我已经创建了一个自定义UITableViewCell。表视图很好地显示了数据。我陷入的是当用户触摸tableview的单元格时,然后我想显示单元格的背景颜色,而不是默认的[蓝色]值,以突出显示单元格的选择。 我使用这段代码,但什么都没有发生:
cell.selectedBackgroundView.backgroundColor=[UIColor blackColor];
我已经创建了一个自定义UITableViewCell。表视图很好地显示了数据。我陷入的是当用户触摸tableview的单元格时,然后我想显示单元格的背景颜色,而不是默认的[蓝色]值,以突出显示单元格的选择。 我使用这段代码,但什么都没有发生:
cell.selectedBackgroundView.backgroundColor=[UIColor blackColor];
当前回答
如果你有一个分组表,每个部分只有一个单元格,只需在代码中添加额外的一行: bgColorView.layer.cornerRadius = 10;
UIView *bgColorView = [[UIView alloc] init];
[bgColorView setBackgroundColor:[UIColor redColor]];
bgColorView.layer.cornerRadius = 10;
[cell setSelectedBackgroundView:bgColorView];
[bgColorView release];
不要忘记导入QuartzCore。
其他回答
再一个提示基督教的方式显示圆角背景分组表。
如果我为单元格使用cornerRadius = 10,它会显示四个角的圆角选择背景。这和表格视图的默认UI不一样。
所以,我想用简单的方法来解决它。 正如你可以从下面的代码中看到的,检查单元格的位置(顶部,底部,中间或顶部底部),并添加更多的子层来隐藏顶部角或底部角。这只是显示了与默认表视图的选择背景完全相同的外观。
我用iPad splitterview测试了这段代码。你可以根据需要改变patchLayer的帧位置。
请让我知道是否有更简单的方法来达到同样的效果。
if (tableView.style == UITableViewStyleGrouped)
{
if (indexPath.row == 0)
{
cellPosition = CellGroupPositionAtTop;
}
else
{
cellPosition = CellGroupPositionAtMiddle;
}
NSInteger numberOfRows = [tableView numberOfRowsInSection:indexPath.section];
if (indexPath.row == numberOfRows - 1)
{
if (cellPosition == CellGroupPositionAtTop)
{
cellPosition = CellGroupPositionAtTopAndBottom;
}
else
{
cellPosition = CellGroupPositionAtBottom;
}
}
if (cellPosition != CellGroupPositionAtMiddle)
{
bgColorView.layer.cornerRadius = 10;
CALayer *patchLayer;
if (cellPosition == CellGroupPositionAtTop)
{
patchLayer = [CALayer layer];
patchLayer.frame = CGRectMake(0, 10, 302, 35);
patchLayer.backgroundColor = YOUR_BACKGROUND_COLOR;
[bgColorView.layer addSublayer:patchLayer];
}
else if (cellPosition == CellGroupPositionAtBottom)
{
patchLayer = [CALayer layer];
patchLayer.frame = CGRectMake(0, 0, 302, 35);
patchLayer.backgroundColor = YOUR_BACKGROUND_COLOR;
[bgColorView.layer addSublayer:patchLayer];
}
}
}
Swift 5 - Xcode版本12.1 (12A7403)
| |第一步 将以下内容添加到AppDelegate.swift文件中
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {
let colorView = UIView()
colorView.backgroundColor = UIColor.lightGray
UITableViewCell.appearance().selectedBackgroundView = colorView
return true
}
|第二步| 确保在属性检查器中,单元格的内容视图背景设置为“清除颜色”(而不是“默认”)。这样做是为了不与App Delegate设置冲突。
对于Swift 3.0:
override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
let cell = super.tableView(tableView, cellForRowAt: indexPath)
cell.contentView.backgroundColor = UIColor.red
}
I've got a slightly different approach than everyone else that reflects the selection on touch rather than after being selected. I have a subclassed UITableViewCell. All you have to do is set the background color in the touch events, which simulates selection on touch, and then set the background color in the setSelected function. Setting the background color in the selSelected function allows for deselecting the cell. Make sure to pass the touch event to the super, otherwise the cell won't actually act as if its selected.
override func touchesBegan(touches: NSSet, withEvent event: UIEvent) {
self.backgroundColor = UIColor(white: 0.0, alpha: 0.1)
super.touchesBegan(touches, withEvent: event)
}
override func touchesCancelled(touches: NSSet!, withEvent event: UIEvent!) {
self.backgroundColor = UIColor.clearColor()
super.touchesCancelled(touches, withEvent: event)
}
override func setSelected(selected: Bool, animated: Bool) {
super.setSelected(selected, animated: animated)
// Configure the view for the selected state
self.backgroundColor = selected ? UIColor(white: 0.0, alpha: 0.1) : UIColor.clearColor()
}
Swift 3.0扩展
extension UITableViewCell {
var selectionColor: UIColor {
set {
let view = UIView()
view.backgroundColor = newValue
self.selectedBackgroundView = view
}
get {
return self.selectedBackgroundView?.backgroundColor ?? UIColor.clear
}
}
}
细胞。selectionColor = uiccolor . formacar .blue