, out createdNew);

        if (!createdNew)
        {
            Current.Shutdown(); // Exit the application
        }

    }
    catch (Exception)
    {
        throw;
    }

    base.OnStartup(e);
}


protected override void OnExit(ExitEventArgs e)
{
    if (m != null)
    {
        m.Dispose();
    }
    base.OnExit(e);
}
}

这么简单的问题有这么多答案。稍微改变一下这里是我对这个问题的解决方案。

Creating a Mutex can be troublesome because the JIT-er only sees you using it for a small portion of your code and wants to mark it as ready for garbage collection. It pretty much wants to out-smart you thinking you are not going to be using that Mutex for that long. In reality you want to hang onto this Mutex for as long as your application is running. The best way to tell the garbage collector to leave you Mutex alone is to tell it to keep it alive though out the different generations of garage collection. Example:

var m = new Mutex(...);
...
GC.KeepAlive(m);

我从这个网页上获得了灵感:http://www.ai.uga.edu/~mc/SingleInstance.html

这是通过事件实现的相同的事情。

public enum ApplicationSingleInstanceMode
{
    CurrentUserSession,
    AllSessionsOfCurrentUser,
    Pc
}

public class ApplicationSingleInstancePerUser: IDisposable
{
    private readonly EventWaitHandle _event;

    /// <summary>
    /// Shows if the current instance of ghost is the first
    /// </summary>
    public bool FirstInstance { get; private set; }

    /// <summary>
    /// Initializes 
    /// </summary>
    /// <param name="applicationName">The application name</param>
    /// <param name="mode">The single mode</param>
    public ApplicationSingleInstancePerUser(string applicationName, ApplicationSingleInstanceMode mode = ApplicationSingleInstanceMode.CurrentUserSession)
    {
        string name;
        if (mode == ApplicationSingleInstanceMode.CurrentUserSession)
            name = $"Local\\{applicationName}";
        else if (mode == ApplicationSingleInstanceMode.AllSessionsOfCurrentUser)
            name = $"Global\\{applicationName}{Environment.UserDomainName}";
        else
            name = $"Global\\{applicationName}";

        try
        {
            bool created;
            _event = new EventWaitHandle(false, EventResetMode.ManualReset, name, out created);
            FirstInstance = created;
        }
        catch
        {
        }
    }

    public void Dispose()
    {
        _event.Dispose();
    }
}

这就是我最终处理这个问题的方式。注意，调试代码仍然在那里进行测试。这段代码在App.xaml.cs文件的OnStartup中。(WPF)

        // Process already running ? 
        if (Process.GetProcessesByName(Process.GetCurrentProcess().ProcessName).Length > 1)
        {

            // Show your error message
            MessageBox.Show("xxx is already running.  \r\n\r\nIf the original process is hung up you may need to restart your computer, or kill the current xxx process using the task manager.", "xxx is already running!", MessageBoxButton.OK, MessageBoxImage.Exclamation);

            // This process 
            Process currentProcess = Process.GetCurrentProcess();

            // Get all processes running on the local computer.
            Process[] localAll = Process.GetProcessesByName(Process.GetCurrentProcess().ProcessName);

            // ID of this process... 
            int temp = currentProcess.Id;
            MessageBox.Show("This Process ID:  " + temp.ToString());

            for (int i = 0; i < localAll.Length; i++)
            {
                // Find the other process 
                if (localAll[i].Id != currentProcess.Id)
                {
                    MessageBox.Show("Original Process ID (Switching to):  " + localAll[i].Id.ToString());

                    // Switch to it... 
                    SetForegroundWindow(localAll[i].MainWindowHandle);

                }
            }

            Application.Current.Shutdown();

        }

这可能有我还没有发现的问题。如果我遇到了，我会更新我的答案。