从这个最初的问题,我将如何在多个字段应用排序?
使用这种稍作调整的结构,我将如何排序城市(上升)和价格(下降)?
var homes = [
{"h_id":"3",
"city":"Dallas",
"state":"TX",
"zip":"75201",
"price":"162500"},
{"h_id":"4",
"city":"Bevery Hills",
"state":"CA",
"zip":"90210",
"price":"319250"},
{"h_id":"6",
"city":"Dallas",
"state":"TX",
"zip":"75000",
"price":"556699"},
{"h_id":"5",
"city":"New York",
"state":"NY",
"zip":"00010",
"price":"962500"}
];
我喜欢的事实是,给出的答案提供了一个一般的方法。在我计划使用这段代码的地方,我将不得不对日期以及其他东西进行排序。“启动”对象的能力似乎很方便,如果不是有点麻烦的话。
我试图把这个答案构建成一个很好的通用示例,但我运气不太好。
下面是一种可扩展的按多个字段排序的方法。
homes.sort(function(left, right) {
var city_order = left.city.localeCompare(right.city);
var price_order = parseInt(left.price) - parseInt(right.price);
return city_order || -price_order;
});
笔记
A function passed to array sort is expected to return negative, zero, positive to indicate less, equal, greater.
a.localeCompare(b) is universally supported for strings, and returns -1,0,1 if a<b,a==b,a>b.
Subtraction works on numeric fields, because a - b gives -,0,+ if a<b,a==b,a>b.
|| in the last line gives city priority over price.
Negate to reverse order in any field, as in -price_order
Add new fields to the or-chain: return city_order || -price_order || date_order;
Date compare with subtraction, because date math converts to milliseconds since 1970.var date_order = new Date(left.date) - new Date(right.date);
Boolean compare with subtraction, which is guaranteed to turn true and false to 1 and 0 (therefore the subtraction produces -1 or 0 or 1). var goodness_order = Boolean(left.is_good) - Boolean(right.is_good)This is unusual enough that I'd suggest drawing attention with the Boolean constructor, even if they're already boolean.
这是另一个可能更接近您对语法的想法的例子
function sortObjects(objArray, properties /*, primers*/) {
var primers = arguments[2] || {}; // primers are optional
properties = properties.map(function(prop) {
if( !(prop instanceof Array) ) {
prop = [prop, 'asc']
}
if( prop[1].toLowerCase() == 'desc' ) {
prop[1] = -1;
} else {
prop[1] = 1;
}
return prop;
});
function valueCmp(x, y) {
return x > y ? 1 : x < y ? -1 : 0;
}
function arrayCmp(a, b) {
var arr1 = [], arr2 = [];
properties.forEach(function(prop) {
var aValue = a[prop[0]],
bValue = b[prop[0]];
if( typeof primers[prop[0]] != 'undefined' ) {
aValue = primers[prop[0]](aValue);
bValue = primers[prop[0]](bValue);
}
arr1.push( prop[1] * valueCmp(aValue, bValue) );
arr2.push( prop[1] * valueCmp(bValue, aValue) );
});
return arr1 < arr2 ? -1 : 1;
}
objArray.sort(function(a, b) {
return arrayCmp(a, b);
});
}
// just for fun use this to reverse the city name when sorting
function demoPrimer(str) {
return str.split('').reverse().join('');
}
// Example
sortObjects(homes, ['city', ['price', 'desc']], {city: demoPrimer});
演示:http://jsfiddle.net/Nq4dk/2/
编辑:只是为了好玩,这里有一个变化,只需要一个类似sql的字符串,所以你可以做sortObjects(房屋,“城市,价格desc”)
function sortObjects(objArray, properties /*, primers*/) {
var primers = arguments[2] || {};
properties = properties.split(/\s*,\s*/).map(function(prop) {
prop = prop.match(/^([^\s]+)(\s*desc)?/i);
if( prop[2] && prop[2].toLowerCase() === 'desc' ) {
return [prop[1] , -1];
} else {
return [prop[1] , 1];
}
});
function valueCmp(x, y) {
return x > y ? 1 : x < y ? -1 : 0;
}
function arrayCmp(a, b) {
var arr1 = [], arr2 = [];
properties.forEach(function(prop) {
var aValue = a[prop[0]],
bValue = b[prop[0]];
if( typeof primers[prop[0]] != 'undefined' ) {
aValue = primers[prop[0]](aValue);
bValue = primers[prop[0]](bValue);
}
arr1.push( prop[1] * valueCmp(aValue, bValue) );
arr2.push( prop[1] * valueCmp(bValue, aValue) );
});
return arr1 < arr2 ? -1 : 1;
}
objArray.sort(function(a, b) {
return arrayCmp(a, b);
});
}
function sort(data, orderBy) {
orderBy = Array.isArray(orderBy) ? orderBy : [orderBy];
return data.sort((a, b) => {
for (let i = 0, size = orderBy.length; i < size; i++) {
const key = Object.keys(orderBy[i])[0],
o = orderBy[i][key],
valueA = a[key],
valueB = b[key];
if (!(valueA || valueB)) {
console.error("the objects from the data passed does not have the key '" + key + "' passed on sort!");
return [];
}
if (+valueA === +valueA) {
return o.toLowerCase() === 'desc' ? valueB - valueA : valueA - valueB;
} else {
if (valueA.localeCompare(valueB) > 0) {
return o.toLowerCase() === 'desc' ? -1 : 1;
} else if (valueA.localeCompare(valueB) < 0) {
return o.toLowerCase() === 'desc' ? 1 : -1;
}
}
}
});
}
使用:
sort(homes, [{city : 'asc'}, {price: 'desc'}])
var homes = [
{"h_id":"3",
"city":"Dallas",
"state":"TX",
"zip":"75201",
"price":"162500"},
{"h_id":"4",
"city":"Bevery Hills",
"state":"CA",
"zip":"90210",
"price":"319250"},
{"h_id":"6",
"city":"Dallas",
"state":"TX",
"zip":"75000",
"price":"556699"},
{"h_id":"5",
"city":"New York",
"state":"NY",
"zip":"00010",
"price":"962500"}
];
function sort(data, orderBy) {
orderBy = Array.isArray(orderBy) ? orderBy : [orderBy];
return data.sort((a, b) => {
for (let i = 0, size = orderBy.length; i < size; i++) {
const key = Object.keys(orderBy[i])[0],
o = orderBy[i][key],
valueA = a[key],
valueB = b[key];
if (!(valueA || valueB)) {
console.error("the objects from the data passed does not have the key '" + key + "' passed on sort!");
return [];
}
if (+valueA === +valueA) {
return o.toLowerCase() === 'desc' ? valueB - valueA : valueA - valueB;
} else {
if (valueA.localeCompare(valueB) > 0) {
return o.toLowerCase() === 'desc' ? -1 : 1;
} else if (valueA.localeCompare(valueB) < 0) {
return o.toLowerCase() === 'desc' ? 1 : -1;
}
}
}
});
}
console.log(sort(homes, [{city : 'asc'}, {price: 'desc'}]));