一个动态的方法来做到这与多个键:

从排序的每个col/key中过滤唯一的值 按顺序排列或颠倒 根据indexOf(value)键值为每个对象添加weights width zeropad 使用计算的权重进行排序

Object.defineProperty(Array.prototype, 'orderBy', {
value: function(sorts) { 
    sorts.map(sort => {            
        sort.uniques = Array.from(
            new Set(this.map(obj => obj[sort.key]))
        );
        
        sort.uniques = sort.uniques.sort((a, b) => {
            if (typeof a == 'string') {
                return sort.inverse ? b.localeCompare(a) : a.localeCompare(b);
            }
            else if (typeof a == 'number') {
                return sort.inverse ? b - a : a - b;
            }
            else if (typeof a == 'boolean') {
                let x = sort.inverse ? (a === b) ? 0 : a? -1 : 1 : (a === b) ? 0 : a? 1 : -1;
                return x;
            }
            return 0;
        });
    });

    const weightOfObject = (obj) => {
        let weight = "";
        sorts.map(sort => {
            let zeropad = `${sort.uniques.length}`.length;
            weight += sort.uniques.indexOf(obj[sort.key]).toString().padStart(zeropad, '0');
        });
        //obj.weight = weight; // if you need to see weights
        return weight;
    }

    this.sort((a, b) => {
        return weightOfObject(a).localeCompare( weightOfObject(b) );
    });
    
    return this;
}
});

Use:

// works with string, number and boolean
let sortered = your_array.orderBy([
    {key: "type", inverse: false}, 
    {key: "title", inverse: false},
    {key: "spot", inverse: false},
    {key: "internal", inverse: true}
]);

下面是一种可扩展的按多个字段排序的方法。

homes.sort(function(left, right) {
    var city_order = left.city.localeCompare(right.city);
    var price_order = parseInt(left.price) - parseInt(right.price);
    return city_order || -price_order;
});

笔记

A function passed to array sort is expected to return negative, zero, positive to indicate less, equal, greater. a.localeCompare(b) is universally supported for strings, and returns -1,0,1 if a<b,a==b,a>b. Subtraction works on numeric fields, because a - b gives -,0,+ if a<b,a==b,a>b. || in the last line gives city priority over price. Negate to reverse order in any field, as in -price_order Add new fields to the or-chain: return city_order || -price_order || date_order; Date compare with subtraction, because date math converts to milliseconds since 1970.var date_order = new Date(left.date) - new Date(right.date); Boolean compare with subtraction, which is guaranteed to turn true and false to 1 and 0 (therefore the subtraction produces -1 or 0 or 1). var goodness_order = Boolean(left.is_good) - Boolean(right.is_good)This is unusual enough that I'd suggest drawing attention with the Boolean constructor, even if they're already boolean.

通过添加两个辅助函数，可以简单地解决这类问题。sortByKey接受一个数组和一个函数，该函数应返回一个项目列表，用于与每个数组条目进行比较。

这利用了javascript对简单值的数组进行智能比较的事实，即[2]<[2,0]<[2,1]<[10,0]。

// Two helpers: function cmp(a, b) { if (a > b) { return 1 } else if (a < b) { return -1 } else { return 0 } } function sortByKey(arr, key) { arr.sort((a, b) => cmp(key(a), key(b))) } // A demonstration: let arr = [{a:1, b:2}, {b:3, a:0}, {a:1, b:1}, {a:2, b:2}, {a:2, b:1}, {a:1, b:10}] sortByKey(arr, item => [item.a, item.b]) console.log(JSON.stringify(arr)) // '[{"b":3,"a":0},{"a":1,"b":1},{"a":1,"b":10},{"a":1,"b":2},{"a":2,"b":1},{"a":2,"b":2}]' sortByKey(arr, item => [item.b, item.a]) console.log(JSON.stringify(arr)) // '[{"a":1,"b":1},{"a":2,"b":1},{"a":1,"b":10},{"a":1,"b":2},{"a":2,"b":2},{"b":3,"a":0}]'

我从Python的列表中偷取了这个想法。排序功能。

我一直在寻找类似的东西，最后得到了这个:

首先，我们有一个或多个排序函数，总是返回0、1或-1:

const sortByTitle = (a, b): number => 
  a.title === b.title ? 0 : a.title > b.title ? 1 : -1;

您可以为想要排序的其他属性创建更多函数。

然后我有一个函数将这些排序函数合并为一个:

const createSorter = (...sorters) => (a, b) =>
  sorters.reduce(
    (d, fn) => (d === 0 ? fn(a, b) : d),
    0
  );

这可以用来以一种可读的方式组合上述排序函数:

const sorter = createSorter(sortByTitle, sortByYear)

items.sort(sorter)

当一个排序函数返回0时，将调用下一个排序函数进行进一步排序。

为了简化操作，可以使用这些辅助函数。

您可以根据需要对任意多个字段进行排序。对于每个排序字段，指定属性名，然后可选地指定-1作为排序方向，以降序排序而不是升序排序。

const data = [ {"h_id":"3","city":"Dallas","state":"TX","zip":"75201","price":"162500"}, {"h_id":"4","city":"Bevery Hills","state":"CA","zip":"90210","price":"319250"}, {"h_id":"6","city":"Dallas","state":"TX","zip":"75000","price":"556699"}, {"h_id":"5","city":"New York","state":"NY","zip":"00010","price":"962500"}, {"h_id":"7","city":"New York","state":"NY","zip":"00010","price":"800500"} ] const sortLexically = (p,d=1)=>(a,b)=>d * a[p].localeCompare(b[p]) const sortNumerically = (p,d=1)=>(a,b)=>d * (a[p]-b[p]) const sortBy = sorts=>(a,b)=>sorts.reduce((r,s)=>r||s(a,b),0) // sort first by city, then by price descending data.sort(sortBy([sortLexically('city'), sortNumerically('price', -1)])) console.log(data)

按多个字段排序对象数组的最简单方法:

 let homes = [ {"h_id":"3",
   "city":"Dallas",
   "state":"TX",
   "zip":"75201",
   "price":"162500"},
  {"h_id":"4",
   "city":"Bevery Hills",
   "state":"CA",
   "zip":"90210",
   "price":"319250"},
  {"h_id":"6",
   "city":"Dallas",
   "state":"TX",
   "zip":"75000",
   "price":"556699"},
  {"h_id":"5",
   "city":"New York",
   "state":"NY",
   "zip":"00010",
   "price":"962500"}
  ];

homes.sort((a, b) => (a.city > b.city) ? 1 : -1);

输出: “Bevery山” “达拉斯” “达拉斯” “达拉斯” “纽约”