假设我有一个字符串:
string str = "1111222233334444";
我如何把这个字符串分成一定大小的块?
例如,将它分解为4的大小将返回字符串:
"1111"
"2222"
"3333"
"4444"
假设我有一个字符串:
string str = "1111222233334444";
我如何把这个字符串分成一定大小的块?
例如,将它分解为4的大小将返回字符串:
"1111"
"2222"
"3333"
"4444"
当前回答
最近我不得不在工作中写一些东西来完成这个任务,所以我想我会把我对这个问题的解决方案贴出来。作为一个额外的好处,这个解决方案的功能提供了一种方法,以相反的方向分割字符串,并且它正确地处理上面Marvin Pinto提到的unicode字符。所以,就是这样:
using System;
using Extensions;
namespace TestCSharp
{
class Program
{
static void Main(string[] args)
{
string asciiStr = "This is a string.";
string unicodeStr = "これは文字列です。";
string[] array1 = asciiStr.Split(4);
string[] array2 = asciiStr.Split(-4);
string[] array3 = asciiStr.Split(7);
string[] array4 = asciiStr.Split(-7);
string[] array5 = unicodeStr.Split(5);
string[] array6 = unicodeStr.Split(-5);
}
}
}
namespace Extensions
{
public static class StringExtensions
{
/// <summary>Returns a string array that contains the substrings in this string that are seperated a given fixed length.</summary>
/// <param name="s">This string object.</param>
/// <param name="length">Size of each substring.
/// <para>CASE: length > 0 , RESULT: String is split from left to right.</para>
/// <para>CASE: length == 0 , RESULT: String is returned as the only entry in the array.</para>
/// <para>CASE: length < 0 , RESULT: String is split from right to left.</para>
/// </param>
/// <returns>String array that has been split into substrings of equal length.</returns>
/// <example>
/// <code>
/// string s = "1234567890";
/// string[] a = s.Split(4); // a == { "1234", "5678", "90" }
/// </code>
/// </example>
public static string[] Split(this string s, int length)
{
System.Globalization.StringInfo str = new System.Globalization.StringInfo(s);
int lengthAbs = Math.Abs(length);
if (str == null || str.LengthInTextElements == 0 || lengthAbs == 0 || str.LengthInTextElements <= lengthAbs)
return new string[] { str.ToString() };
string[] array = new string[(str.LengthInTextElements % lengthAbs == 0 ? str.LengthInTextElements / lengthAbs: (str.LengthInTextElements / lengthAbs) + 1)];
if (length > 0)
for (int iStr = 0, iArray = 0; iStr < str.LengthInTextElements && iArray < array.Length; iStr += lengthAbs, iArray++)
array[iArray] = str.SubstringByTextElements(iStr, (str.LengthInTextElements - iStr < lengthAbs ? str.LengthInTextElements - iStr : lengthAbs));
else // if (length < 0)
for (int iStr = str.LengthInTextElements - 1, iArray = array.Length - 1; iStr >= 0 && iArray >= 0; iStr -= lengthAbs, iArray--)
array[iArray] = str.SubstringByTextElements((iStr - lengthAbs < 0 ? 0 : iStr - lengthAbs + 1), (iStr - lengthAbs < 0 ? iStr + 1 : lengthAbs));
return array;
}
}
}
此外,这里还有一个运行此代码结果的图像链接:http://i.imgur.com/16Iih.png
其他回答
使用正则表达式和Linq:
List<string> groups = (from Match m in Regex.Matches(str, @"\d{4}")
select m.Value).ToList();
我觉得这样更有可读性,但这只是个人观点。它也可以是一行代码:)。
static IEnumerable<string> Split(string str, int chunkSize)
{
IEnumerable<string> retVal = Enumerable.Range(0, str.Length / chunkSize)
.Select(i => str.Substring(i * chunkSize, chunkSize))
if (str.Length % chunkSize > 0)
retVal = retVal.Append(str.Substring(str.Length / chunkSize * chunkSize, str.Length % chunkSize));
return retVal;
}
它正确地处理不能被chunkSize整除的输入字符串长度。
请注意,可能需要额外的代码来优雅地处理边缘情况(null或空输入字符串,chunkSize == 0)。
static IEnumerable<string> Split(string str, double chunkSize)
{
return Enumerable.Range(0, (int) Math.Ceiling(str.Length/chunkSize))
.Select(i => new string(str
.Skip(i * (int)chunkSize)
.Take((int)chunkSize)
.ToArray()));
}
另一种方法是:
using System;
using System.Collections.Generic;
using System.Linq;
public class Program
{
public static void Main()
{
var x = "Hello World";
foreach(var i in x.ChunkString(2)) Console.WriteLine(i);
}
}
public static class Ext{
public static IEnumerable<string> ChunkString(this string val, int chunkSize){
return val.Select((x,i) => new {Index = i, Value = x})
.GroupBy(x => x.Index/chunkSize, x => x.Value)
.Select(x => string.Join("",x));
}
}
static List<string> GetChunks(string value, int chunkLength)
{
var res = new List<string>();
int count = (value.Length / chunkLength) + (value.Length % chunkLength > 0 ? 1 : 0);
Enumerable.Range(0, count).ToList().ForEach(f => res.Add(value.Skip(f * chunkLength).Take(chunkLength).Select(z => z.ToString()).Aggregate((a,b) => a+b)));
return res;
}
demo
for (int i = 0; i <= Convert.ToInt32(Math.Truncate(Convert.ToDecimal(_string.Length / _chunkSize))); i++)
{
var _currentChunk = _string.Substring(i * _chunkSize, Math.Min(_chunkSize, _string.Length - i * _chunkSize));
//do something with current chunk
}