有没有办法用JavaScript生成指定范围内的随机数?

例如:指定范围从1到6,随机数可以是1、2、3、4、5或6。


当前回答

范围[a,b]内的加密强随机整数(假设:a<b)

let rand=(a,b)=>a+(b-a+1)*crypto.getRandomValues(新Uint32Array(1))[0]/2**32|0console.log(兰特(1,6));

其他回答

数学不是我的强项,但我一直在做一个项目,我需要在正负之间生成很多随机数。

function randomBetween(min, max) {
    if (min < 0) {
        return min + Math.random() * (Math.abs(min)+max);
    }else {
        return min + Math.random() * max;
    }
}

例如

randomBetween(-10,15)//or..
randomBetween(10,20)//or...
randomBetween(-200,-100)

当然,您也可以添加一些验证,以确保您不使用数字以外的任何内容。还要确保最小值始终小于或等于最大值。

这应该是有效的:

const getRandomNum = (min, max) => Math.floor(Math.random() * (max - min + 1)) + min

尝试使用:

函数随机(最小值,最大值){return Math.round((Math.random()*(Math.abs(max-min)))+min);}console.log(随机(1,6));

其他解决方案:

(数学随机()*6|0)+1~~(数学随机()*6)+1

联机尝试

如果您想覆盖负数和正数,并确保其安全,请使用以下方法:

JS解决方案:

function generateRangom(low, up) {
  const u = Math.max(low, up);
  const l = Math.min(low, up);
  const diff = u - l;
  const r = Math.floor(Math.random() * (diff + 1)); //'+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
  
  return l + r; //add the random number that was selected within distance between low and up to the lower limit.  
}

Java解决方案:

public static int generateRandom(int low, int up) {
        int l = Math.min(low, up);
        int u = Math.max(low, up);
        int diff = u - l;

        int r = (int) Math.floor(Math.random() * (diff + 1)); // '+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
  
        return l + r;//add the random number that was selected within distance between low and up to the lower limit.      
}