我开始使用Python编写各种项目的代码(包括Django web开发和Panda3D游戏开发)。

为了帮助我理解发生了什么,我想基本上“看看”Python对象内部,看看它们是如何运行的——比如它们的方法和属性。

假设我有一个Python对象,我需要什么来打印它的内容?这可能吗?


当前回答

如果您想查看参数和方法,就像其他人指出的那样,可以使用pprint或dir()

如果您想查看内容的实际值,可以这样做

object.__dict__

其他回答

如果你有兴趣查看对象myobj对应的函数的源代码,你可以输入iPython或Jupyter Notebook:

myobj ? ?

If you want to look inside a live object, then python's inspect module is a good answer. In general, it works for getting the source code of functions that are defined in a source file somewhere on disk. If you want to get the source of live functions and lambdas that were defined in the interpreter, you can use dill.source.getsource from dill. It also can get the code for from bound or unbound class methods and functions defined in curries... however, you might not be able to compile that code without the enclosing object's code.

>>> from dill.source import getsource
>>> 
>>> def add(x,y):
...   return x+y
... 
>>> squared = lambda x:x**2
>>> 
>>> print getsource(add)
def add(x,y):
  return x+y

>>> print getsource(squared)
squared = lambda x:x**2

>>> 
>>> class Foo(object):
...   def bar(self, x):
...     return x*x+x
... 
>>> f = Foo()
>>> 
>>> print getsource(f.bar)
def bar(self, x):
    return x*x+x

>>> 

已经有很多好的提示了,但还没有提到最短和最简单的(不一定是最好的):

object?
"""Visit http://diveintopython.net/"""

__author__ = "Mark Pilgrim (mark@diveintopython.org)"


def info(object, spacing=10, collapse=1):
    """Print methods and doc strings.

    Takes module, class, list, dictionary, or string."""
    methodList = [e for e in dir(object) if callable(getattr(object, e))]
    processFunc = collapse and (lambda s: " ".join(s.split())) or (lambda s: s)
    print "\n".join(["%s %s" %
                     (method.ljust(spacing),
                      processFunc(str(getattr(object, method).__doc__)))
                     for method in methodList])

if __name__ == "__main__":
    print help.__doc__

如果你对此感兴趣,可以看看objbrowser。它使用Python标准库中的inspect模块进行下面的对象内省。