我主要是c#开发人员,但我目前正在用Python开发一个项目。
我如何在Python中表示等价的Enum ?
我主要是c#开发人员,但我目前正在用Python开发一个项目。
我如何在Python中表示等价的Enum ?
当前回答
我使用元类来实现枚举(在我的想法中,它是一个const)。代码如下:
class ConstMeta(type):
'''
Metaclass for some class that store constants
'''
def __init__(cls, name, bases, dct):
'''
init class instance
'''
def static_attrs():
'''
@rtype: (static_attrs, static_val_set)
@return: Static attributes in dict format and static value set
'''
import types
attrs = {}
val_set = set()
#Maybe more
filter_names = set(['__doc__', '__init__', '__metaclass__', '__module__', '__main__'])
for key, value in dct.iteritems():
if type(value) != types.FunctionType and key not in filter_names:
if len(value) != 2:
raise NotImplementedError('not support for values that is not 2 elements!')
#Check value[0] duplication.
if value[0] not in val_set:
val_set.add(value[0])
else:
raise KeyError("%s 's key: %s is duplicated!" % (dict([(key, value)]), value[0]))
attrs[key] = value
return attrs, val_set
attrs, val_set = static_attrs()
#Set STATIC_ATTRS to class instance so that can reuse
setattr(cls, 'STATIC_ATTRS', attrs)
setattr(cls, 'static_val_set', val_set)
super(ConstMeta, cls).__init__(name, bases, dct)
def __getattribute__(cls, name):
'''
Rewrite the special function so as to get correct attribute value
'''
static_attrs = object.__getattribute__(cls, 'STATIC_ATTRS')
if name in static_attrs:
return static_attrs[name][0]
return object.__getattribute__(cls, name)
def static_values(cls):
'''
Put values in static attribute into a list, use the function to validate value.
@return: Set of values
'''
return cls.static_val_set
def __getitem__(cls, key):
'''
Rewrite to make syntax SomeConstClass[key] works, and return desc string of related static value.
@return: Desc string of related static value
'''
for k, v in cls.STATIC_ATTRS.iteritems():
if v[0] == key:
return v[1]
raise KeyError('Key: %s does not exists in %s !' % (str(key), repr(cls)))
class Const(object):
'''
Base class for constant class.
@usage:
Definition: (must inherit from Const class!
>>> class SomeConst(Const):
>>> STATUS_NAME_1 = (1, 'desc for the status1')
>>> STATUS_NAME_2 = (2, 'desc for the status2')
Invoke(base upper SomeConst class):
1) SomeConst.STATUS_NAME_1 returns 1
2) SomeConst[1] returns 'desc for the status1'
3) SomeConst.STATIC_ATTRS returns {'STATUS_NAME_1': (1, 'desc for the status1'), 'STATUS_NAME_2': (2, 'desc for the status2')}
4) SomeConst.static_values() returns set([1, 2])
Attention:
SomeCosnt's value 1, 2 can not be duplicated!
If WrongConst is like this, it will raise KeyError:
class WrongConst(Const):
STATUS_NAME_1 = (1, 'desc for the status1')
STATUS_NAME_2 = (1, 'desc for the status2')
'''
__metaclass__ = ConstMeta
##################################################################
#Const Base Class ends
##################################################################
def main():
class STATUS(Const):
ERROR = (-3, '??')
OK = (0, '??')
