基本上像骰子一样返回1-6，

return Math.round(Math.random() * 5 + 1);

获取0到400之间的随机整数

let rand=数学舍入（Math.random（）*400）document.write（兰特）

获取200到1500之间的随机整数

让范围＝｛min:200，max:1500｝设delta=范围.max-范围.minconst rand=数学舍入（range.min+Math.random（）*delta）document.write（兰特）

使用函数

函数randBetween（最小值，最大值）{设delta=最大值-最小值return Math.round（min+Math.random（）*delta）}document.write（randBetween（10，15））；

//JavaScript ES6箭头函数常量randBetween=（最小值，最大值）=>{设delta=最大值-最小值return Math.round（min+Math.random（）*delta）}document.write（randBetween（10，20））

var x = 6; // can be any number
var rand = Math.floor(Math.random()*x) + 1;

如果您想覆盖负数和正数，并确保其安全，请使用以下方法：

JS解决方案：

function generateRangom(low, up) {
  const u = Math.max(low, up);
  const l = Math.min(low, up);
  const diff = u - l;
  const r = Math.floor(Math.random() * (diff + 1)); //'+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
  
  return l + r; //add the random number that was selected within distance between low and up to the lower limit.  
}

Java解决方案：

public static int generateRandom(int low, int up) {
        int l = Math.min(low, up);
        int u = Math.max(low, up);
        int diff = u - l;

        int r = (int) Math.floor(Math.random() * (diff + 1)); // '+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
  
        return l + r;//add the random number that was selected within distance between low and up to the lower limit.      
}

范围[a，b]内的加密强随机整数（假设：a<b）

let rand=（a，b）=>a+（b-a+1）*crypto.getRandomValues（新Uint32Array（1））[0]/2**32|0console.log（兰特（1,6））；

我发现了一种使用ES6默认参数实现这一点的新方法。它非常漂亮，因为它允许一个参数或两个参数。这里是：

function random(n, b = 0) {
    return Math.random() * (b-n) + n;
}