我想对所有的医护人员说:

 
SELECT
s.NOTE_ID
,STUFF ((
        SELECT
           [note_text] + ' ' 
        FROM
            HNO_NOTE_TEXT s1
        WHERE
            (s1.NOTE_ID = s.NOTE_ID)
        ORDER BY [line] ASC
         FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
         ,
        1,
        2,
        '') AS NOTE_TEXT_CONCATINATED
FROM
    HNO_NOTE_TEXT s
    GROUP BY NOTE_ID
 

使用Sql Server 2005及以上版本的另一种选择

---- test data
declare @t table (OUTPUTID int, SCHME varchar(10), DESCR varchar(10))
insert @t select 1125439       ,'CKT','Approved'
insert @t select 1125439       ,'RENO','Approved'
insert @t select 1134691       ,'CKT','Approved'
insert @t select 1134691       ,'RENO','Approved'
insert @t select 1134691       ,'pn','Approved'

---- actual query
;with cte(outputid,combined,rn)
as
(
  select outputid, SCHME + ' ('+DESCR+')', rn=ROW_NUMBER() over (PARTITION by outputid order by schme, descr)
  from @t
)
,cte2(outputid,finalstatus,rn)
as
(
select OUTPUTID, convert(varchar(max),combined), 1 from cte where rn=1
union all
select cte2.outputid, convert(varchar(max),cte2.finalstatus+', '+cte.combined), cte2.rn+1
from cte2
inner join cte on cte.OUTPUTID = cte2.outputid and cte.rn=cte2.rn+1
)
select outputid, MAX(finalstatus) from cte2 group by outputid

一个例子是

在Oracle中可以使用LISTAGG聚合函数。

原始记录

name   type
------------
name1  type1
name2  type2
name2  type3

Sql

SELECT name, LISTAGG(type, '; ') WITHIN GROUP(ORDER BY name)
FROM table
GROUP BY name

导致

name   type
------------
name1  type1
name2  type2; type3

另一个不带垃圾的例子:"，TYPE).value('(./text())[1]'，'VARCHAR(MAX)')"

WITH t AS (
    SELECT 1 n, 1 g, 1 v
    UNION ALL 
    SELECT 2 n, 1 g, 2 v
    UNION ALL 
    SELECT 3 n, 2 g, 3 v
)
SELECT g
        , STUFF (
                (
                    SELECT ', ' + CAST(v AS VARCHAR(MAX))
                    FROM t sub_t
                    WHERE sub_t.g = main_t.g
                    FOR XML PATH('')
                )
                , 1, 2, ''
        ) cg
FROM t main_t
GROUP BY g

输入-输出是

*************************   ->  *********************
*   n   *   g   *   v   *       *   g   *   cg      *
*   -   *   -   *   -   *       *   -   *   -       *
*   1   *   1   *   1   *       *   1   *   1, 2    *
*   2   *   1   *   2   *       *   2   *   3       *
*   3   *   2   *   3   *       *********************
*************************   

不需要游标，WHILE循环或用户定义函数。

只需要创造性地使用FOR XML和PATH。

[注意:此解决方案仅适用于SQL 2005及更高版本。原来的问题没有指定使用的版本。

CREATE TABLE #YourTable ([ID] INT, [Name] CHAR(1), [Value] INT)

INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'A',4)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (1,'B',8)
INSERT INTO #YourTable ([ID],[Name],[Value]) VALUES (2,'C',9)

SELECT 
  [ID],
  STUFF((
    SELECT ', ' + [Name] + ':' + CAST([Value] AS VARCHAR(MAX)) 
    FROM #YourTable 
    WHERE (ID = Results.ID) 
    FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
  ,1,2,'') AS NameValues
FROM #YourTable Results
GROUP BY ID

DROP TABLE #YourTable

我使用了这种方法，可能更容易掌握。获取一个根元素，然后连接到具有相同ID但不是“正式”名称的选项

  Declare @IdxList as Table(id int, choices varchar(max),AisName varchar(255))
  Insert into @IdxLIst(id,choices,AisName)
  Select IdxId,''''+Max(Title)+'''',Max(Title) From [dbo].[dta_Alias] 
 where IdxId is not null group by IdxId
  Update @IdxLIst
    set choices=choices +','''+Title+''''
    From @IdxLIst JOIN [dta_Alias] ON id=IdxId And Title <> AisName
    where IdxId is not null
    Select * from @IdxList where choices like '%,%'