我有一个非常简单的JavaScript数组，可能包含也可能不包含重复项。
var names = ["Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl"];
我需要删除重复项并将唯一值放入新数组。
我可以指出我尝试过的所有代码，但我认为它们没有用，因为它们不起作用。我也接受jQuery解决方案。
类似的问题：
获取数组中的所有非唯一值（即：重复/多次出现）
当前回答
如果不想包含整个库，可以使用此选项添加任何数组都可以使用的方法：
Array.prototype.uniq = function uniq() {
return this.reduce(function(accum, cur) {
if (accum.indexOf(cur) === -1) accum.push(cur);
return accum;
}, [] );
}
["Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl"].uniq()
其他回答
这里非常简单，可以在任何地方（甚至在PhotoshopScript中）理解和工作代码。检查一下！
var peoplenames = new Array("Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl");
peoplenames = unique(peoplenames);
alert(peoplenames);
function unique(array){
var len = array.length;
for(var i = 0; i < len; i++) for(var j = i + 1; j < len; j++)
if(array[j] == array[i]){
array.splice(j,1);
j--;
len--;
}
return array;
}
//*result* peoplenames == ["Mike","Matt","Nancy","Adam","Jenny","Carl"]
使用jQuery快速而肮脏：
var names = ["Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl"];
var uniqueNames = [];
$.each(names, function(i, el){
if($.inArray(el, uniqueNames) === -1) uniqueNames.push(el);
});
var lines = ["Mike", "Matt", "Nancy", "Adam", "Jenny", "Nancy", "Carl"];
var uniqueNames = [];
for(var i = 0; i < lines.length; i++)
{
if(uniqueNames.indexOf(lines[i]) == -1)
uniqueNames.push(lines[i]);
}
if(uniqueNames.indexOf(uniqueNames[uniqueNames.length-1])!= -1)
uniqueNames.pop();
for(var i = 0; i < uniqueNames.length; i++)
{
document.write(uniqueNames[i]);
document.write("<br/>");
}
以下脚本返回仅包含唯一值的新数组。它适用于字符串和数字。不需要额外的库，只需要普通的JS。
浏览器支持：
Feature Chrome Firefox (Gecko) Internet Explorer Opera Safari
Basic support (Yes) 1.5 (1.8) 9 (Yes) (Yes)
https://jsfiddle.net/fzmcgcxv/3/
var duplicates = ["Mike","Matt","Nancy","Adam","Jenny","Nancy","Carl","Mike","Mike","Nancy","Carl"];
var unique = duplicates.filter(function(elem, pos) {
return duplicates.indexOf(elem) == pos;
});
alert(unique);
这里是另一种使用jQuery的方法，
function uniqueArray(array){
if ($.isArray(array)){
var dupes = {}; var len, i;
for (i=0,len=array.length;i<len;i++){
var test = array[i].toString();
if (dupes[test]) { array.splice(i,1); len--; i--; } else { dupes[test] = true; }
}
}
else {
if (window.console) console.log('Not passing an array to uniqueArray, returning whatever you sent it - not filtered!');
return(array);
}
return(array);
}
作者：William Skidmore
