有没有办法用JavaScript生成指定范围内的随机数?
例如:指定范围从1到6,随机数可以是1、2、3、4、5或6。
有没有办法用JavaScript生成指定范围内的随机数?
例如:指定范围从1到6,随机数可以是1、2、3、4、5或6。
当前回答
如果您想覆盖负数和正数,并确保其安全,请使用以下方法:
JS解决方案:
function generateRangom(low, up) {
const u = Math.max(low, up);
const l = Math.min(low, up);
const diff = u - l;
const r = Math.floor(Math.random() * (diff + 1)); //'+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
return l + r; //add the random number that was selected within distance between low and up to the lower limit.
}
Java解决方案:
public static int generateRandom(int low, int up) {
int l = Math.min(low, up);
int u = Math.max(low, up);
int diff = u - l;
int r = (int) Math.floor(Math.random() * (diff + 1)); // '+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
return l + r;//add the random number that was selected within distance between low and up to the lower limit.
}
其他回答
尽管有许多答案,但结果几乎相同。我想补充一下我的答案并解释一下它的作用。因为理解它的工作方式比复制粘贴单行代码更重要。生成随机数只是简单的数学。
代码:
function getR(lower, upper) {
var percent = (Math.random() * 100);
// this will return number between 0-99 because Math.random returns decimal number from 0-0.9929292 something like that
//now you have a percentage, use it find out the number between your INTERVAL :upper-lower
var num = ((percent * (upper - lower) / 100));
//num will now have a number that falls in your INTERVAL simple maths
num += lower;
//add lower to make it fall in your INTERVAL
//but num is still in decimal
//use Math.floor>downward to its nearest integer you won't get upper value ever
//use Math.ceil>upward to its nearest integer upper value is possible
//Math.round>to its nearest integer 2.4>2 2.5>3 both lower and upper value possible
console.log(Math.floor(num), Math.ceil(num), Math.round(num));
}
TL;博士
function generateRandomInteger(min, max) {
return Math.floor(min + Math.random()*(max - min + 1))
}
要获得随机数generateRandomInteger(-20,20);
下面的解释
整数-不是分数的数字;整数
我们需要得到一个随机数,比如最小值和最大值之间的X。十、 min和max都是整数
即最小<=X<=最大
如果我们从方程中减去min,这相当于
0<=(X-最小)<=(最大-最小)
现在,让我们将其与随机数r相乘这是
0<=(X-分钟)*r<=(最大-分钟)*r
现在,让我们把min加回到等式中
最小<=最小+(X-最小)*r<=最小值+(最大-最小)*r
对于任何给定的X,只有当r的范围为[0,1]时,上述方程才满足。对于r的任何其他值,上述方程都不满足。
在此处了解范围[x,y]或(x,y)的更多信息
我们的下一步是找到一个函数,该函数总是产生范围为[0,1]的值
现在,r的范围,即[0,1]与Javascript中的Math.random()函数非常相似。不是吗?
函数的作用是:返回浮点伪随机范围[0,1)内的数字;即从0(含0)到但不包括1(不含)
使用Math.Random()的随机函数0<=r<1
注意,在Math.random()中,左边界是包含的,右边界是排他的。这意味着min+(max-min)*r的取值范围为[min,max)
为了包括我们的右边界,即[min,max],我们将右边界增加1,并将结果下限。
function generateRandomInteger(min, max) {
return Math.floor(min + Math.random()*(max - min + 1))
}
要获得随机数
generateRandomInteger(-20,20);
此函数可以生成介于(包括)最小值和最大值之间的随机整数:
function randomNumber(min, max) {
if (min > max) {
let temp = max;
max = min;
min = temp;
}
if (min <= 0) {
return Math.floor(Math.random() * (max + Math.abs(min) + 1)) + min;
} else {
return Math.floor(Math.random() * (max - min + 1)) + min;
}
}
例子:
randomNumber(-2, 3); // can be -2, -1, 0, 1, 2 and 3
randomNumber(-5, -2); // can be -5, -4, -3 and -2
randomNumber(0, 4); // can be 0, 1, 2, 3 and 4
randomNumber(4, 0); // can be 0, 1, 2, 3 and 4
尝试使用:
函数随机(最小值,最大值){return Math.round((Math.random()*(Math.abs(max-min)))+min);}console.log(随机(1,6));
如果您想覆盖负数和正数,并确保其安全,请使用以下方法:
JS解决方案:
function generateRangom(low, up) {
const u = Math.max(low, up);
const l = Math.min(low, up);
const diff = u - l;
const r = Math.floor(Math.random() * (diff + 1)); //'+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
return l + r; //add the random number that was selected within distance between low and up to the lower limit.
}
Java解决方案:
public static int generateRandom(int low, int up) {
int l = Math.min(low, up);
int u = Math.max(low, up);
int diff = u - l;
int r = (int) Math.floor(Math.random() * (diff + 1)); // '+1' because Math.random() returns 0..0.99, it does not include 'diff' value, so we do +1, so 'diff + 1' won't be included, but just 'diff' value will be.
return l + r;//add the random number that was selected within distance between low and up to the lower limit.
}