在Java中,我有一个名为“text”的字符串变量中的文本字段中的文本。

如何将“文本”变量的内容保存到文件中?


当前回答

我已经发布了一个库,它保存文件,并且只使用一行代码处理所有内容,您可以在这里找到它及其文档

Github存储库

你的问题答案很简单

String path = FileSaver
        .get()
        .save(string.getBytes(),"file.txt");

其他回答

我倾向于尽可能依赖于库来进行这种操作。这使我不太可能意外地忽略一个重要的步骤(如上面狼鹬犯的错误)。上面建议了一些库,但我最喜欢的是GoogleGuava。Guava有一个名为Files的类,非常适合此任务:

// This is where the file goes.
File destination = new File("file.txt");
// This line isn't needed, but is really useful 
// if you're a beginner and don't know where your file is going to end up.
System.out.println(destination.getAbsolutePath());
try {
    Files.write(text, destination, Charset.forName("UTF-8"));
} catch (IOException e) {
    // Useful error handling here
}
private static void generateFile(String stringToWrite, String outputFile) {
    try {       
        FileWriter writer = new FileWriter(outputFile);
        writer.append(stringToWrite);
        writer.flush();
        writer.close();
        log.debug("New File is generated ==>"+outputFile);
    } catch (Exception exp) {
        log.error("Exception in generateFile ", exp);
    }
}

使用这个,它非常易读:

import java.nio.file.Files;
import java.nio.file.Paths;

Files.write(Paths.get(path), lines.getBytes(), StandardOpenOption.WRITE);

如果您需要基于一个字符串创建文本文件:

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;

public class StringWriteSample {
    public static void main(String[] args) {
        String text = "This is text to be saved in file";

        try {
            Files.write(Paths.get("my-file.txt"), text.getBytes());
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

最好在finally块中关闭writer/outputstream,以防发生意外

finally{
   if(writer != null){
     try{
        writer.flush();
        writer.close();
     }
     catch(IOException ioe){
         ioe.printStackTrace();
     }
   }
}