在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
当前回答
这是我的整个App.xaml.cs,这段代码也将启动的程序实例带到前台:
public partial class App : Application
{
private static Mutex _mutex = null;
[DllImport("user32.dll")]
static extern bool SetForegroundWindow(IntPtr hWnd);
[DllImport("user32.dll")]
static extern bool ShowWindow(IntPtr hWnd, int nCmdShow);
protected override void OnStartup(StartupEventArgs e)
{
_mutex = new Mutex(true, "YourMutexName", out var createdNew);
if (!createdNew)
{
using (var currentProcess = Process.GetCurrentProcess())
{
foreach (var process in Process.GetProcessesByName(currentProcess.ProcessName))
{
if (process.Id != currentProcess.Id)
{
ShowWindow(process.MainWindowHandle, 9);
SetForegroundWindow(process.MainWindowHandle);
}
process.Dispose();
}
}
// app is already running! Exiting the application
Shutdown();
}
base.OnStartup(e);
}
protected override void OnExit(ExitEventArgs e)
{
_mutex.Dispose();
base.OnExit(e);
}
}
其他回答
下面是一个示例,它允许您拥有应用程序的单个实例。当加载任何新实例时,它们将参数传递给正在运行的主实例。
public partial class App : Application
{
private static Mutex SingleMutex;
public static uint MessageId;
private void Application_Startup(object sender, StartupEventArgs e)
{
IntPtr Result;
IntPtr SendOk;
Win32.COPYDATASTRUCT CopyData;
string[] Args;
IntPtr CopyDataMem;
bool AllowMultipleInstances = false;
Args = Environment.GetCommandLineArgs();
// TODO: Replace {00000000-0000-0000-0000-000000000000} with your application's GUID
MessageId = Win32.RegisterWindowMessage("{00000000-0000-0000-0000-000000000000}");
SingleMutex = new Mutex(false, "AppName");
if ((AllowMultipleInstances) || (!AllowMultipleInstances && SingleMutex.WaitOne(1, true)))
{
new Main();
}
else if (Args.Length > 1)
{
foreach (Process Proc in Process.GetProcesses())
{
SendOk = Win32.SendMessageTimeout(Proc.MainWindowHandle, MessageId, IntPtr.Zero, IntPtr.Zero,
Win32.SendMessageTimeoutFlags.SMTO_BLOCK | Win32.SendMessageTimeoutFlags.SMTO_ABORTIFHUNG,
2000, out Result);
if (SendOk == IntPtr.Zero)
continue;
if ((uint)Result != MessageId)
continue;
CopyDataMem = Marshal.AllocHGlobal(Marshal.SizeOf(typeof(Win32.COPYDATASTRUCT)));
CopyData.dwData = IntPtr.Zero;
CopyData.cbData = Args[1].Length*2;
CopyData.lpData = Marshal.StringToHGlobalUni(Args[1]);
Marshal.StructureToPtr(CopyData, CopyDataMem, false);
Win32.SendMessageTimeout(Proc.MainWindowHandle, Win32.WM_COPYDATA, IntPtr.Zero, CopyDataMem,
Win32.SendMessageTimeoutFlags.SMTO_BLOCK | Win32.SendMessageTimeoutFlags.SMTO_ABORTIFHUNG,
5000, out Result);
Marshal.FreeHGlobal(CopyData.lpData);
Marshal.FreeHGlobal(CopyDataMem);
}
Shutdown(0);
}
}
}
public partial class Main : Window
{
private void Window_Loaded(object sender, RoutedEventArgs e)
{
HwndSource Source;
Source = HwndSource.FromHwnd(new WindowInteropHelper(this).Handle);
Source.AddHook(new HwndSourceHook(Window_Proc));
}
private IntPtr Window_Proc(IntPtr hWnd, int Msg, IntPtr wParam, IntPtr lParam, ref bool Handled)
{
Win32.COPYDATASTRUCT CopyData;
string Path;
if (Msg == Win32.WM_COPYDATA)
{
CopyData = (Win32.COPYDATASTRUCT)Marshal.PtrToStructure(lParam, typeof(Win32.COPYDATASTRUCT));
Path = Marshal.PtrToStringUni(CopyData.lpData, CopyData.cbData / 2);
if (WindowState == WindowState.Minimized)
{
// Restore window from tray
}
// Do whatever we want with information
Activate();
Focus();
}
if (Msg == App.MessageId)
{
Handled = true;
return new IntPtr(App.MessageId);
}
return IntPtr.Zero;
}
}
public class Win32
{
public const uint WM_COPYDATA = 0x004A;
public struct COPYDATASTRUCT
{
public IntPtr dwData;
public int cbData;
public IntPtr lpData;
}
[Flags]
public enum SendMessageTimeoutFlags : uint
{
SMTO_NORMAL = 0x0000,
SMTO_BLOCK = 0x0001,
SMTO_ABORTIFHUNG = 0x0002,
SMTO_NOTIMEOUTIFNOTHUNG = 0x0008
}
[DllImport("user32.dll", SetLastError=true, CharSet=CharSet.Auto)]
public static extern uint RegisterWindowMessage(string lpString);
[DllImport("user32.dll")]
public static extern IntPtr SendMessageTimeout(
IntPtr hWnd, uint Msg, IntPtr wParam, IntPtr lParam,
SendMessageTimeoutFlags fuFlags, uint uTimeout, out IntPtr lpdwResult);
}
一个新的使用互斥和IPC的东西,也传递任何命令行参数到运行的实例,是WPF单实例应用程序。
基于命名互斥的方法不是跨平台的,因为命名互斥在Mono中不是全局的。基于进程枚举的方法没有任何同步,可能会导致不正确的行为(例如,同时启动的多个进程可能都根据时间自行终止)。在控制台应用程序中不需要基于windows系统的方法。这个解决方案建立在Divin的答案之上,解决了所有这些问题:
using System;
using System.IO;
namespace TestCs
{
public class Program
{
// The app id must be unique. Generate a new guid for your application.
