SELECT
    OBJECT_NAME(PARENT_OBJECT_ID) AS PARENT_TABLE,
    OBJECT_NAME(OBJECT_ID) TRIGGER_TABLE,
    *
FROM
SYS.OBJECTS
WHERE TYPE = 'TR'

c# Cribs:我最终得到了这个超级通用的一行程序。希望这对原始海报和/或刚刚输入我在谷歌中做的相同问题的人都有用:

SELECT TriggerRecord.name as TriggerName,ParentRecord.name as ForTableName 
FROM sysobjects TriggerRecord 
INNER JOIN sysobjects ParentRecord ON TriggerRecord.parent_obj=ParentRecord.id 
WHERE TriggerRecord.xtype='TR'

查询特点:

可用于任何SQL数据库(即初始目录) 自我解释 一个简单的陈述 可以直接粘贴到大多数语言的大多数IDE中

我最近有同样的任务，我使用以下sql server 2012 db。使用management studio并连接到要搜索的数据库。然后执行以下脚本。

Select 
[tgr].[name] as [trigger name], 
[tbl].[name] as [table name]

from sysobjects tgr 

join sysobjects tbl
on tgr.parent_obj = tbl.id

WHERE tgr.xtype = 'TR'

使用此查询:

    SELECT     
        DB_NAME() AS DataBaseName,  
        S.Name AS SchemaName,               
        T.name AS TableName,
        dbo.SysObjects.Name AS TriggerName,
        dbo.sysComments.Text AS SqlContent,
    FROM dbo.SysObjects 
    INNER JOIN dbo.sysComments ON dbo.SysObjects.ID = dbo.sysComments.ID
    INNER JOIN sys.tables AS T ON sysobjects.parent_obj = t.object_id 
    INNER JOIN sys.schemas AS S ON t.schema_id = s.schema_id 
    WHERE dbo.SysObjects.xType = 'TR' 
        AND dbo.SysObjects.Name LIKE 'Permit_AfterInsert' ---- <----- HERE

SELECT tbl.name as Table_Name,trig.name as Trigger_Name,trig.is_disabled  
FROM [sys].[triggers] as trig inner join sys.tables as tbl on 
trig.parent_id = tbl.object_id 

SELECT
   ServerName   = @@servername,
   DatabaseName = db_name(),
   SchemaName   = isnull( s.name, '' ),
   TableName    = isnull( o.name, 'DDL Trigger' ),
   TriggerName  = t.name, 
   Defininion   = object_definition( t.object_id )

FROM sys.triggers t
   LEFT JOIN sys.all_objects o
      ON t.parent_id = o.object_id
   LEFT JOIN sys.schemas s
      ON s.schema_id = o.schema_id
ORDER BY 
   SchemaName,
   TableName,
   TriggerName