警告:数组到字符串的转换

注意:数组到字符串的转换

(PHP 7.4之前的一个通知，PHP 8.0之后的一个警告)

如果你试图将数组视为字符串，就会发生这种情况:

$arr = array('foo', 'bar');

echo $arr;  // Notice: Array to string conversion
$str = 'Something, ' . $arr;  // Notice: Array to string conversion

数组不能简单地与字符串回显或连接，因为结果没有很好地定义。PHP将使用字符串“Array”来代替数组，并触发通知，指出这可能不是预期的结果，您应该检查这里的代码。你可能想要这样的东西:

echo $arr[0];  // displays foo
$str = 'Something ' . join(', ', $arr); //displays Something, foo, bar

或者循环数组:

foreach($arr as $key => $value) {
    echo "array $key = $value";
    // displays first: array 0 = foo
    // displays next:  array 1 = bar
}

如果这个通知出现在您意想不到的地方，这意味着您认为是字符串的变量实际上是一个数组。这意味着你的代码中有一个错误，使这个变量成为一个数组，而不是你期望的字符串。

致命错误:允许的内存大小XXX字节已耗尽(已尝试分配XXX字节)

没有足够的内存来运行脚本。PHP已达到内存限制并停止执行。这个错误是致命的，脚本停止。内存限制的值可以在php.ini文件中配置，也可以使用ini_set('memory_limit'， '128 M');在脚本中(将覆盖php.ini中定义的值)。内存限制的目的是防止一个PHP脚本占用所有可用内存，导致整个web服务器瘫痪。

The first thing to do is to minimise the amount of memory your script needs. For instance, if you're reading a large file into a variable or are fetching many records from a database and are storing them all in an array, that may use a lot of memory. Change your code to instead read the file line by line or fetch database records one at a time without storing them all in memory. This does require a bit of a conceptual awareness of what's going on behind the scenes and when data is stored in memory vs. elsewhere.

如果在脚本没有执行内存密集型工作时发生此错误，则需要检查代码以查看是否存在内存泄漏。memory_get_usage函数是您的朋友。

相关问题:

所有“Fatal error: Allowed memory size of XXX bytes exhausted”问题

注意:试图获取非对象错误的属性

在没有对象时试图访问对象的属性时发生。

非对象通知的一个典型例子是

$users = json_decode('[{"name": "hakre"}]');
echo $users->name; # Notice: Trying to get property of non-object

在本例中，$users是一个数组(因此不是一个对象)，它没有任何属性。

这类似于访问数组中不存在的索引或键(参见注意:未定义索引)。

这个例子简化了很多。大多数情况下，这样的通知表示一个未检查的返回值，例如，如果一个对象不存在，或者只是一个意外的非对象值(例如，在Xpath结果中，具有意外格式的JSON结构，具有意外格式的XML等)，库将返回NULL，但代码不会检查这样的条件。

由于这些非对象通常会被进一步处理，因此在对非对象调用对象方法时经常会发生致命错误(参见:致命错误:调用成员函数…在非对象上)停止脚本。

通过检查错误条件和/或变量是否符合期望，可以很容易地防止这种情况。下面是一个带有DOMXPath示例的通知:

$result  = $xpath->query("//*[@id='detail-sections']/div[1]");
$divText = $result->item(0)->nodeValue; # Notice: Trying to get property of non-object

问题是访问第一项的nodeValue属性(字段)，而没有检查它是否存在于$result集合中。相反，通过将变量分配给代码所操作的对象，可以使代码更加显式:

$result  = $xpath->query("//*[@id='detail-sections']/div[1]");
$div     = $result->item(0);
$divText = "-/-";
if (is_object($div)) {
    $divText = $div->nodeValue;
}
echo $divText;

相关的错误:

