我想知道是否有一种方法来处理用户在输入EditText时按下Enter,就像onSubmit HTML事件。
还想知道是否有一种方法来操纵虚拟键盘,以这样的方式,“完成”按钮被标记为其他的东西(例如“Go”),并在单击时执行特定的动作(再次,像onSubmit)。
我想知道是否有一种方法来处理用户在输入EditText时按下Enter,就像onSubmit HTML事件。
还想知道是否有一种方法来操纵虚拟键盘,以这样的方式,“完成”按钮被标记为其他的东西(例如“Go”),并在单击时执行特定的动作(再次,像onSubmit)。
当前回答
A dependable way to respond to an <enter> in an EditText is with a TextWatcher, a LocalBroadcastManager, and a BroadcastReceiver. You need to add the v4 support library to use the LocalBroadcastManager. I use the tutorial at vogella.com: 7.3 "Local broadcast events with LocalBroadcastManager" because of its complete concise code Example. In onTextChanged before is the index of the end of the change before the change>;minus start. When in the TextWatcher the UI thread is busy updating editText's editable, so we send an Intent to wake up the BroadcastReceiver when the UI thread is done updating editText.
import android.content.Context;
import android.content.Intent;
import android.content.IntentFilter;
import android.text.Editable;
//in onCreate:
editText.addTextChangedListener(new TextWatcher() {
public void onTextChanged
(CharSequence s, int start, int before, int count) {
//check if exactly one char was added and it was an <enter>
if (before==0 && count==1 && s.charAt(start)=='\n') {
Intent intent=new Intent("enter")
Integer startInteger=new Integer(start);
intent.putExtra("Start", startInteger.toString()); // Add data
mySendBroadcast(intent);
//in the BroadcastReceiver's onReceive:
int start=Integer.parseInt(intent.getStringExtra("Start"));
editText.getText().replace(start, start+1,""); //remove the <enter>
//respond to the <enter> here
其他回答
我知道这已经有一年了,但我刚刚发现这非常适合EditText。
EditText textin = (EditText) findViewById(R.id.editText1);
textin.setInputType(InputType.TYPE_CLASS_TEXT);
除了文本和空格,它可以阻止任何东西。我不能制表,“返回”(“\n”),或任何东西。
完美的工作
public class MainActivity extends AppCompatActivity {
TextView t;
Button b;
EditText e;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
b = (Button) findViewById(R.id.b);
e = (EditText) findViewById(R.id.e);
e.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start, int before, int count) {
if (before == 0 && count == 1 && s.charAt(start) == '\n') {
b.performClick();
e.getText().replace(start, start + 1, ""); //remove the <enter>
}
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after) {}
@Override
public void afterTextChanged(Editable s) {}
});
b.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
b.setText("ok");
}
});
}
}
完美的工作
下面是一个简单的静态函数,您可以将它扔到Utils或keyboard类中,当用户敲击硬件或软件键盘上的返回键时,它将执行代码。这是@earlcasper精彩回答的修改版
/**
* Return a TextView.OnEditorActionListener that will execute code when an enter is pressed on
* the keyboard.<br>
* <code>
* myTextView.setOnEditorActionListener(Keyboards.onEnterEditorActionListener(new Runnable()->{
* Toast.makeText(context,"Enter Pressed",Toast.LENGTH_SHORT).show();
* }));
* </code>
* @param doOnEnter A Runnable for what to do when the user hits enter
* @return the TextView.OnEditorActionListener
*/
public static TextView.OnEditorActionListener onEnterEditorActionListener(final Runnable doOnEnter){
return (__, actionId, event) -> {
if (event==null) {
if (actionId == EditorInfo.IME_ACTION_DONE) {
// Capture soft enters in a singleLine EditText that is the last EditText.
doOnEnter.run();
return true;
} else if (actionId==EditorInfo.IME_ACTION_NEXT) {
// Capture soft enters in other singleLine EditTexts
doOnEnter.run();
return true;
} else {
return false; // Let system handle all other null KeyEvents
}
} else if (actionId==EditorInfo.IME_NULL) {
// Capture most soft enters in multi-line EditTexts and all hard enters.
// They supply a zero actionId and a valid KeyEvent rather than
// a non-zero actionId and a null event like the previous cases.
if (event.getAction()==KeyEvent.ACTION_DOWN) {
// We capture the event when key is first pressed.
return true;
} else {
doOnEnter.run();
return true; // We consume the event when the key is released.
}
} else {
// We let the system handle it when the listener
// is triggered by something that wasn't an enter.
return false;
}
};
}
这个问题还没有被Butterknife回答
布局的XML
<android.support.design.widget.TextInputLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:hint="@string/some_input_hint">
<android.support.design.widget.TextInputEditText
android:id="@+id/textinput"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:imeOptions="actionSend"
android:inputType="text|textCapSentences|textAutoComplete|textAutoCorrect"/>
</android.support.design.widget.TextInputLayout>
JAVA应用程序
@OnEditorAction(R.id.textinput)
boolean onEditorAction(int actionId, KeyEvent key){
boolean handled = false;
if (actionId == EditorInfo.IME_ACTION_SEND || (key.getKeyCode() == KeyEvent.KEYCODE_ENTER)) {
//do whatever you want
handled = true;
}
return handled;
}
editText.setOnEditorActionListener(new TextView.OnEditorActionListener() {
@Override
public boolean onEditorAction(TextView v, int actionId, KeyEvent event) {
if (actionId != 0 || event.getAction() == KeyEvent.ACTION_DOWN) {
// Action
return true;
} else {
return false;
}
}
});
Xml
<EditText
android:id="@+id/editText2"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:hint="@string/password"
android:imeOptions="actionGo|flagNoFullscreen"
android:inputType="textPassword"
android:maxLines="1" />