select top (@TakeCount) * --FETCH NEXT
from(
    Select  ROW_NUMBER() OVER (order by StartDate) AS rowid,*
    From YourTable
)A
where Rowid>@SkipCount --OFFSET

这里有人在sql 2011中讲述了这个功能，令人遗憾的是，他们选择了一个有点不同的关键字“OFFSET / FETCH”，但它不是标准的，然后ok。

特别是对于SQL-SERVER，您可以通过许多不同的方式实现这一点。对于给定的真实例子，我们取Customer表。

例1:使用"SET ROWCOUNT"

SET ROWCOUNT 10
SELECT CustomerID, CompanyName from Customers
ORDER BY CompanyName

若要返回所有行，请将ROWCOUNT设置为0

SET ROWCOUNT 0  
SELECT CustomerID, CompanyName from Customers
    ORDER BY CompanyName

例2:使用"ROW_NUMBER and OVER"

With Cust AS
( SELECT CustomerID, CompanyName,
ROW_NUMBER() OVER (order by CompanyName) as RowNumber 
FROM Customers )
select *
from Cust
Where RowNumber Between 0 and 10

例3:使用“OFFSET and FETCH”，但是使用这个“ORDER BY”是强制的

SELECT CustomerID, CompanyName FROM Customers
ORDER BY CompanyName
OFFSET 0 ROWS
FETCH NEXT 10 ROWS ONLY

希望这对你有所帮助。

您可以在公共表表达式中使用ROW_NUMBER来实现这一点。

;WITH My_CTE AS
(
     SELECT
          col1,
          col2,
          ROW_NUMBER() OVER(ORDER BY col1) AS row_number
     FROM
          My_Table
     WHERE
          <<<whatever>>>
)
SELECT
     col1,
     col2
FROM
     My_CTE
WHERE
     row_number BETWEEN @start_row AND @end_row

另一个例子:

declare @limit int 
declare @offset int 
set @offset = 2;
set @limit = 20;
declare @count int
declare @idxini int 
declare @idxfim int 
select @idxfim = @offset * @limit
select @idxini = @idxfim - (@limit-1);
WITH paging AS
    (
        SELECT 
             ROW_NUMBER() OVER (order by object_id) AS rowid, *
        FROM 
            sys.objects 
    )
select *
    from 
        (select COUNT(1) as rowqtd from paging) qtd, 
            paging 
    where 
        rowid between @idxini and @idxfim
    order by 
        rowid;

详细阐述Somnath-Muluk的回答:

SELECT *
FROM table_name_here
ORDER BY (SELECT NULL AS NOORDER)
OFFSET 9 ROWS 
FETCH NEXT 25 ROWS ONLY 

W /o添加任何额外的列。 在SQL Server 2019中测试，但我猜也可以在旧的版本中工作。