print STATUS.ERROR
print STATUS.static_values()
print STATUS.STATIC_ATTRS
#Usage sample:
user_input = 1
#Validate input:
print user_input in STATUS.static_values()
#Template render like:
print '<select>'
for key, value in STATUS.STATIC_ATTRS.items():
print '<option value="%s">%s</option>' % (value[0], value[1])
print '</select>'
if __name__ == '__main__':
main()
其他回答
Alec Thomas简洁回答的一个变体(支持获取枚举值的名称):
class EnumBase(type):
def __init__(self, name, base, fields):
super(EnumBase, self).__init__(name, base, fields)
self.__mapping = dict((v, k) for k, v in fields.iteritems())
def __getitem__(self, val):
return self.__mapping[val]
def enum(*seq, **named):
enums = dict(zip(seq, range(len(seq))), **named)
return EnumBase('Enum', (), enums)
Numbers = enum(ONE=1, TWO=2, THREE='three')
print Numbers.TWO
print Numbers[Numbers.ONE]
print Numbers[2]
print Numbers['three']
Python的标准是PEP 435,所以在Python 3.4+中可以使用Enum类:
>>> from enum import Enum
>>> class Colors(Enum):
... red = 1
... green = 2
... blue = 3
>>> for color in Colors: print color
Colors.red
Colors.green
Colors.blue
为什么枚举必须是整数?不幸的是,在不改变Python语言的情况下,我想不出任何好看的构造来生成它,所以我将使用字符串:
class Enumerator(object):
def __init__(self, name):
self.name = name
def __eq__(self, other):
if self.name == other:
return True
return self is other
def __ne__(self, other):
if self.name != other:
return False
return self is other
def __repr__(self):
return 'Enumerator({0})'.format(self.name)
def __str__(self):
return self.name
class Enum(object):
def __init__(self, *enumerators):
for e in enumerators:
setattr(self, e, Enumerator(e))
def __getitem__(self, key):
return getattr(self, key)
也许现在更好的是,为了配置文件或其他远程输入,我们可以自然地对字符串进行测试。
例子:
class Cow(object):
State = Enum(
'standing',
'walking',
'eating',
'mooing',
'sleeping',
'dead',
'dying'
)
state = State.standing
In [1]: from enum import Enum
In [2]: c = Cow()
In [3]: c2 = Cow()
In [4]: c.state, c2.state
Out[4]: (Enumerator(standing), Enumerator(standing))
In [5]: c.state == c2.state
Out[5]: True
In [6]: c.State.mooing
Out[6]: Enumerator(mooing)
In [7]: c.State['mooing']
Out[7]: Enumerator(mooing)
In [8]: c.state = Cow.State.dead
In [9]: c.state == c2.state
Out[9]: False
In [10]: c.state == Cow.State.dead
Out[10]: True
In [11]: c.state == 'dead'
Out[11]: True
In [12]: c.state == Cow.State['dead']
Out[11]: True
使用下面的方法。
TYPE = {'EAN13': u'EAN-13',
'CODE39': u'Code 39',
'CODE128': u'Code 128',
'i25': u'Interleaved 2 of 5',}
>>> TYPE.items()
[('EAN13', u'EAN-13'), ('i25', u'Interleaved 2 of 5'), ('CODE39', u'Code 39'), ('CODE128', u'Code 128')]
>>> TYPE.keys()
['EAN13', 'i25', 'CODE39', 'CODE128']
>>> TYPE.values()
[u'EAN-13', u'Interleaved 2 of 5', u'Code 39', u'Code 128']
我用它来选择Django模型,它看起来非常python化。它不是一个真正的Enum,但它完成了这项工作。
枚举已按照PEP 435中的描述添加到Python 3.4。它还被反向移植到pypi上的3.3、3.2、3.1、2.7、2.6、2.5和2.4。
对于更高级的Enum技术,请尝试aenum库(2.7,3.3+,与enum34是同一作者)。py2和py3之间的代码并不完全兼容,例如,你需要在python 2中使用__order__)。
要使用enum34,执行$ pip install enum34 要使用aenum,执行$ pip install aenum
安装enum(没有编号)将安装一个完全不同且不兼容的版本。
from enum import Enum # for enum34, or the stdlib version
# from aenum import Enum # for the aenum version
Animal = Enum('Animal', 'ant bee cat dog')
Animal.ant # returns <Animal.ant: 1>
Animal['ant'] # returns <Animal.ant: 1> (string lookup)
Animal.ant.name # returns 'ant' (inverse lookup)
或者说:
class Animal(Enum):
ant = 1
bee = 2
cat = 3
dog = 4
在早期版本中,完成枚举的一种方法是:
def enum(**enums):
return type('Enum', (), enums)
是这样使用的:
>>> Numbers = enum(ONE=1, TWO=2, THREE='three')
>>> Numbers.ONE
1
>>> Numbers.TWO
2
>>> Numbers.THREE
'three'
你也可以很容易地支持自动枚举,就像这样:
def enum(*sequential, **named):
enums = dict(zip(sequential, range(len(sequential))), **named)
return type('Enum', (), enums)
并像这样使用:
>>> Numbers = enum('ZERO', 'ONE', 'TWO')
>>> Numbers.ZERO
0
>>> Numbers.ONE
1
支持将值转换回名称可以这样添加:
def enum(*sequential, **named):
enums = dict(zip(sequential, range(len(sequential))), **named)
reverse = dict((value, key) for key, value in enums.iteritems())
enums['reverse_mapping'] = reverse
return type('Enum', (), enums)
这将覆盖带有该名称的任何内容,但对于在输出中呈现枚举非常有用。如果反向映射不存在,它将抛出一个KeyError。第一个例子:
>>> Numbers.reverse_mapping['three']
'THREE'
如果你使用MyPy,另一种表达“枚举”的方式是typing.Literal。
例如:
from typing import Literal #python >=3.8
from typing_extensions import Literal #python 2.7, 3.4-3.7
Animal = Literal['ant', 'bee', 'cat', 'dog']
def hello_animal(animal: Animal):
print(f"hello {animal}")
hello_animal('rock') # error
hello_animal('bee') # passes