注意:未定义索引 致命错误:调用成员函数…在一个非物体上

mysql_connect(): user 'name'@'host'拒绝访问

当您连接到无效或缺少凭据(用户名/密码)的MySQL/MariaDB服务器时，会出现此警告。所以这通常不是代码问题，而是服务器配置问题。

See the manual page on mysql_connect("localhost", "user", "pw") for examples. Check that you actually used a $username and $password. It's uncommon that you gain access using no password - which is what happened when the Warning: said (using password: NO). Only the local test server usually allows to connect with username root, no password, and the test database name. You can test if they're really correct using the command line client: mysql --user="username" --password="password" testdb Username and password are case-sensitive and whitespace is not ignored. If your password contains meta characters like $, escape them, or put the password in single quotes. Most shared hosting providers predeclare mysql accounts in relation to the unix user account (sometimes just prefixes or extra numeric suffixes). See the docs for a pattern or documentation, and CPanel or whatever interface for setting a password. See the MySQL manual on Adding user accounts using the command line. When connected as admin user you can issue a query like: CREATE USER 'username'@'localhost' IDENTIFIED BY 'newpassword'; Or use Adminer or WorkBench or any other graphical tool to create, check or correct account details. If you can't fix your credentials, then asking the internet to "please help" will have no effect. Only you and your hosting provider have permissions and sufficient access to diagnose and fix things. Verify that you could reach the database server, using the host name given by your provider: ping dbserver.hoster.example.net Check this from a SSH console directly on your webserver. Testing from your local development client to your shared hosting server is rarely meaningful. Often you just want the server name to be "localhost", which normally utilizes a local named socket when available. Othertimes you can try "127.0.0.1" as fallback. Should your MySQL/MariaDB server listen on a different port, then use "servername:3306". If that fails, then there's a perhaps a firewall issue. (Off-topic, not a programming question. No remote guess-helping possible.) When using constants like e.g. DB_USER or DB_PASSWORD, check that they're actually defined. If you get a "Warning: Access defined for 'DB_USER'@'host'" and a "Notice: use of undefined constant 'DB_PASS'", then that's your problem. Verify that your e.g. xy/db-config.php was actually included and whatelse. Check for correctly set GRANT permissions. It's not sufficient to have a username+password pair. Each MySQL/MariaDB account can have an attached set of permissions. Those can restrict which databases you are allowed to connect to, from which client/server the connection may originate from, and which queries are permitted. The "Access denied" warning thus may as well show up for mysql_query calls, if you don't have permissions to SELECT from a specific table, or INSERT/UPDATE, and more commonly DELETE anything. You can adapt account permissions when connected per command line client using the admin account with a query like: GRANT ALL ON yourdb.* TO 'username'@'localhost'; If the warning shows up first with Warning: mysql_query(): Access denied for user ''@'localhost' then you may have a php.ini-preconfigured account/password pair. Check that mysql.default_user= and mysql.default_password= have meaningful values. Oftentimes this is a provider-configuration. So contact their support for mismatches. Find the documentation of your shared hosting provider: e.g. HostGator, GoDaddy, 1and1, DigitalOcean, BlueHost, DreamHost, MediaTemple, ixWebhosting, lunarhosting, or just google yours´. Else consult your webhosting provider through their support channels. Note that you may also have depleted the available connection pool. You'll get access denied warnings for too many concurrent connections. (You have to investigate the setup. That's an off-topic server configuration issue, not a programming question.) Your libmysql client version may not be compatible with the database server. Normally MySQL and MariaDB servers can be reached with PHPs compiled in driver. If you have a custom setup, or an outdated PHP version, and a much newer database server, or significantly outdated one - then the version mismatch may prevent connections. (No, you have to investigate yourself. Nobody can guess your setup).

更多的引用:

mysql服务器错误:mysql用户无法访问root用户 mysql_connect():拒绝访问 mysql_select_db()拒绝访问用户" @'localhost'(使用密码:NO) PHPMyAdmin拒绝用户“root”@“localhost”的访问

顺便说一句，你可能不想再使用mysql_*函数了。新来者经常迁移到mysqli，然而这也一样乏味。相反，阅读PDO和准备好的语句。 $db =新PDO("mysql:主机=localhost;dbname=testdb"， "用户名"，"密码");

解析错误:语法错误，意外的T_PAAMAYIM_NEKUDOTAYIM

范围解析操作符也被称为“Paamayim Nekudotayim”，源自希伯来语פייםנקדיים”。意思是“双冒号”。

如果您无意中在代码中放入::，则通常会发生此错误。

相关问题:

参考:PHP语法错误;以及如何解决这些问题? PHP中两个冒号是什么意思? 在PHP中::(双冒号)和->(箭头)之间的区别是什么? 意外T_PAAMAYIM_NEKUDOTAYIM，期望T_NS_Separator

文档:

范围解析运算符(::)

警告:数组到字符串的转换

注意:数组到字符串的转换

(PHP 7.4之前的一个通知，PHP 8.0之后的一个警告)

如果你试图将数组视为字符串，就会发生这种情况:

$arr = array('foo', 'bar');

echo $arr;  // Notice: Array to string conversion
$str = 'Something, ' . $arr;  // Notice: Array to string conversion

数组不能简单地与字符串回显或连接，因为结果没有很好地定义。PHP将使用字符串“Array”来代替数组，并触发通知，指出这可能不是预期的结果，您应该检查这里的代码。你可能想要这样的东西:

echo $arr[0];  // displays foo
$str = 'Something ' . join(', ', $arr); //displays Something, foo, bar

或者循环数组:

foreach($arr as $key => $value) {
    echo "array $key = $value";
    // displays first: array 0 = foo
    // displays next:  array 1 = bar
}

如果这个通知出现在您意想不到的地方，这意味着您认为是字符串的变量实际上是一个数组。这意味着你的代码中有一个错误，使这个变量成为一个数组，而不是你期望的字符串。