我一直在安卓SDK平台上工作,现在还不清楚如何保存应用程序的状态。因此,考虑到“你好,Android”示例的这个小的重新设计:
package com.android.hello;
import android.app.Activity;
import android.os.Bundle;
import android.widget.TextView;
public class HelloAndroid extends Activity {
private TextView mTextView = null;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mTextView = new TextView(this);
if (savedInstanceState == null) {
mTextView.setText("Welcome to HelloAndroid!");
} else {
mTextView.setText("Welcome back.");
}
setContentView(mTextView);
}
}
我认为这对于最简单的情况来说已经足够了,但无论我如何离开应用程序,它总是以第一条消息来响应。
我确信解决方案就像重写onPause之类的东西一样简单,但我已经在文档中翻了大约30分钟,没有发现任何明显的东西。
我的同事写了一篇文章,解释了Android设备上的应用程序状态,包括活动生命周期和状态信息的解释,如何存储状态信息,以及保存到状态Bundle和SharedPreferences。看看这里。
本文涵盖三种方法:
使用实例状态包存储应用程序生存期(即临时)的本地变量/UI控制数据
[Code sample – Store state in state bundle]
@Override
public void onSaveInstanceState(Bundle savedInstanceState)
{
// Store UI state to the savedInstanceState.
// This bundle will be passed to onCreate on next call. EditText txtName = (EditText)findViewById(R.id.txtName);
String strName = txtName.getText().toString();
EditText txtEmail = (EditText)findViewById(R.id.txtEmail);
String strEmail = txtEmail.getText().toString();
CheckBox chkTandC = (CheckBox)findViewById(R.id.chkTandC);
boolean blnTandC = chkTandC.isChecked();
savedInstanceState.putString(“Name”, strName);
savedInstanceState.putString(“Email”, strEmail);
savedInstanceState.putBoolean(“TandC”, blnTandC);
super.onSaveInstanceState(savedInstanceState);
}
使用共享首选项在应用程序实例之间(即永久)存储本地变量/UI控制数据
[Code sample – store state in SharedPreferences]
@Override
protected void onPause()
{
super.onPause();
// Store values between instances here
SharedPreferences preferences = getPreferences(MODE_PRIVATE);
SharedPreferences.Editor editor = preferences.edit(); // Put the values from the UI
EditText txtName = (EditText)findViewById(R.id.txtName);
String strName = txtName.getText().toString();
EditText txtEmail = (EditText)findViewById(R.id.txtEmail);
String strEmail = txtEmail.getText().toString();
CheckBox chkTandC = (CheckBox)findViewById(R.id.chkTandC);
boolean blnTandC = chkTandC.isChecked();
editor.putString(“Name”, strName); // value to store
editor.putString(“Email”, strEmail); // value to store
editor.putBoolean(“TandC”, blnTandC); // value to store
// Commit to storage
editor.commit();
}
使用保留的非配置实例在应用程序生存期内的活动之间保持对象实例在内存中的活动状态
[Code sample – store object instance]
private cMyClassType moInstanceOfAClass; // Store the instance of an object
@Override
public Object onRetainNonConfigurationInstance()
{
if (moInstanceOfAClass != null) // Check that the object exists
return(moInstanceOfAClass);
return super.onRetainNonConfigurationInstance();
}
基本上有两种方法可以实现这一改变。
使用onSaveInstanceState()和onRestoreInstance State()。在manifestandroid:configChanges=“orientation|screenSize”中。
我真的不建议使用第二种方法。因为在我的一次体验中,它导致设备屏幕一半变黑,同时从纵向旋转到横向,反之亦然。
使用上面提到的第一种方法,我们可以在方向改变或任何配置改变时保存数据。我知道一种方法,可以在savedInstance状态对象中存储任何类型的数据。
示例:如果要持久化Json对象,请考虑一个案例。使用getter和setter创建一个模型类。
class MyModel extends Serializable{
JSONObject obj;
setJsonObject(JsonObject obj)
{
this.obj=obj;
}
JSONObject getJsonObject()
return this.obj;
}
}
现在,在onCreate和onSaveInstanceState方法中的活动中,执行以下操作。它看起来像这样:
@override
onCreate(Bundle savedInstaceState){
MyModel data= (MyModel)savedInstaceState.getSerializable("yourkey")
JSONObject obj=data.getJsonObject();
//Here you have retained JSONObject and can use.
}
@Override
protected void onSaveInstanceState(Bundle outState) {
super.onSaveInstanceState(outState);
//Obj is some json object
MyModel dataToSave= new MyModel();
dataToSave.setJsonObject(obj);
oustate.putSerializable("yourkey",dataToSave);
}
现在,在视图模型中使用两种方法是有意义的。如果要将第一个保存为保存的实例:您可以像这样在视图模型中添加状态参数https://developer.android.com/topic/libraries/architecture/viewmodel-savedstate#java
或者您可以在视图模型中保存变量或对象,在这种情况下,视图模型将保存生命周期,直到活动被破坏。
public class HelloAndroidViewModel extends ViewModel {
public Booelan firstInit = false;
public HelloAndroidViewModel() {
firstInit = false;
}
...
}
public class HelloAndroid extends Activity {
private TextView mTextView = null;
HelloAndroidViewModel viewModel = ViewModelProviders.of(this).get(HelloAndroidViewModel.class);
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
mTextView = new TextView(this);
//Because even if the state is deleted, the data in the viewmodel will be kept because the activity does not destroy
if(!viewModel.firstInit){
viewModel.firstInit = true
mTextView.setText("Welcome to HelloAndroid!");
}else{
mTextView.setText("Welcome back.");
}
setContentView(mTextView);
}
}
虽然公认的答案是正确的,但有一种更快、更容易的方法可以使用名为Icepick的库在Android上保存“活动”状态。Icepick是一个注释处理器,它负责为您保存和恢复状态时使用的所有样板代码。
对Icepick:
class MainActivity extends Activity {
@State String username; // These will be automatically saved and restored
@State String password;
@State int age;
@Override public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
Icepick.restoreInstanceState(this, savedInstanceState);
}
@Override public void onSaveInstanceState(Bundle outState) {
super.onSaveInstanceState(outState);
Icepick.saveInstanceState(this, outState);
}
}
与执行以下操作相同:
class MainActivity extends Activity {
String username;
String password;
int age;
@Override
public void onSaveInstanceState(Bundle savedInstanceState) {
super.onSaveInstanceState(savedInstanceState);
savedInstanceState.putString("MyString", username);
savedInstanceState.putString("MyPassword", password);
savedInstanceState.putInt("MyAge", age);
/* remember you would need to actually initialize these variables before putting it in the
Bundle */
}
@Override
public void onRestoreInstanceState(Bundle savedInstanceState) {
super.onRestoreInstanceState(savedInstanceState);
username = savedInstanceState.getString("MyString");
password = savedInstanceState.getString("MyPassword");
age = savedInstanceState.getInt("MyAge");
}
}
Icepick可以处理任何使用Bundle保存其状态的对象。