如何从数组中删除一个特定值? 类似 :

array.remove(value);

我必须使用核心核心核心JavaScript。 不允许框架 。


当前回答

Vanilla JavaScript(ES5.1) - (ES5.1) -已经到位版本版本

浏览器支持 :因特网探索者 9或以后(或以后(详细浏览器支持)

/**
 * Removes all occurences of the item from the array.
 *
 * Modifies the array “in place”, i.e. the array passed as an argument
 * is modified as opposed to creating a new array. Also returns the modified
 * array for your convenience.
 */
function removeInPlace(array, item) {
    var foundIndex, fromIndex;

    // Look for the item (the item can have multiple indices)
    fromIndex = array.length - 1;
    foundIndex = array.lastIndexOf(item, fromIndex);

    while (foundIndex !== -1) {
        // Remove the item (in place)
        array.splice(foundIndex, 1);

        // Bookkeeping
        fromIndex = foundIndex - 1;
        foundIndex = array.lastIndexOf(item, fromIndex);
    }

    // Return the modified array
    return array;
}

Vanilla JavaScript(ES5.1) - (ES5.1) -不可变版本版本

浏览器支持: 与原版的香草 JavaScript 相同

/**
 * Removes all occurences of the item from the array.
 *
 * Returns a new array with all the items of the original array except
 * the specified item.
 */
function remove(array, item) {
    var arrayCopy;

    arrayCopy = array.slice();

    return removeInPlace(arrayCopy, item);
}

香草ES6 -不可变版本版本

浏览器支持: Chrome 46, 边缘 12, Firefox 16, Opera 37, Safari 8 ()详细浏览器支持)

/**
 * Removes all occurences of the item from the array.
 *
 * Returns a new array with all the items of the original array except
 * the specified item.
 */
function remove(array, item) {
    // Copy the array
    array = [...array];

    // Look for the item (the item can have multiple indices)
    let fromIndex = array.length - 1;
    let foundIndex = array.lastIndexOf(item, fromIndex);

    while (foundIndex !== -1) {
        // Remove the item by generating a new array without it
        array = [
            ...array.slice(0, foundIndex),
            ...array.slice(foundIndex + 1),
        ];

        // Bookkeeping
        fromIndex = foundIndex - 1;
        foundIndex = array.lastIndexOf(item, fromIndex)
    }

    // Return the new array
    return array;
}

其他回答

尝试使用此代码filter方法,您可以从数组中删除任何特定项。

let arr = [1, 2, 3, 4, 5, 6, 7, 8, 9];
function removeItem(arr, value) {
  return arr.filter(function (ele) {
    return ele !== value;
  });
}
console.log(removeItem(arr, 6));

除了所有这些解决方案之外, 它也可以用阵列来完成. 减量...

const removeItem = 
    idx => 
    arr => 
    arr.reduce((acc, a, i) =>  idx === i ? acc : acc.concat(a), [])

const array = [1, 2, 3]
const index = 1

const newArray = removeItem(index)(array) 

console.log(newArray) // logs the following array to the console : [1, 3]

...或者一个循环函数(诚实地说不是那么优雅...也许有人有更好的循环解决方案? ? )...

const removeItemPrep = 
    acc => 
    i => 
    idx => 
    arr => 

    // If the index equals i, just feed in the unchanged accumulator(acc) else...
    i === idx ? removeItemPrep(acc)(i + 1)(idx)(arr) :

    // If the array length + 1 of the accumulator is smaller than the array length of the original array concatenate the array element at index i else... 
    acc.length + 1 < arr.length ? removeItemPrep(acc.concat(arr[i]))(i + 1)(idx)(arr) : 

    // return the accumulator
    acc 

const removeItem = removeItemPrep([])(0)

const array = [1, 2, 3]
const index = 1

const newArray = removeItem(index)(array) 

console.log(newArray) // logs the following array to the console : [1, 3]
Array.prototype.remove = function(x) {
    var y=this.slice(x+1);
    var z=[];
    for(i=0;i<=x-1;i++) {
        z[z.length] = this[i];
    }

    for(i=0;i<y.length;i++){
        z[z.length]=y[i];
    }

    return z;
}

使用不同种类数组的过滤器

    **simple array**
    const arr = ['1','2','3'];
    const updatedArr = arr.filter(e => e !== '3');
    console.warn(updatedArr);

    **array of object**
    const newArr = [{id:1,name:'a'},{id:2,name:'b'},{id:3,name:'c'}]
    const updatedNewArr = newArr.filter(e => e.id !== 3);
    console.warn(updatedNewArr);

    **array of object with different parameter name**
    const newArr = [{SINGLE_MDMC:{id:1,cout:10}},{BULK_MDMC:{id:1,cout:15}},{WPS_MDMC:{id:2,cout:10}},]
    const newArray = newArr.filter((item) => !Object.keys(item).includes('SINGLE_MDMC'));
    console.log(newArray)
function array_remove(arr, index) {
    for (let i = index; i < arr.length - 1; i++) {
        arr[i] = arr[i + 1];
    }
    arr.length -= 1;
    return arr;
}
my_arr = ['A', 'B', 'C', 'D'];
console.log(array_remove(my_arr, 0));