请问如何在ASP中获取客户端IP地址?NET时使用MVC 6。 请求。ServerVariables["REMOTE_ADDR"]无效。


当前回答

@crokusek回答的简短版本

public string GetUserIP(HttpRequest req)
{
    var ip = req.Headers["X-Forwarded-For"].FirstOrDefault();

    if (!string.IsNullOrWhiteSpace(ip)) ip = ip.Split(',')[0];

    if (string.IsNullOrWhiteSpace(ip)) ip = Convert.ToString(req.HttpContext.Connection.RemoteIpAddress);

    if (string.IsNullOrWhiteSpace(ip)) ip = req.Headers["REMOTE_ADDR"].FirstOrDefault();

    return ip;
}

其他回答

我发现,你们中的一些人发现你们得到的IP地址是:::1或0.0.0.1

这是一个问题,因为你试图从你自己的机器获取IP,而c#试图返回IPv6的混乱。

所以,我实现了来自@Johna (https://stackoverflow.com/a/41335701/812720)和@David (https://stackoverflow.com/a/8597351/812720)的答案,感谢他们!

下面是解决方案:

add Microsoft.AspNetCore.HttpOverrides Package in your References (Dependencies/Packages) add this line in Startup.cs public void Configure(IApplicationBuilder app, IHostingEnvironment env) { // your current code // start code to add // to get ip address app.UseForwardedHeaders(new ForwardedHeadersOptions { ForwardedHeaders = ForwardedHeaders.XForwardedFor | ForwardedHeaders.XForwardedProto }); // end code to add } to get IPAddress, use this code in any of your Controller.cs IPAddress remoteIpAddress = Request.HttpContext.Connection.RemoteIpAddress; string result = ""; if (remoteIpAddress != null) { // If we got an IPV6 address, then we need to ask the network for the IPV4 address // This usually only happens when the browser is on the same machine as the server. if (remoteIpAddress.AddressFamily == System.Net.Sockets.AddressFamily.InterNetworkV6) { remoteIpAddress = System.Net.Dns.GetHostEntry(remoteIpAddress).AddressList .First(x => x.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork); } result = remoteIpAddress.ToString(); }

现在你可以从remoteIpAddress或result获取IPv4地址

您可以使用IHttpConnectionFeature来获取此信息。

var remoteIpAddress = httpContext.GetFeature<IHttpConnectionFeature>()?.RemoteIpAddress;
using Microsoft.AspNetCore.Http;
using Microsoft.AspNetCore.Http.Features;

public string GetClientIPAddress(HttpContext context)
    {
        string ip = string.Empty;
if (!string.IsNullOrEmpty(context.Request.Headers["X-Forwarded-For"]))
        {
            ip = context.Request.Headers["X-Forwarded-For"];
        }
        else
        {
            ip = context.Request.HttpContext.Features.Get<IHttpConnectionFeature>().RemoteIpAddress.ToString();
        }
        return ip;
    }

你想获取Ip地址;

GetClientIPAddress(HttpContext);

根据官方文档,如果你使用Apache或Nginx集成,以下代码应该添加到启动。ConfigureServices方法。

// using Microsoft.AspNetCore.HttpOverrides;

    services.Configure<ForwardedHeadersOptions>(options =>
    {
        options.ForwardedHeaders = ForwardedHeaders.XForwardedFor | 
            ForwardedHeaders.XForwardedProto;
        // Only loopback proxies are allowed by default.
        // Clear that restriction because forwarders are enabled by explicit 
        // configuration.
        options.KnownNetworks.Clear();
        options.KnownProxies.Clear();
    });

最重要的是,在配置方法中使用

app.UseForwardedHeaders();

进一步假设在nginx conf文件中,在一个位置内,使用

proxy_set_header   Host $host;
proxy_set_header   X-Real-IP $remote_addr;
proxy_set_header   X-Forwarded-For $proxy_add_x_forwarded_for;
proxy_set_header   X-Forwarded-Host $server_name;

现在X-Forwarded-For中的第一个条目将是真正的客户端IP。

重要:如果你想保护应用程序,不允许攻击者注入x - forward - for,请阅读这个答案。

请参见转发Linux和非iis反向代理方案、配置Nginx和处理无效报头

在。net 5中,我使用它通过AWS fargate上的容器来检索客户端IP。

public static class HttpContextExtensions
{
    //https://gist.github.com/jjxtra/3b240b31a1ed3ad783a7dcdb6df12c36

    public static IPAddress GetRemoteIPAddress(this HttpContext context, bool allowForwarded = true)
    {
        if (allowForwarded)
        {
            string header = (context.Request.Headers["CF-Connecting-IP"].FirstOrDefault() ?? context.Request.Headers["X-Forwarded-For"].FirstOrDefault());
            if (IPAddress.TryParse(header, out IPAddress ip))
            {
                return ip;
            }
        }
        return context.Connection.RemoteIpAddress;
    }
}

你这样称呼它:

var ipFromExtensionMethod = HttpContext.GetRemoteIPAddress().ToString();