我试图读取一个大的csv文件(aprox。6 GB)在熊猫和我得到一个内存错误:

MemoryError                               Traceback (most recent call last)
<ipython-input-58-67a72687871b> in <module>()
----> 1 data=pd.read_csv('aphro.csv',sep=';')

...

MemoryError: 

有什么帮助吗?


当前回答

如果你有一个csv文件,有数百万个数据条目,你想要加载完整的数据集,你应该使用dask_cudf,

import dask_cudf as dc

df = dc.read_csv("large_data.csv")

其他回答

你可以尝试sframe,它和pandas有相同的语法,但是允许你操作比你的RAM大的文件。

除了上面的答案,对于那些想要处理CSV然后导出到CSV、parquet或SQL的人来说,d6tstack是另一个不错的选择。您可以加载多个文件,它处理数据模式更改(添加/删除列)。核心支持已经被剔除。

def apply(dfg):
    # do stuff
    return dfg

c = d6tstack.combine_csv.CombinerCSV([bigfile.csv], apply_after_read=apply, sep=',', chunksize=1e6)

# or
c = d6tstack.combine_csv.CombinerCSV(glob.glob('*.csv'), apply_after_read=apply, chunksize=1e6)

# output to various formats, automatically chunked to reduce memory consumption
c.to_csv_combine(filename='out.csv')
c.to_parquet_combine(filename='out.pq')
c.to_psql_combine('postgresql+psycopg2://usr:pwd@localhost/db', 'tablename') # fast for postgres
c.to_mysql_combine('mysql+mysqlconnector://usr:pwd@localhost/db', 'tablename') # fast for mysql
c.to_sql_combine('postgresql+psycopg2://usr:pwd@localhost/db', 'tablename') # slow but flexible

如果您使用pandas将大文件读入块,然后逐行yield,这是我所做的

import pandas as pd

def chunck_generator(filename, header=False,chunk_size = 10 ** 5):
   for chunk in pd.read_csv(filename,delimiter=',', iterator=True, chunksize=chunk_size, parse_dates=[1] ): 
        yield (chunk)

def _generator( filename, header=False,chunk_size = 10 ** 5):
    chunk = chunck_generator(filename, header=False,chunk_size = 10 ** 5)
    for row in chunk:
        yield row

if __name__ == "__main__":
filename = r'file.csv'
        generator = generator(filename=filename)
        while True:
           print(next(generator))

您可以将数据读入为块,并将每个块保存为pickle。

import pandas as pd 
import pickle

in_path = "" #Path where the large file is
out_path = "" #Path to save the pickle files to
chunk_size = 400000 #size of chunks relies on your available memory
separator = "~"

reader = pd.read_csv(in_path,sep=separator,chunksize=chunk_size, 
                    low_memory=False)    


for i, chunk in enumerate(reader):
    out_file = out_path + "/data_{}.pkl".format(i+1)
    with open(out_file, "wb") as f:
        pickle.dump(chunk,f,pickle.HIGHEST_PROTOCOL)

在下一步中,读入pickle并将每个pickle附加到所需的数据框架中。

import glob
pickle_path = "" #Same Path as out_path i.e. where the pickle files are

data_p_files=[]
for name in glob.glob(pickle_path + "/data_*.pkl"):
   data_p_files.append(name)


df = pd.DataFrame([])
for i in range(len(data_p_files)):
    df = df.append(pd.read_pickle(data_p_files[i]),ignore_index=True)

解决方案1:

使用大数据的熊猫

解决方案2:

TextFileReader = pd.read_csv(path, chunksize=1000)  # the number of rows per chunk

dfList = []
for df in TextFileReader:
    dfList.append(df)

df = pd.concat(dfList,sort=False)