public static string AppId = "01234567-89ab-cdef-0123-456789abcdef";
// The stream is stored globally to ensure that it won't be disposed before the application terminates.
public static FileStream UniqueInstanceStream;
public static int Main(string[] args)
{
EnsureUniqueInstance();
// Your code here.
return 0;
}
private static void EnsureUniqueInstance()
{
// Note: If you want the check to be per-user, use Environment.SpecialFolder.ApplicationData instead.
string lockDir = Path.Combine(
Environment.GetFolderPath(Environment.SpecialFolder.CommonApplicationData),
"UniqueInstanceApps");
string lockPath = Path.Combine(lockDir, $"{AppId}.unique");
Directory.CreateDirectory(lockDir);
try
{
// Create the file with exclusive write access. If this fails, then another process is executing.
UniqueInstanceStream = File.Open(lockPath, FileMode.Create, FileAccess.Write, FileShare.None);
// Although only the line above should be sufficient, when debugging with a vshost on Visual Studio
// (that acts as a proxy), the IO exception isn't passed to the application before a Write is executed.
UniqueInstanceStream.Write(new byte[] { 0 }, 0, 1);
UniqueInstanceStream.Flush();
}
catch
{
throw new Exception("Another instance of the application is already running.");
}
}
}
}
但是不使用互斥,简单的回答:
System.Diagnostics;
...
string thisprocessname = Process.GetCurrentProcess().ProcessName;
if (Process.GetProcesses().Count(p => p.ProcessName == thisprocessname) > 1)
return;
把它放在Program.Main()中。 例子:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.Diagnostics;
namespace Sample
{
static class Program
{
/// <summary>
/// The main entry point for the application.
/// </summary>
[STAThread]
static void Main()
{
//simple add Diagnostics namespace, and these 3 lines below
string thisprocessname = Process.GetCurrentProcess().ProcessName;
if (Process.GetProcesses().Count(p => p.ProcessName == thisprocessname) > 1)
return;
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new Sample());
}
}
}
您可以添加MessageBox。在if语句中显示并输入“应用程序已运行”。 这可能对某些人有帮助。
下面是我使用的一个轻量级解决方案,它允许应用程序将一个已经存在的窗口带到前台,而无需求助于自定义窗口消息或盲目地搜索进程名。
[DllImport("user32.dll")]
static extern bool SetForegroundWindow(IntPtr hWnd);
static readonly string guid = "<Application Guid>";
static void Main()
{
Mutex mutex = null;
if (!CreateMutex(out mutex))
return;
// Application startup code.
Environment.SetEnvironmentVariable(guid, null, EnvironmentVariableTarget.User);
}
static bool CreateMutex(out Mutex mutex)
{
bool createdNew = false;
mutex = new Mutex(false, guid, out createdNew);
if (createdNew)
{
Process process = Process.GetCurrentProcess();
string value = process.Id.ToString();
Environment.SetEnvironmentVariable(guid, value, EnvironmentVariableTarget.User);
}
else
{
string value = Environment.GetEnvironmentVariable(guid, EnvironmentVariableTarget.User);
Process process = null;
int processId = -1;
if (int.TryParse(value, out processId))
process = Process.GetProcessById(processId);
if (process == null || !SetForegroundWindow(process.MainWindowHandle))
MessageBox.Show("Unable to start application. An instance of this application is already running.");
}
return createdNew;
}
编辑:你也可以静态地存储和初始化互斥量和createdNew,但是一旦你完成了它,你需要显式地释放/释放互斥量。就我个人而言,我更喜欢将互斥锁保持在本地,因为即使应用程序在未到达Main结束时就关闭,它也会被自动销毁。