如何从Node.js中的HTTP post方法中提取表单数据(form[method="post"])和文件上传?

我看了文件,谷歌了一下,什么都没找到。

function (request, response) {
    //request.post????
}

有图书馆或黑客吗?


当前回答

参考:https://nodejs.org/en/docs/guides/anatomy-of-an-http-transaction/

let body = [];
request.on('data', (chunk) => {
  body.push(chunk);
}).on('end', () => {
  body = Buffer.concat(body).toString();
  // at this point, `body` has the entire request body stored in it as a string
});

其他回答

要详细说明使用URLSearchParams:

Node.js知识:如何读取POST数据? 类:URLSearchParams .js文档 MDN: URLSearchParams

const http = require('http');

const POST_HTML =
  '<html><head><title>Post Example</title></head>' +
  '<body>' +
  '<form method="post">' +
  'Input 1: <input name="input1"><br>' +
  'Input 2: <input name="input2"><br>' +
  'Input 1: <input name="input1"><br>' +
  '<input type="submit">' +
  '</form>' +
  '</body></html>';

const FORM_DATA = 'application/x-www-form-urlencoded';

function processFormData(body) {
  const params = new URLSearchParams(body);

  for ([name, value] of params.entries()) console.log(`${name}: ${value}`);
}

// req: http.IncomingMessage
// res: http.ServerResponse
//
function requestListener(req, res) {
  const contentType = req.headers['content-type'];
  let body = '';

  const append = (chunk) => {
    body += chunk;
  };
  const complete = () => {
    if (contentType === FORM_DATA) processFormData(body);

    res.writeHead(200);
    res.end(POST_HTML);
  };

  req.on('data', append);
  req.on('end', complete);
}

http.createServer(requestListener).listen(8080);
$ node index.js
input1: one
input2: two
input1: three

你可以使用querystring模块:

var qs = require('querystring');

function (request, response) {
    if (request.method == 'POST') {
        var body = '';

        request.on('data', function (data) {
            body += data;

            // Too much POST data, kill the connection!
            // 1e6 === 1 * Math.pow(10, 6) === 1 * 1000000 ~~~ 1MB
            if (body.length > 1e6)
                request.connection.destroy();
        });

        request.on('end', function () {
            var post = qs.parse(body);
            // use post['blah'], etc.
        });
    }
}

现在,例如,如果你有一个名为age的输入字段,你可以使用变量post访问它:

console.log(post.age);

如果你将数据编码为JSON,然后将其发送到Node.js,会更简洁。

function (req, res) {
    if (req.method == 'POST') {
        var jsonString = '';

        req.on('data', function (data) {
            jsonString += data;
        });

        req.on('end', function () {
            console.log(JSON.parse(jsonString));
        });
    }
}

有很多种方法。然而,我所知道的最快的方法是使用带有body-parser的Express.js库。

var express = require("express");
var bodyParser = require("body-parser");
var app = express();

app.use(bodyParser.urlencoded({extended : true}));

app.post("/pathpostdataissentto", function(request, response) {
  console.log(request.body);
  //Or
  console.log(request.body.fieldName);
});

app.listen(8080);

这可以用于字符串,但我要更改bodyParser。urlencoded to bodyParser。如果POST数据包含json数组,则改为json。

更多信息:http://www.kompulsa.com/how-to-accept-and-parse-post-requests-in-node-js/

不使用express也可以提取post参数。

1: NMP安装多方

2:导入多方。As var multiparty = require('multiparty');

3: `

if(req.method ==='POST'){
   var form = new multiparty.Form();
   form.parse(req, function(err, fields, files) {
      console.log(fields['userfile1'][0]);
    });
    }

4:和HTML形式是。

<form method=POST enctype=multipart/form-data>
<input type=text name=userfile1><br>
<input type=submit>
</form>

我希望这对你有用。谢谢。