我需要列出SQL Server数据库中的所有触发器表名和表的模式。

我马上就要讲到这个了:

SELECT trigger_name = name, trigger_owner = USER_NAME(uid),table_schema = , table_name = OBJECT_NAME(parent_obj),
  isupdate = OBJECTPROPERTY( id, 'ExecIsUpdateTrigger'), isdelete = OBJECTPROPERTY( id, 'ExecIsDeleteTrigger'),
  isinsert = OBJECTPROPERTY( id, 'ExecIsInsertTrigger'), isafter = OBJECTPROPERTY( id, 'ExecIsAfterTrigger'),
  isinsteadof = OBJECTPROPERTY( id, 'ExecIsInsteadOfTrigger'),
  [disabled] = OBJECTPROPERTY(id, 'ExecIsTriggerDisabled') 
FROM sysobjects INNER JOIN sysusers ON sysobjects.uid = sysusers.uid
WHERE type = 'TR'

我还需要得到表的模式。


当前回答

SELECT
   ServerName   = @@servername,
   DatabaseName = db_name(),
   SchemaName   = isnull( s.name, '' ),
   TableName    = isnull( o.name, 'DDL Trigger' ),
   TriggerName  = t.name, 
   Defininion   = object_definition( t.object_id )

FROM sys.triggers t
   LEFT JOIN sys.all_objects o
      ON t.parent_id = o.object_id
   LEFT JOIN sys.schemas s
      ON s.schema_id = o.schema_id
ORDER BY 
   SchemaName,
   TableName,
   TriggerName

其他回答

使用此查询:

    SELECT     
        DB_NAME() AS DataBaseName,  
        S.Name AS SchemaName,               
        T.name AS TableName,
        dbo.SysObjects.Name AS TriggerName,
        dbo.sysComments.Text AS SqlContent,
    FROM dbo.SysObjects 
    INNER JOIN dbo.sysComments ON dbo.SysObjects.ID = dbo.sysComments.ID
    INNER JOIN sys.tables AS T ON sysobjects.parent_obj = t.object_id 
    INNER JOIN sys.schemas AS S ON t.schema_id = s.schema_id 
    WHERE dbo.SysObjects.xType = 'TR' 
        AND dbo.SysObjects.Name LIKE 'Permit_AfterInsert' ---- <----- HERE

一个困难是文本或描述有换行。我的笨拙的拼凑,使它在更表格的东西,是添加一个HTML文字到SELECT子句,复制并粘贴到记事本,保存与HTML扩展,在浏览器中打开,然后复制并粘贴到一个电子表格。 例子

SELECT obj.NAME AS TBL,trg.name,sm.definition,'<br>'
FROM SYS.OBJECTS obj
LEFT JOIN (SELECT trg1.object_id,trg1.parent_object_id,trg1.name FROM sys.objects trg1 WHERE trg1.type='tr' AND trg1.name like 'update%') trg
 ON obj.object_id=trg.parent_object_id
LEFT JOIN (SELECT sm1.object_id,sm1.definition FROM sys.sql_modules sm1 where sm1.definition like '%suser_sname()%') sm ON trg.object_id=sm.object_id
WHERE obj.type='u'
ORDER BY obj.name;

你可能仍然需要使用标签将描述放到一个字段中,但至少它会在一行上,我发现这非常有帮助。

不需要与其他表连接…所有信息都可以从sys.objects中获取。

SELECT  name as trigger_name
, object_name(parent_obj) as tableName
, object_schema_name(parent_obj) as schemaName 
,OBJECTPROPERTY( id, 'ExecIsUpdateTrigger') AS isupdate 
,OBJECTPROPERTY( id, 'ExecIsDeleteTrigger') AS isdelete 
,OBJECTPROPERTY( id, 'ExecIsInsertTrigger') AS isinsert 
,OBJECTPROPERTY( id, 'ExecIsAfterTrigger') AS isafter 
,OBJECTPROPERTY( id, 'ExecIsInsteadOfTrigger') AS isinsteadof 
,OBJECTPROPERTY(id, 'ExecIsTriggerDisabled') AS [disabled] 
FROM    sysobjects s
WHERE s.type = 'TR' 

c# Cribs:我最终得到了这个超级通用的一行程序。希望这对原始海报和/或刚刚输入我在谷歌中做的相同问题的人都有用:

SELECT TriggerRecord.name as TriggerName,ParentRecord.name as ForTableName 
FROM sysobjects TriggerRecord 
INNER JOIN sysobjects ParentRecord ON TriggerRecord.parent_obj=ParentRecord.id 
WHERE TriggerRecord.xtype='TR'

查询特点:

可用于任何SQL数据库(即初始目录) 自我解释 一个简单的陈述 可以直接粘贴到大多数语言的大多数IDE中

你觉得这个怎么样?非常简洁:)

SELECT OBJECT_NAME(parent_id) Table_or_ViewNM,
      name TriggerNM,
      is_instead_of_trigger,
      is_disabled
FROM sys.triggers
WHERE parent_class_desc = 'OBJECT_OR_COLUMN'
ORDER BY OBJECT_NAME(parent_id),
Name ;